Bihar Board 12th Biology Objective Answers Chapter 4 Reproductive Health

Bihar Board 12th Biology Objective Questions and Answers

Bihar Board 12th Biology Objective Answers Chapter 4 Reproductive Health

Question 1.
RCH stands for
(a) routine check-up of health
(b) reproduction cum hygiene
(c) reversible contraceptive hazards
(d) reproductive and child health care.
Answer:
(d) reproductive and child health care.

Question 2.
Amminocentesis is a technique used to
(a) determine errors in amino acid metabolism in embryo
(b) pin point specific cardiac ailments in embryo
(c) determine any hereditary genetic abnormality in embryo
(d) all of these.
Answer:
(a) determine errors in amino acid metabolism in embryo

Question 3.
Which of the following cannot be detected in a developing foetus by amniocentesis ?
(a) Jaundice
(b) Down’s syndrome
(c) Cystic fibrosis
(d) Colourblindness
Answer:
(a) Jaundice

Bihar Board 12th Biology Objective Answers Chapter 4 Reproductive Health

Question 4.
In which of the following weeks of pregnancy CVS is done ?
(a) 12th – 14th week
(b) 8th – 10th week
(c) 5th – 7th week
(d) None of these
Answer:
(b) 8th – 10th week

Question 5.
Causes for increased population growth in india is/are
(a) increase in birth rate
(b) decrease in death rate
(c) lack of education
(d) all of these.
Answer:
(d) all of these.

Question 6.
Which of the following pairs contributes to an increase in population ?
(a) Natality and immigration
(b) Mortality and emigration
(c) Natality and emigration
(d) Mortality and immigration
Answer:
(a) Natality and immigration

Question 7.
Which of the following is correct regarding the consequences of lower population ?
(a) It increases the poverty of a country.
(b) It leads to shortage of food supply.
(c) It results in unemployment
(d) All of these
Answer:
(d) All of these

Question 8.
The best way to decrease population of a country is
(a) to educate people
(b) to have better houses
(c) to kill people on a large scale
(d) to practice and implement familay planning.
Answer:
(d) to practice and implement familay planning.

Question 9.
Which of the following correctly describes the measures
that can be used to control over-population ?
(a) Educating people about the advantages of a small family
(b) Raising the age of marriage
(c) Encouraging family planning programme
(d) All of these
Answer:
(d) All of these

Bihar Board 12th Biology Objective Answers Chapter 4 Reproductive Health

Question 10.
Which of the following is not a characteristic of an ideal contraceptive ?
(a) User-friendly
(b) Irreversible
(c) Easily available
(d) Least side-effects
Answer:
(b) Irreversible

Question 11.
On which of the following facts does the method of periodic abstinence is based ?
(a) Ovulation occurs on about the 14th day of menstruation.
(b) Ovum remains alive for about 1-2 days.
(c) Sperms survive for about 3 days.
(d) All of these
Answer:
(d) All of these

Question 12.
Which of the following is a non-medicated intrauterine device (IUD) ?
(a) CuT
(b) Lippes Loop
(c) Cu7
(d) LNG-20
Answer:
(b) Lippes Loop

Question 13.
Multiload device contains
(a) manganese
(b) iron
(c) copper
(d) calcium
Answer:
(c) copper

Bihar Board 12th Biology Objective Answers Chapter 4 Reproductive Health

Question 14.
Which of the following is not an intrauterine device ?
(a) Progestasert
(b) Multiload-375
(c) Norplant
(d) Lippes loop
Answer:
(c) Norplant

Question 15.
What is the work of copper-T ?
(a) To inhibit ovulation
(b) To inhibit fertilisation
(c) To inhibit implantation of blastocyst
(d) To inhibit gametogenesis
Answer:
(b) To inhibit fertilisation

Question 16.
IUDs prevent pregnancy by
(a) inhibiting physiological and morphological uterine changes required for implantation.
(b) increasing phagocytosis of spermatozoa within uterus
(c) suppressing motility of sperms as well as their fertilising capacity
(d) all of these.
Answer:
(d) all of these.

Question 17.
Cu ions released from copper releasing intrauterine devices (IUDs)
(a) prevent ovulation
(b) make uterus unsuitable for implantation
(c) decrease phagocytosis of sperms
(d) suppress sperm motility.
Answer:
(d) suppress sperm motility.

Question 18.
The birth control device used by women is
(a) diaphragm
(b) vault
(c) copper T
(d) all of these.
Answer:
(d) all of these.

Bihar Board 12th Biology Objective Answers Chapter 4 Reproductive Health

Question 19.
The most important component of oral contraceptive pills is
(a) progesterone-estrogen
(b) growth hormore
(c) thyroxine
(d) luteinising hormone.
Answer:
(a) progesterone-estrogen

Question 20.
Progesterone pill helps in preventing pregnancy by not allowing
(a) ova formation
(b) fertilisation
(c) implantation
(d) none of these.
Answer:
(a) ova formation

Question 21.
What is true about “Saheli” ?
(i) Developed at the CDRI, Lucknow
(ii) Contains a steroidal preparation
(iii) “Once-a-weak” pill
(iv) Many side effects
(v) High contraceptive value
(vi) Very few side effects value
(vii) Low contraceptive value
(a) (i), (ii), (iii), (v), (vi)
(b) (i), (iii), (v), (vi), (vii)
(c) (i), (ii), (iii), (iv), (v)
(d) (i), (iii), (iv), (v)
Answer:
(d) (i), (iii), (iv), (v)

Question 22.
What is the figure given below showing in particular ?
Bihar Board 12th Biology Objective Answers Chapter 4 Reproductive Health
(a) Ovarian cancer
(b) Uterine cancer
(c) Tubectomy
(d) Vasectomy
Answer:
(c) Tubectomy

Bihar Board 12th Biology Objective Answers Chapter 4 Reproductive Health

Question 23.
Which of the following birth control measures can be considered as the safest ?
(a) The rhythm method
(b) The use of physical barriers
(c) Termination of unwanted pregnancy
(d) Sterilisation techniques
Answer:
(d) Sterilisation techniques

Question 24.
Which of the following is the most widely accepted method of contraception in India at present ?
(a) Cervical caps
(b) Tubectomy
(c) Diaphragms
(d) IUDs (Intra uterine devices)
Answer:
(d) IUDs (Intra uterine devices)

Question 25.
Which of the following is a full proof method contraception ?
(a) Implantation
(b) Lactational amenorrhea
(c) Condoms
(d) Sterilisation
Answer:
(d) Sterilisation

Question 26.
Which of the following statements is correct regarding vasectomy ?
(a) It prevents the production of sperm in the testes.
(b) It prevents the production of semen.
(c) It prevents the movement of sperm into the urethra.
(d) It prevents a man from having an erection.
Answer:
(c) It prevents the movement of sperm into the urethra.

Question 27.
Which of the following statements is incorrect regarding the medical termination of pregnancy (MTP) ?
(a) These help in getting rid of unwanted pregnancies.
(b) These help in aborting the pregnancies which may be harmful to either mother of foetus or both.
(c) These contribute in decreasing the human population.
(d) None of these.
Answer:
(d) None of these.

Bihar Board 12th Biology Objective Answers Chapter 4 Reproductive Health

Question 28.
Which of the following represents the correct match of a sexually transmitted disease with its pathogen ?
(a) Syphilis-Treponema pallidum
(b) Gonorrhoea-Entamoeba histolytica
(c) Urethritis-Bacillus anthracis
(d) Softsore-Bacillus brevis
Answer:
(a) Syphilis-Treponema pallidum

Question 29.
The sexually transmitted disease, that can affect both the male and the female genitals and may damage the eyes of babies born of infected mothers is
(a) AIDS
(b) syphilis
(c) gonorrhoea
(d) hepatitis
Answer:
(c) gonorrhoea

Question 30.
A sexually transmitted disease symptomised by the development of chancre on the genitals is caused by the infection of
(a) Treponema pallidum
(b) Neisseria gonorrhoeae
(c) human immunodeficiency virus
(d) hepatitis B virus
Answer:
(a) Treponema pallidum

Question 31.
Which of the following is correct regarding HIV, hepatitis B, gonorrhoea, trichomoniasis ?
(a) Trichomoniasis is an STD whereas others are not.
(b) Gonorrhoea is a viral disease whereas others are bacterial.
(c) HIV is a pathogen whereas others are diseases.
(d) Hepatitis B is eradicated completely whereas others are not.
Answer:
(c) HIV is a pathogen whereas others are diseases.

Question 32.
Which one of the following groups includes sexually transmitted diseases caused by bacteria only ?
(a) Syphilis, gonorrhoea, chancroid
(b) Syphilis, chlamydiasis, chancroid
(c) Syphilis, gonorrhoea, scabies
(d) Syphilis, scabies, pediculosis
Answer:
(a) Syphilis, gonorrhoea, chancroid

Bihar Board 12th Biology Objective Answers Chapter 4 Reproductive Health

Question 33.
Confirmatory test for STDs is
(a) ELISA
(b) PCR
(c) DNA hybridisation
(d) all of these.
Answer:
(d) all of these.

Question 34.
Hepatitis B is transmitted through
(a) blood transfusion
(b) intimate physical contact
(c) sexual contact
(d) all of these
Answer:
(d) all of these

Question 35.
The common means of transmission of AIDS is
(a) sexual intercourse
(b) blood transfusion
(c) placental transfer
(d) all of these.
Answer:
(d) all of these.

Question 36.
Which of the following STDs are not completely curable ?
(a) Chlamydiasis, gonorrhoea, trichomoniasis
(b) Chancroid syphilis, genital warts
(c) AIDS, syphilis, hepatitis B
(d) AIDS, genital herpes, hepatitis B
Answer:
(d) AIDS, genital herpes, hepatitis B

Bihar Board 12th Biology Objective Answers Chapter 4 Reproductive Health

Question 37.
World AIDS day is
(a) December 21
(b) December 1
(c) November 1
(d) June 11
Answer:
(b) December 1

Question 38.
In vitro fertilisation is a technique that involves transfer of which one of the following into the fallopian tube ?
(a) Embryo only, upto 8 cell stage
(b) Either zygote or early embryo upto 8 cell stage
(c) Embro of 32 cell stage
(d) Zygote only
Answer:
(b) Either zygote or early embryo upto 8 cell stage

Question 39.
The test-tube baby programme employs which one of the following techniques ?
(a) Zygote intra Fallopian transfer (ZIFT)
(b) Intra uterine insemination (IUI)
(c) Gamete intra Fallopian transfer
(d) All of these
Answer:
(a) Zygote intra Fallopian transfer (ZIFT)

Question 40.
The first case of IVF-ET technique success, was reported by
(a) Louis joy Brown and Banting Best
(b) Patrick Steptoe and Rebert Edwards
(c) Robert Steptoe and Gilbert Brown
(d) Baylis and Starling Taylor.
Answer:
(b) Patrick Steptoe and Rebert Edwards

Question 41.
Which of the following is ART ?
(a) IUDs
(b) GIFT
(c) ZIFT
(d) Both (b) & (c)
Answer:
(d) Both (b) & (c)

Bihar Board 12th Biology Objective Answers Chapter 4 Reproductive Health

Question 42.
The technique called Gamete Intra Fallopian Transfer (GIFT) is recommended for those females
(a) who cannot produce an ovum
(b) who cannot retain the foetus inside uterus
(c) who cannot provide suitable environment for fertilisation
(d) all of these
Answer:
(a) who cannot produce an ovum

Question 43.
Which method can be used for women that cannot produce ovum but can provide suitable environment ?
(a) IUD
(b) GIFT
(c) IUI
(d) ICSI
Answer:
(b) GIFT

Question 44.
Which of these can be used to cure infertility in couples where male partner has very low sperm count ?
(a) IUD
(b) GIFT
(c) IUI
(d) None of these
Answer:
(c) IUI

Question 45.
The method of directly injecting a sperm into ovum in assisted reproductive technology is called
(a) GIFT
(b) ZIFT
(c) ICSI
(d) ET
Answer:
(c) ICSI

Question 46.
Increased IMR and decreased MMR in a population will
(a) cause rapid increase in growth rate
(b) result in decline in growth rate
(c) not cause significant change in growth rate
(d) result in an explosive population.
Answer:
(b) result in decline in growth rate

Bihar Board 12th Biology Objective Answers Chapter 4 Reproductive Health

Question 47.
Intensely lactating mothers do not generally conceive due to the
(a) suppression of gonadotropins
(b) hypersecretion of gonadotropins .
(c) suppression of gametic transport
(d) suppression of fertilisation.
Answer:
(a) suppression of gonadotropins

Question 48.
A national level approach to build up a reproductively healthy society was taken up in our country in
(a) 1950s
(b) 1960s
(c) 1980s
(d) 1990s
Answer:
(a) 1950s

Question 49.
Emergency contraceptives are effective if used within,
(a) 72 hrs of coitus
(b) 72 hrs of ovulation
(c) 72 hrs of menstruation
(d) 72 hrs of implantation.
Answer:
(a) 72 hrs of coitus

Question 50.
From the sexually transmitted diseases mentioned below, identify the one which does not specifically affect the sex organs.
(a) Syphilis
(b) AIDS
(c) Gonorrhea
(d) Genital warts
Answer:
(b) AIDS

Question 51.
Condoms are one of the most popular contraceptives because of the following reasons.
(a) These are effective barriers for insemination.
(b) They do not interfere with coital act.
(c) These help in reducing the risk of STDs.
(d) All of the above
Answer:
(d) All of the above

Question 52.
The correct surgical procedure as a contraceptive method is
(a) ovariectomy
(b) hysterectomy
(c) vasectomy
(d) castration.
Answer:
(c) vasectomy

Bihar Board 12th Biology Objective Answers Chapter 4 Reproductive Health

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Bihar Board 12th Biology Objective Questions and Answers

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 1.
Which of the following facrtors affect human health ?
(i) Infections
(ii) Silent mutation
(iii) Life style
(iv) Genetic disorders
(a) (i), (ii)and(iv)
(b) (i) and (ii)
(c) (i), (iii) and (iv)
(d) (i), (ii), (iii) and (iv)
Answer:
(c) (i), (iii) and (iv)

Question 2.
Which one of the following disease is non – communicable ?
(a) Diphtheria
(b) Flu
(c) Cancer
(d) Malaria
Answer:
(c) Cancer

Question 3.
Which of the following pairs contains an infectious and a non-infectious disease respectively ?
(a) Typhoid and AIDS
(b) AIDS and cancer
(c) Pneumonia and malaria
(d) Cancer and malaria
Answer:
(b) AIDS and cancer

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 4.
Typhoid fever in human beings is caused by
(a) Plasmodium vivax
(b) Trichophyton
(c) Salmonella typhi
(d) Rhinoviruses.
Answer:
(c) Salmonella typhi

Question 5.
Which of the following is the bacterial disease in humans ?
(a) Dysentery
(b) Malaria
(c) Plague
(d) Both (a) & (c)
Answer:
(d) Both (a) & (c)

Question 6.
Which of the following pathogens causes whooping coough ?
(a) Legionella spp.
(b) Bordetella pertussis
(c) Vibrio cholerae
(d) Burcella melitensis
Answer:
(b) Bordetella pertussis

Question 7.
Which one of the following sets includes bacterial diseases ?
(a) Tetanus, tuberculosis, measles
(b) Diptheria, leprosy, plague
(c) Cholera, typhoid, mumps
(d) Malaria, mumps, poliomyelits
Answer:
(b) Diptheria, leprosy, plague

Question 8.
The common cold is caused by
(a) Rhino viruses
(b) Streptococcus pnemoniae
(c) Salmonella typhimurium
(d) Plasmodium vivax.
Answer:
(a) Rhino viruses

Question 9.
Hepatitis B is transmitted through
(a) sneezing
(b) female Anopheles
(c) coughing
(d) blood transfusion.
Answer:
(b) female Anopheles

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 10.
A toxic substance, responsible for the chills and high fever recurring every three to four days in malarial fever, is
(a) interferon
(b) haemozoin
(c) hirudin
(d) colostrum
Answer:
(b) haemozoin

Question 11.
During the life cycle of Plasmodium, sexual reproduction takes place in which of the following hosts ?
(a) Human
(b) Female Anopheles mosquito
(c) Male Anopheles mosquito
(d) Both (a) and (b)
Answer:
(b) Female Anopheles mosquito

Question 12.
Amoebic dysentery (amoebiasis) is caused by
(a) Entamoeba histolytica
(b) E. coli
(c) Streptococcus pneumoniae
(d) Trichophyton.
Answer:
(a) Entamoeba histolytica

Question 13.
Which one of the following diseases cannot be cured by taking antibiotics ?
(a) Plague
(b) Amoebiasis
(c) Leprosy
(d) Whooping cough
Answer:
(b) Amoebiasis

Question 14.
An intestinal parasite which causes blockage of the intestinal passage and whose eggs are excreted along with the faeces of infected person is ______.
(a) Wuchereria bancrofti
(b) Ascaris
(c) Epidermophyton
(d) Microsporum
Answer:
(b) Ascaris

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 15.
Elephantiasis, a chronic inflammation that results in gross deformities is caused by
(a) Ascaris
(b) E.coli
(c) Wuchereria
(d) Trichophyton
Answer:
(c) Wuchereria

Question 16.
Which of the following is affected by the infection of Wuchereria bancrofti ?
(a) Lymphatic vessels
(b) Respiratory system
(c) Nervous system
(d) Blood circulation
Answer:
(a) Lymphatic vessels

Question 17.
Which of the following diseases is transmitted by the bite of the female mosquito vector ?
(a) Filariasis
(b) Amoebiasis
(c) Typhoid
(d) Pneumonia
Answer:
(a) Filariasis

Question 18.
Which of the following pairs correctly matches a disease and a pathogen causing it ?
(a) Typhoid – Salmonella typhi
(b) Pneumonia – Haemophilus pneumoniae
(c) Malaria – Ascaris lumbricoides
(d) Ringworm – Entamoeba histolytica
Answer:
(a) Typhoid – Salmonella typhi

Question 19.
The pathogen Microsporum responsible for ringworm disease in humans belongs to the same kingdom as that of
(a) Taenia, a tapeworm
(b) Ascaris, a roundworm
(c) Rhizopus, a mould
(d) Wuchereria, a filarial worm,
Answer:
(c) Rhizopus, a mould

Question 20.
Appearance of dry, scaly lesions with itching on various parts of the body are the symptoms of _______.
(a) elephantiasis
(b) ringworm
(c) ascariasis
(d) amoebiasis
Answer:
(b) ringworm

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 21.
Gambusia is a fish which is being introduced into the ponds in order to check the vector-borne diseases such as
(a) dengue
(b) malaria
(c) chikungunya
(d) all of these.
Answer:
(d) all of these.

Question 22.
Which one of the following pairs of diseases is viral as well as transmitted by mosquitoes ?
(a) Encephalitis and sleeping sickness
(b) Yellow fever and sleeping sickness
(c) Elephantiasis and dengue
(d) Yellow fever and dengue
Answer:
(d) Yellow fever and dengue

Question 23.
Which one of the following pairs is not correctly matched ?
(a) Dengue fever – Fiavi-ribo virus
(b) Syphilis – Trichu ris inch jura
(c) Plague – Yersinia pesris
(d) Filariasis – Wuchereria banchrofri
Answer:
(b) Syphilis – Trichu ris inch jura

Question 24.
The term ‘immunity’ refers to
(a) mutalism between host and parasite
(b) ability of the host to fight the disease-causing organism
(c) ability of the parasite to survive within a host
(d) a fatal disease.
Answer:
(b) ability of the host to fight the disease causing organism

Question 25.
A person has developed interferons in his body. He seems to carry an infection of
(a) tetanus
(b) malaria
(c) measles
(d) typhoid
Answer:
(c) measles

Question 26.
The first line of defence in the immune system is provided by
(a) skin and mucous membrane
(b) inflammatory response
(c) the complement system
(d) none of these.
Answer:
(a) skin and mucous membrane

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 27.
Primary response produced due to first time encounter with a pathogen is of
(a) high intensity
(b) low intenisty
(c) intermediate intensity
(d) no intensity.
Answer:
(b) low intenisty

Question 28.
Which of the following components does not participate in innate immunity ?
(a) Neutrophils
(b) Macrophages
(c) B-lymphocytes
(d) Natural killer cells
Answer:
(c) B-lymphocytes

Question 29.
Antibodies are secreted by
(a) T-lymphocytes
(b) B-lymphocytes
(c) both (a) and (b)
(d) natural killer cell.
Answer:
(b) B-lymphocytes

Question 30.
The antigen binding site of an antibody is present at
(a) the constant region
(b) the C-terminal
(c) the variable region
(d) between constant and variable region.
Answer:
(c) the variable region

Question 31.
Humoral immunity is associated with
(a) T-cells
(b) B-cells
(c) macrophages
(d) both (a) and (b)
Answer:
(b) B-cells

Question 32.
The antibody which can cross placental barrier is.
(a) IgA
(b) JgE
(c) IgM
(d) IgG.
Answer:
(d) IgG.

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 33.
The most abundant class of immunoglobulins (Igs) in the body is
(a) IgA
(b) IgG
(c) IgE
(d) IgM
Answer:
(b) IgG

Question 34.
A protein or polysaccharide molecule that stimulates antibody formation.
(a) antigen
(b) antibiotics
(c) exotoxin
(d) endotoxins.
Answer:
(a) antigen

Question 35.
Passive immunity can be conferred directly by
(a) vaccines
(b) antitoxins
(c) colostrum
(d) both (b) & (c)
Answer:
(d) both (b) & (c)

Question 36.
Which form of pathogen is used in vaccination ?
(a) Activated and strong pathogenic antigens
(b) Inactivated and weakened pathogenic antigens
(c) Hyperactive and strong pathogen
(d) Preformed antibodies
Answer:
(b) Inactivated and weakened pathogenic antigens

Question 37.
Injection of antitoxin in tetanus confers which type of immunisation ?
(a) Active immunisation
(b) Passive immunisation
(c) Auto-immunisation
(d) Humoral immunisation
Answer:
(b) Passive immunisation

Question 38.
The term ‘antitoxin’ refers to a preparation containing
(a) B-lymphoctyes and T-lymphocytes
(b) antibodies to the toxin
(c) weakend pathogen
(d) inactivated T-lymphocytes.
Answer:
(b) antibodies to the toxin

Question 39.
The injection given against the snake venom contains
(a) antigenic proteins
(b) preformed antibodies
(c) attenuated pathogen
(d) all of these.
Answer:
(b) preformed antibodies

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 40.
Vaccine against polio viruses is an example of
(a) auto-immunisation
(b) passive immunisation
(c) active immunisation
(d) simple immunisation
Answer:
(c) active immunisation

Question 41.
Hepatitis B vaccine is produced from
(a) inactivated viruses
(b) yeast
(c) Haemophilus influenzae
(d) Salmonella typhimurium.
Answer:
(b) yeast

Question 42.
Use of vaccines and immunisation programmes have controlled which of the following infectious diseases ?
(a) Polio and tetanus
(b) Diphtheria and pheumonia
(c) Cancer and AIDS
(d) Both (a) and (b)
Answer:
(d) Both (a) and (b)

Question 43.
The most abundant antibody produced against allergens is
(a) IgE
(b) IgA
(c) IgG
(d) IgM.
Answer:
(a) IgE

Question 44.
Which of the following cells actively participate during allergy ?
(a) B-lymphocytes
(b) Liver cells
(c) Mast cells
(d) Red blood cells
Answer:
(c) Mast cells

Question 45.
The drugs used to quickly reduce the symptoms of allergy are
(a) ati-histamine and adrenaline
(b) histamine and thyroxine
(c) adrenaline and a-interferon
(d) all of these
Answer:
(a) ati-histamine and adrenaline

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 46.
An auto-immune disease is
(a) SCID
(b) rheumatoid arthritis
(c) myasthenia gravis
(d) both (b) and (c).
Answer:
(d) both (b) and (c).

Question 47.
Which out of the following groups represent auto-immune disorders ?
(a) SCID and diphtheria
(b) Diabetes mellitus (type 1) and rheumatic fever
(c) AIDS and cholera
(d) Hepatitis and leukaemia
Answer:
(b) Diabetes mellitus (type 1) and rheumatic fever

Question 48.
The primary lymphoid organs are
(a) spleen and thymus
(b) bone marrow and thymus
(c) bone marrow and lymph node
(d) thymus and MALT.
Answer:
(d) thymus and MALT.

Question 49.
The site where lymphocytes interact with antigens and proliferate to become effector cells are
(a) spleen and lymph nodes
(b) bone marrow and thymus
(c) Peyer’s patches and tonsils
(d) both (a) and (c).
Answer:
(d) both (a) and (c).

Question 50.
Which of these glands is large at the time of birth but in adults, it reduces to a very small size ?
(a) Thyroid
(b) Adrenal
(c) Thymus
(d) Spleen
Answer:
(c) Thymus

Question 51.
MALT is
(a) Muscle Associated Lymphoid Tissues
(b) Mucosal Associated Lymphoid Tissues
(c) Mucosal and Lymphoid Tissue
(d) Memory Association Lymphoid Tissues.
Answer:
(b) Mucosal Associated Lymphoid Tissues

Question 52.
The lymphoid tissue, located within the lining of digestive tract is
(a) spleen
(b) Peyer’s pathes
(c) lymph nodes
(d) MALT
Answer:
(d) MALT

Question 53.
The abbreviation AIDS stands for
(a) Acquired immuno disease syndrome
(b) Acquired immuno deficiency syndrome
(c) Acquired immunity determining syndrome
(d) Acquired immunity delay syndrome.
Answer:
(b) Acquired immunodeficiency syndrome

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 54.
The genetic material of HIV is
(a) dsDNA
(b) dsRNA
(c) ssDNA
(d) ssRNA
Answer:
(d) ssRNA

Question 55.
The human immunodeficiency virus is
(a) an unenveloped, RNA genome containing retrovirus
(b) an enveloped, RNA genome containing retrovirus
(c) an enveloped, DNA genome containing retrovirus
(d) an enveloped, RNA genome containing reovirus.
Answer:
(b) an enveloped, RNA genome containing retrovirus

Question 56.
Which of the following is not a cause of transmission of HIV?
(a) Multiple sexual partners
(b) Sharing infected needles
(c) Mosquito bite
(d) Transfusion of contaminated blood
Answer:
(c) Mosquito bite

Question 57.
Viral DNA after being converted from viral RNA by X, incorporates into host genome to undergo replication. What is‘X’ ?
(a) DNA polymerase
(b) Restriction endonuclease
(c) RNA polymerase
(d) Revers transcriptase
Answer:
(d) Revers transcriptase

Question 58.
The cells called ‘HIV factory’ is
(a) helper T-cells
(b) macrophages
(c) dendritic cells
(d) WBCs.
Answer:
(b) macrophages

Question 59.
HIV is a retrovirus that attacks
(a) helper T-cells
(b) cytotoxin t-cells
(c) B-cells
(d) neutrophils.
Answer:
(a) helper T-cells

Question 60.
AIDS is characterised by
(a) decrease in the number of killer T-cells
(b) decrease in the number of suppressor T-cells
(c) decrease in the number of helper T-cells
(d) increase in the number of helper T-cells
Answer:
(c) decrease in the number of helper T-cells

Question 61.
AIDS is widely diagnosed by
(a) Widal test
(b) ELISA
(c) PC
(d) Chromatography.
Answer:
(b) ELISA

Question 62.
Which of the following day is celebrated as ‘World AIDS Day’ ?
(a) 31st March
(b) 1st March
(c) Ist December
(d) 31st December
Answer:
(c) Ist December

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 63.
Cancer cells do not exhibit the property of
(a) generating tumors
(b) metastasis
(c) contact inhibition
(d) less number of mitochondrial^cristae.
Answer:
(c) contact inhibition

Question 64.
A person suffering from leukaemia has
(a) tumors in adipose tissue
(b) increased number of plasma cells
(c) increased number of melanocytes
(d) increased number of WBCs.
Answer:
(d) increased number of WBCs.

Question 65.
A metastatic cancerous tumour is termed ‘sarcoma’ if the disorder is in
(a) fibroblasts
(b) circulatory system
(c) immune system
(d) epithelial cells.
Answer:
(a) fibroblasts

Question 66.
A chemical carcinogen present in tobacco smoke is responsible for
(a) skin cancer
(b) pancreatic cancer
(c) stomach cancer
(d) lung cancer.
Answer:
(d) lung cancer.

Question 67.
Major factors that cause cancer are
(a) oncogenes and polymorphonuclear leucocytes
(b) oncogenes and tumour suppressor genes
(c) MHC genes
(d) cellular oncogenes and a-interferons.
Answer:
(b) oncogenes and tumour suppressor genes

Question 68.
Which of the following approaches are used for the treatment of cancer ?
(a) Immunotherapy
(b) Surgery
(c) Radiotherapy & chemotherapy
(d) All of these
Answer:
(d) All of these

Question 69.
The substance given to cancer patients in order to activate their immune system and destroy the tumour is
(a) histamine
(b) interleukin
(c) a-interferon
(d) morphine.
Answer:
(c) a-interferon

Question 70.
In humans, receptors for opioids are present in
(a) central nervous system
(b) gastrointestinal tract
(c) respiratory tract
(d) both (a) and (b)
Answer:
(d) both (a) and (b)

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 71.
Heroin is commonly called as
(a) coke
(b) crack
(c) smack
(d) charas.
Answer:
(c) smack

Question 72.
Which compound is formed by acetylation of morphine ?
(a) Heroin
(b) Cocaine
(C) Tobacco.
(d) Marijuana
Answer:
(a) Heroin

Question 73.
Marijuana is extracted from .
(a) dried leaves and flowers of hemp plant .
(b) ergot fungus
(c) roots of hemp plant
(d) cocoa plant.
Answer:
(a) dried leaves and flowers of hemp plant .

Question 74.
Charas and ganja are the drugs which affect
(a) respiratory system
(b) cardiovascular system
(c) digestive system
(d) nervous system.
Answer:
(b) cardiovascular system

Question 75.
Cocaine is obtained from
(a) Erythroxylon coca
(b) Papaver somniferum
(c) Atropa belladona
(d) Dature stramonium
Answer:
(a) Erythroxylon coca

Question 76.
Cocaine is commonly called as
(a) smack
(b) coke
(c) crack
(d) both(b)&(c)
Answer:
(d) both(b)&(c)

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 77.
_______ is a CNS stimulant as it interferes with the trasport of the neuro-transmitter __________ .
(a) Cocaine, acetylcoline
(b) Barbituarate, glutamate
(c) Cocaine, dopamine
(d) Barbiturate, glycine
Answer:
(c) Cocaine, dopamine

Question 78.
Whihc of the following plants possess hallucinogenic properties ?
(a) Erythroxylon coca
(b) Atropa belladona
(c) Datura stramonium
(d) All of these
Answer:
(d) All of these

Question 79.
Which drug is being excessively taken by some sports persons nowadays ?
(a) Opioids
(b) Barbiturates
(c) Cannabinoids
(d) Lysergic acid diethly amides (LSD)
Answer:
(c) Cannabinoids

Question 80.
Which drug is used as medicine to help patients cope with depression and insomnia ?
(a) Morphine
(b) Amphetamines
(c) Barbiturate
(d) Both (b) and (c)
Answer:
(d) Both (b) and (c)

Question 81.
Which one of the following is an opiate narcotic ?
(a) Barbiturates
(b) Morphine
(c) Amphetamines
(d) LSD
Answer:
(b) Morphine

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 82.
Which one of the following is a mismatched pair of the drug and its effect ?
(a) Amphetamines – CNS stimulants
(b) Lysergic acid Diethlyamide (LSD) – Psychedelic (hallucinogen)
(c) Heroin – Depressant, slows down body functions
(d) Barbiturates – Transquilliser
Answer:
(d) Barbiturates – Transquilliser

Question 83.
The addictive chemical present in tobacco is
(a) caffeine
(b) nicotine
(c) catechol
(d) carbon monoxide.
Answer:
(b) nicotine

Question 84.
Level of which hormones get elevated by the intake of nicotine ?
(a) FSH,LH
(b) Thyroxine, progesterone
(c) Oxytocine, prolactin
(d) Adrenaline, nor-adrenaline
Answer:
(d) Adrenaline, nor-adrenaline

Question 85.
The intravenous drug abusers are more likely to develop
(a) cancer
(b) AIDS
(c) malaria
(d) typhoid.
Answer:
(b) AIDS

Question 86.
The organisms which cause diseases is plants and animals are called
(a) pathogens
(b) vectors
(c) insects
(d) worms.
Answer:
(a) pathogens

Question 87.
The chemical test that is used for diagnosis of tyhpoidis
(a) ELISA-Test
(b) EST-Test
(c) PCR-Test
(d) Widal-Test.
Answer:
(d) Widal-Test.

Question 88.
The sporozoites that cause infection, when a female Anopheles mosquito bites a person are formed in
(a) liver of the person
(b) RBCs of mosquito
(c) salivary glands of mosqiot
(d) intenstine of mosquito.
Answer:
(d) intenstine of mosquito.

Question 89.
The disease chikungunya is transmitted by
(a) house flies
(b) Aedes mosquitoes
(c) cockroach
(d) female Anopheles.
Answer:
(b) Aedes mosquitoes

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 90.
The genes causing cancer are
(a) structural genes
(b) expressor genes
(c) oncogenes
(d) regulatory genes.
Answer:
(c) oncogenes

Question 91.
AIDS is caused by HIV. Among the following, which one is not a mode of transmission of HIV ?
(a) Transfusion of contaminated blood.
(b) Sharing the infected needles.
(c) Shaking hands with infected persons.
(d) Sexual contact with infected persons.
Answer:
(c) Shaking hands with infected persons.

Question 92.
‘Smack’ is a drug obtained from the
(a) latex of Papever somniferum
(b) leaves of Cannabis saliva
(c) flowers of Datura
(d) fruits of Erythroxyl coca.
Answer:
(a) latex of Papever somniferum

Question 93.
The substance produced by a cell in viral infection that can protect other cells from further infection is
(a) serotonin
(b) colostrum
(c) interferon
(d) histamine.
Answer:
(c) interferon

Question 94.
Antibodies present in colostrum which protect the new born from certain diseases is of
(a) IgG type
(b) IgA type
(c) IgD type
(d) IgE type.
Answer:
(b) IgA type

Question 95.
Tobacco consumption is known to stimulate secretion of adrenaline and nor-adrenaline. The component causing this could be
(a) nicotine
(b) tannic acid
(c) curaimin
(d) catechin.
Answer:
(a) nicotine

Question 96.
Antivenom against snake poison contains
(a) antigens
(b) antigen-antibody complexes
(c) antibodies
(d) enzymes
Answer:
(c) antibodies

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Question 97.
Which of the following is not a lymphoid tissue ?
(a) Spleen
(b) Tonsils
(c) Pancreas
(d) Thymus
Answer:
(c) Pancreas

Question 98.
Which of the following glands is large sized at birth but reduces in size with ageing ?
(a) Pineal
(b) Pituitary
(c) Thymus
(d) Thyroid
Answer:
(c) Thymus

Question 99.
Haemozoin is a
(a) precursor of haemoglobin
(b) toxin released from Streptococcus infected cells
(c) toxin released from Plasmodium infected cells
(d) toxin released from Haemophilus infected cells.
Answer:
(c) toxin released from Plasmodium infected cells

Question 100.
One of the following is not the causal organism for ringworm.
(a) Microsporum
(b) Trichophyton
(c) Epidermophyton
(d) Macrosporum
Answer:
(d) Macrosporum

Question 101.
A person with sickle cell anaemia is
(a) more prone to malaria
(b) more prone to typhoid
(c) less prone to malaria
(d) less prone to typhoid.
Answer:
(c) less prone to malaria

Bihar Board 12th Biology Objective Answers Chapter 8 Human Health and Disease

Bihar Board 12th Biology Objective Answers Chapter 7 Evolution

Bihar Board 12th Biology Objective Questions and Answers

Bihar Board 12th Biology Objective Answers Chapter 7 Evolution

Question 1.
One of the possible early sources of energy was/were
(a) CO2
(b) chlorophyll
(c) green plants
(d) UV rays and lightning.
Answer:
(d) UV rays and lightning.

Question 2.
Abiogenesis theory of origin supports
(a) spontaneous generation
(b) origin of life from blue-green algae
(c) origin of life is due to pre-existing organisms
(d) organic evolution is due to chemical reactions.
Answer:
(a) spontaneous generation

Bihar Board 12th Biology Objective Answers Chapter 7 Evolution

Question 3.
Who proposed that the first form of the could have come from pre-existing non-living organic molecules ?
(a) S.L. Miller
(b) Oparin and Haldane
(c) Charles Darwin
(d) Alfred Wallace
Answer:
(b) Oparin and Haldane

Question 4.
According to one of the most widely accepted theories, earth’s atmosphere before origin of life was
(a) oxidising
(b) oxidising along with H2
(c) reducing with free O2 in small amount
(d) reducing with oxygen absent in O2 form.
Answer:
(b) oxidising along with H2

Question 5.
According to Oparin, which one of the following was not present in the primitive atmosphere of the earth ?
(a) Methane
(b) Oxygen
(c) Hydrogen
(d) Water vapour
Answer:
(b) Oxygen

Question 6.
The correct sequence for the manufacture of the compounds on the primitive earth is
(a) NH3, CH4, protein and carbohydrate
(b) protein, carbohydrate, water and nucleic acid
(c) NH3, CH4, carbohydrate and nucleic acid
(d) NH3, carbohydrate, protien and nucleic acid.
Answer:
(d) NH3, carbohydrate, protien and nucleic acid.

Bihar Board 12th Biology Objective Answers Chapter 7 Evolution

Question 7.
Early at mosphere contained methane and other hydrocarbons. They have been now replaced by
(a) nitrogen
(b) oxygen
(c) carbon dioxide
(d) hydrogen.
Answer:
(c) carbon dioxide

Question 8.
The first life originated
(a) on land
(b) in air
(c) in water
(d) all of these.
Answer:
(c) in water

Question 9.
Coacervates are
(a) colloid droplets
(b) nucleoprotein containing entities
(c) microspheres
(d) both (a) and (b)
Answer:
(d) both (a) and (b)

Question 10.
First life from on earth was a
(a) cyanobacterium
(b) chemoheterotroph
(c) autotroph
(d) photoautotroph.
Answer:
(b) chemoheterotroph

Question 11.
The ship used by Charles Darwin during the sea voyages was
(a) HMS Beagle
(b) HSM Beagle
(c) HMS Eagle
(d) HSM Eagle.
Answer:
(a) HMS Beagle

Question 12.
Fitnes according to Darwin refers to
(a) number of species in a community
(b) useful variation in population
(c) strength of an individual
(d) reproductive fitness of an organism.
Answer:
(d) reproductive fitness of an organism.

Bihar Board 12th Biology Objective Answers Chapter 7 Evolution

Question 13.
Alfred Wallace worked in
(a) Galapagos Island
(b) Australian Island Continent
(c) Ma lay Archipelago
(d) none of these.
Answer:
(c) Ma lay Archipelago

Question 14.
The theory of natural selection was given by
(a) Lamarck
(b) Alfred Wallace
(c) Charles Darwin
(d) Oparin and Haldane.
Answer:
(c) Charles Darwin

Question 15.
The preserved fossil remains of Archaeopteryx show that
(a) it was a flying reptile from the Permian period
(b) reptiles gave rise to birds during Jurassic period
(c) it was a flying reptile in the Triassic period
(d) reptiles gave rise to birds during Permian period.
Answer:
(b) reptiles gave rise to birds during Jurassic period

Question 16.
Which of the following isotopes is used for Finding the fossil age maximum about 35,0000 years ?
(a) 238U
(b) 14C
(c) 3H
(d) 206Pb
Answer:
(b) 14C

Question 17.
Which of the following statements is True ?
(a) Wings to birds and insects are homologous organs.
(b) Human hands and bird’s wings are analogous organs.
(c) Human hands and bat’s wings are analogous organs.
(d) Flipper of penguin and dolphin are analogous organs.
Answer:
(d) Flipper of penguin and dolphin are analogous organs.

Question 18.
Replacement of the lighter-coloured variety of peppered moth (Biston betularia) to its darker variety (Biston carbonaria) in England is the example of
(a) natural selection
(b) regeneration
(c) genetic isolation
(d) temporal isolation.
Answer:
(a) natural selection

Bihar Board 12th Biology Objective Answers Chapter 7 Evolution

Question 19.
Phenomenon of ‘industrial melanism’ demonstrates
(a) geographical isolation
(b) reproductive isolation
(c) natural selection
(d) induced mutation.
Answer:
(c) natural selection

Question 20.
Which one of the following phenomena supports Darwin’s concept of natural selection in organic evolution ?
(a) Development of transgenic animals
(b) Production of “Dolly’, the sheep by cloning
(c) Prevalence of pesticide resistant insects
(d) Development of organs from ‘stem cells’ for organ transplantation.
Answer:
(c) Prevalence of pesticide resistant insects

Question 21.
The phenomenon ‘ontogeny repeats phylogeny’ is explained by
(a) recapitualtion theory
(b) Inheritcance theory
(c) mutation theory
(d) natural selection theory.
Answer:
(a) recapitualtion theory

Question 22.
The presence of gill slits, in the embryos of vertebrates, supports the theory of
(a) metamorphosis
(b) biogenesis
(c) organic evolution
(d) recapitulation
Answer:
(d) recapitulation

Question 23.
Which is not a vestigial organ in man ?
(a) Nictitating membrane
(b) Tail vertebrae
(c) Vermiform appendix
(d) Nails
Answer:
(d) Nails

Question 24.
Which one is not a vestigia organ ?
(a) Wings of kiwi
(b) Coccyx in man
(c) Pelvic girdle of python
(d) Flipper of seal
Answer:
(d) Flipper of seal

Bihar Board 12th Biology Objective Answers Chapter 7 Evolution

Question 25.
By the statement ‘survival of the fittest’, Darwin meant that
(a) the strongest of all species survives
(b) the most intelligent of the species survives
(c) the cleverest of the species survives
(d) the species most adaptable to changes survives.
Answer:
(d) the species most adaptable to changes survives.

Question 26.
Which of the following are the two key concepts of Darwinian theory of evolution ?
(a) Genetic drift and mutation
(b) Adaptive radiation and homology
(c) Mutation and natural selection
(d) Branching descent and natural selection
Answer:
(d) Branching descent and natural selection

Question 27.
According to Lamarckism, long necked giraffes evolved because
(a) nature selected only long necked ones
(b) humans preferred only long necked ones
(c) short necks suddenly changed into long necks
(d) of stretching of necks over many generations by short necked ones.
Answer:
(d) of stretching of necks over many generations by short necked ones.

Question 28.
Which of the following evidences does not favour the Lamarckian concept of inheritance of acquired characters ?
(a) Lack of pigment in cave-dwelling animlas
(b) Melanisation in peppered moth
(c) Absence of limbs in snakes
(d) Presence of webbed toes in aquatic birds
Answer:
(b) Melanisation in peppered moth

Question 29.
“Human population grows in geometric ratio while food materials increase in arithmetic proportion”. It is a statement from
(a) Darwin
(b) Bateson
(c) AmartyaSen
(d) Malthus.
Answer:
(d) Malthus.

Question 30.
Which one of the following scientist’s name is correctly matched with the theory put forth by him ?
(a) de Vries – Theory of natural selection
(b) Darwin – Theory of pangenesis
(c) Weismann – Theory of continuity of germplasm
(d) Pasteur – Theory of inheritance of acquired charcters
Answer:
(c) Weismann-Theory of continuity of germplasm

Question 31.
Single step large mutation leading to speciation is also called
(a) founder effect
(b) saltation
(c) branching descent
(d) natural selection
Answer:
(b) saltation

Question 32.
At a particular locus, frequency of allele A is 0.6 and that of allele a is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium ?
(a) 0.36
(b) 0.16
(c) 0.24
(d) 0.48
Answer:
(d) 0.48

Question 33.
Hardy-Weinberg equilibrium is known to be affected by gene flow, genetic drift mutation, genetic recombination and
(a) evolution
(b) limiting facrtors
(c) saltation
(d) natural selection.
Answer:
(d) natural selection.

Bihar Board 12th Biology Objective Answers Chapter 7 Evolution

Question 34.
The Hardy-Weinberg principle cannot operate if
(a) a population does not migrate for a longtime to a new habitat.
(b) frequent mutations occur in the population
(c) the population has no chance of interaction with other populations
(d) free interbreeding occurs among all members of the population.
Answer:
(b) frequent mutations occur in the population

Question 35.
Genetic drift operates only in
(a) larger populations
(b) Mendelian populations
(c) island populations
(d) smaller populations.
Answer:
(d) smaller populations.

Question 36.
Which of the following is most important for speciation ?
(a) Seasonal isolation
(b) Reproductive isolation
(c) Behavioural isolation
(d) Tropical isolation
Answer:
(b) Reproductive isolation

Question 37.
The factors involved in the formation of new species are
(a) Isolation and competition
(b) gene flow and competition
(c) competition and mutation
(d) isolation and variation.
Answer:
(d) isolation and variation.

Question 38.
Stabilising selection favours
(a) both extreme forms of a trait
(b) intermediate forms of a trait
(c) environmental differences
(d) one extreme form over the other extreme form and over intermediate forms of a trait.
Answer:
(b) intermediate forms of a trait

Question 39.
The different forms of interbreeding species that live in different geographical regions are called
(a) sibling species
(b) sympatric species
(c) allopatric species
(d) polytypic species.
Answer:
(c) allopatric species

Question 40.
Which of following represents correct order of evolutiton ?
(a) Amoeba → Leucosolenia → Hydra → Ascaris
(b) Leucosolenia → Hydra → Amoeba → Ascaris
(c) Ascaris → Amoeba → Leucosolenia → Hydra
(d) None of these
Answer:
(a) Amoeba → Leucosolenia → Hydra → Ascaris

Bihar Board 12th Biology Objective Answers Chapter 7 Evolution

Question 41.
Presence of gills in the tadpole of frog indicated that
(a) fishes were amphibious in the past
(b) fishes evolved from frog-like ancestors
(c) frogs will have gills in future
(d) frogs evolved from gilled ancestors.
Answer:
(d) frogs evolved from gilled ancestors.

Question 42.
The character that proves that frogs have evolved from fishes is
(a) their ability to swim in water
(b) tadpole larva in frogs
(c) similarity in the shape of the head
(d) their feeding on aquatic plants.
Answer:
(b) tadpole larva in frogs

Question 43.
Identify the correct arrangement of periods of Palaeozoic era in ascending order in geological time scale.
(a) Cambrian → Devonian → Ordovician → Silurian → Carboniferous → Permian
(b) Cambrian → Ordovician → Silurian → Devonian→Carboniferous → Permian
(c) Cambrian → Ordovician → Devonian → Silurian → Carboniferous → Permian
(d) Silurian → Devonian → Cambrian → Ordovician → Permian → Carboniferous
Answer:
(b) Cambrian → Ordovician → Silurian → Devonian → Carboniferous → Permian

Question 44.
Which is the correct order of increasing geological time scale for a hypothetical vertebrate evolution ?
(a) Cenozoic, Mesozoic, Palaeozoic, Proterozoic
(b) Cenozoic, Palaeozoic, Mesozoic, Proterozoic
(c) Proterozoic, Cenozoic, Palaezoic, Mesozoic
(d) Proterozoic, Palaeozoic, Mesozoic, Cenozoic
Answer:
(d) Proterozoic, Palaeozoic, Mesozoic, Cenozoic

Question 45.
The ‘Devonian period’ is considered to be as
(a) age of fishes
(b) age of amphibians
(c) age of reptiles
(d) age of mammals.
Answer:
(a) age of fishes

Question 46.
Amphibians were dominant during _______ period.
(a) Carboniferous
(b) Silurian
(c) Ordovician
(d) Cambrian
Answer:
(a) Carboniferous

Question 47.
The primate which existed 15 mya was
(a) Homo habilis
(b) Australopithecus
(c) Ramapithecus
(d) Homo erectus
Answer:
(c) Ramapithecus

Bihar Board 12th Biology Objective Answers Chapter 7 Evolution

Question 48.
The extinct stone ancestor, who ate only fruits and hunted with stone weapons was
(a) Ramapithecus
(b) Australophecus
(c) Dryopithecus
(d) Homo erectus
Answer:
(b) Australophecus

Question 49.
One of the oldest, best preserved and most complete hominid fossil commonly known as ‘Lucy’ belongs to the genus
(a) Austraolopithecus
(b) Oreopithecus
(c) Dryopithecus
(d) Pithecanthropus
Answer:
(a) Austraolopithecus

Question 50.
The brain capacity of Homo eractus was about
(a) 650 c.c.
(b) 900 c.c.
(c) 1500 c.c.
(d) 1400 c.c.
Answer:
(b) 900 c.c.

Question 51.
The extinct human who lived 1,00,000 to 40,000 years ago, in East and Central Asia, used hides to protect their bodies and had brain capacity of 1400 c.c. were
(a) Homo habilis
(b) Neanderthal man
(c) Cro-Magnon man
(d) Ramapithecus.
Answer:
(b) Neanderthal man

Question 52.
Which of the following statements is correct ?
(a) Australopithecus has large brain around 900 c.c.
(b) Neanderthal man lived in East Africa and the fruits.
(c) Homo erectus had brain capacity 900 c.c.
(d) Homo sapiens arose in Central Asia and moved to other continuents and developed into distinct races.
Answer:
(c) Homo erectus had brain capacity 900 c.c.

Question 53.
Which of the following statements js correct regarding evolution of mankind ?
(a) Homo erectus is preceded by Homo habilis.
(b) Neanderthal man and Cro-Magnon man were living at the same time.
(c) Australopithecus was living in Australia.
(d) None of these
Answer:
(a) Homo erectus is preceded by Homo habilis.

Question 54.
The cranial capacity was largest among the
(a) Peking man
(b) Java ape man
(c) African man
(d) Neanderthal man.
Answer:
(d) Neanderthal man.

Question 55.
The most apparent change during the evolutionary history oiHomo sapiens is traced in
(a) loss of body hair
(b) walking unright
(c) sortening of the jaws
(d) remarkable, increase in the brain size.
Answer:
(d) remarkable, increase in the brain size.

Question 56.
What kind of evidences suggested that man is more closely related with chimpanzee than with other hominoid apes ?
(a) Evidence from DNA of sex chromosomes only
(b) Comparison of chromosome morphology and number
(c) Evidence from fossil remains, and the fossil mitochondrial DNA alone
(d) Evidence from banding pattern of chromosome 3 and 6
Answer:
(d) Evidence from banding pattern of chromosome 3 and 6

Bihar Board 12th Biology Objective Answers Chapter 7 Evolution

Question 57.
Which of the following eras, in geological time scale, corresponds to the period when life had not orginated upon the earth ?
(a) Azoic
(b) Palaeozoic
(c) Mesozoic
(d) Archaeozoic
Answer:
(a) Azoic

Question 58.
Homo sapiens arose during which epoch ?
(a) Pleistocene
(b) Pliocene
(c) Oligocene
(d) Holocene
Answer:
(d) Holocene

Question 59.
Study the human evolution is called
(a) archaeology
(b) anthropology
(c) pedigree analysis
(d) chronobiology.
Answer:
(b) anthropology

Question 60.
Which of the following is used as an atmospheric pollution indicator ?
(a) Lepidoptera
(b) Lichens
(c) Lycopersicon
(d) Lycopodium
Answer:
(b) Lichens

Question 61.
The theory of spontaneous generation stated that
(a) life arose from living forms only
(b) life can arise from both living and non-living
(c) life can arise from non-living things only
(d) life arises spontaneusly, neither from living nor from the non-living.
Answer:
(c) life can arise from non-living things only

Question 62.
Animal husbandry and plant breeding programmes are the examples of
(a) reverse evolution
(b) aritifical selection
(c) mutation
(d) natural selection.
Answer:
(d) natural selection.

Question 63.
Palaentological evidences for evolutaion refer to the
(a) development of embryo
(b) homologous organs
(c) fossils
(d) analogous organs.
Answer:
(c) fossils

Bihar Board 12th Biology Objective Answers Chapter 7 Evolution

Question 64.
The bones of forelimbs of whale, bat, cheeah and man are similar in structure, because
(a) one organism has given rise to another
(b) they share a common ancestor
(c) they perform the same function.
(d) the have biochemical similarities.
Answer:
(b) they share a common ancestor

Question 65.
Analogous organs arise due to
(a) divergent evolution
(b) artificial selection
(c) genetic drift
(d) convergent evolution.
Answer:
(d) convergent evolution.

Question 66.
(p+q)2 = p2 + 2pq + q2 = 1 represents an equation used in
(a) population genetics
(b) Mendilian genetics
(c) biometircs
(d) molecular genetics.
Answer:
(a) population genetics

Question 67.
Appearnace of antibiotic-resistant bacteria is an example of
(a) adaptive radiation
(b) transduction
(c) pre-existing variation in the population
(d) divergent evolution.
Answer:
(c) pre-existing variation in the population

Question 68.
Fossils are generally found in
(a) sedimentasry rocks
(b) igneous rocks
(c) metamorphic rocks
(d) any type of rock.
Answer:
(a) sedimentasry rocks

Question 69.
Which type of selection is industrial melanism observed in moth, Biston betularia?
(a) Stabilising
(b) Directional
(c) Disruptive
(d) Artificial
Answer:
(b) Directional

Question 70.
Which of the following is an example for link species ?
(a) Lobe fish
(b) Dodo bird
(c) Seaweed
(d) Chimpanzee
Answer:
(a) Lobe fish

Question 71.
Variations during mutations of meiotic recombinations are
(a) random and directionless
(b) random and directional
(c) random and small
(d) random small and directional
Answer:
(a) random and directionless

Bihar Board 12th Biology Objective Answers Chapter 7 Evolution

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Bihar Board 12th Chemistry Model Papers

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Time : 3 Hours 15 Min
Full Marks: 70

Instructions for the candidates

  1. Candidates are required to give answers in their own words as far as practicable.
  2. Figures in the right hand margin indicates full marks.
  3. While answering the questions, candidate should adhere to the words limit as far as practicable.
  4. 15 Minutes of extra time has been allotted for the candidates to read the questions carefully.
  5. This question paper is divided into two sections : Section -A and Section-B
  6. In Section A, there are 35 objective type questions which are compulsory, each carrying 1 mark. Darken the circle with blue/black ball pen against the correct option on OMR Sheet provided to you. Do not use Whitener/Liquid/Blade/ Nail on OMR Sheet otherwise your result will be treated as invalid.
  7. In section-B, there are 18 short answer type questions (each carrying 2 marks), out of which only 10 (ten) questions are to be answered Apart from this there are 06 Long Answer type questions (each carrying 5 marks), out of which 3 questions are to be answered.
  8. Use of any electronic device is prohibited.

Objective Type Questions

In the following questions no. from 1 to 35, there is only one correct answer against each question. For each question, mark (darken) the correct answer on the OMR Sheet provided to you. (1 x 35 = 35)

Question 1.
Which type of crystals contains more than one Bravais lattice ?
(a) Hexagonal
(b) Triclinic
(c) Rhombohedral
(d) Monoclinic
Answer:
(d) Monoclinic

Question 2.
For the structure given below the site marked as S is a …………….
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 1
(a) tetrahedral void
(b) cubic void
(c) octahedral void
(d) none of these
Answer:
(c) octahedral void

Question 3.
If the radius of an octahedral void is r and radius of atoms in close packing is R, the relation between r and R is
(a) r = 0.414 R
(b) R = 0.414 r
(c) r = 2R
(d) r = \(\sqrt{2} R\)
Answer:
(a) r = 0.414 R

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Question 4.
A metal crystallises into a lattice containing a sequence of layers as AB AB AB………………… What percentage of voids are left in the lattice ?
(a) 72%
(b) 48%
(c) 26%
(d) 32%
Answer:
(c) 26%

Question 5.
In ccp arrangement the pattern of successive layers can be designated as
(a) AB AB AB
(b) ABC ABC ABC
(c) AB ABC AB
(d) ABA ABA ABA
Answer:
(b) ABC ABC ABC

Question 6.
A solution is obtained by mixing 200 g of 30% and 300 g of 20% solution by weight. What is the percentage of solute in the final solution ?
(a) 50%
(b) 28%
(c) 64%
(d) 24%
Answer:
(d) 24%

Question 7.
When 1.04 g of BaCl2 is present in 105 g of solution the concentration of solution is ………….
(a) 104 ppm
(b) 10.4 ppm
(c) 0104 ppm
(d) 104 ppm
Answer:
(b) 10.4 ppm

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Question 8.
In the cell, |Zn2+| |Cu2+|Cu, the negative terminals
(a) Cu
(b)Cu2+
(c) Zn
(d) Zn2+
Answer:
(d) Zn2+

Question 9.
What will be standard cell potential of galvanic cell with the following reaction ?
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 2
(a) 74 V
(b) 1.14 V
(c) 34 V
(d) – 0.34 V
Answer:
(c) 34 V                         .

Question 10.
In a reaction 2HI → H2 + I2 the concentration of HI decreases from 0.5 mol L-1 in 10 minutes. What is the rate of reaction during this interval ?
(a) 5 x 10-3 M min-1
(b) 5 x 10-3 M min-1
(c) 5 x 10-2 M min-1
(d) 5 x 10-2 M min-1
Answer:
(a) 5 x 10-3 M min-1

Question 11.
The rate of disappearance of SO, in the reaction, 2SO2 + O2  → 2SO3 is 1.28 x 10-5 Ms . The rate of appearance of SO3 is ……………….
(a) 64 x 10-5 M s-1
(b) 0.32 x 10-5 M s-1
(c) 56 x 10-5 Ms1
(d) 1.28 x 10-5  M s-1
Answer:
(d) 1.28 x 10-5  M s-1

Question 12.
Which of the following is a property of physisorption ?
(a) High specificity
(b) Irreversibility
(c) Non-specificity
(d) None of these
Answer:
(c) Non-specificity

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Question 13.
Which of the following statement is not correct about physisorption ?
(a) It is a reversible process
(b) It requires less heat of adsorption
(c) It requires activation energy
(d) It takes place at low temperature
Answer:
(c) It requires activation energy

Question 14.
The name of the metal which is extracted from the ore is given below. Mark the example which is not correct.
(a) Malachite – Cu
(b) Calamine – Zn
(c) Chromite – Cr
(d) Dolomite – Al
Answer:
(d) Dolomite – Al

Question 15.
Which of the followings is magnetite ?
(a) Fe2CO3
(b) Fe2O3
(c) Fe3O4
(d) Fe2O3.3H2O
Answer:
(c) Fe3O4

Question 16.
Nitrogen can form only one chloride with chlorine which is NCl3 whereas P can form PCl3 and PCl5. This is ……………
(a) due to absence of d-orbitals in nitrogen
(b) due to difference in size of N and P
(c) due to higher reactivity of P towards Cl than N
(d) due to presence of multiple bonding in nitrogen
Answer:
(a) due to absence of d-orbitals in nitrogen

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Question 17.
On heating a mixture of NH4Cl and KNO2, we get
(a) NH4NO3
(b) KNH4(NO3)2
(c) N2
(d) NO
Answer:
(c) N2

Question 18.
The melting point of copper is higher than that of zinc because
(a) the s, p as well as d-electrons of copper are involved in metallic bonding
(b) the atomic volume of copper is higher
(c) the d-electrons of copper are involved in metallic bonding
(d) the s as well as d-electrons of copper are involved in metallic bonding
Answer:
(c) the d-electrons of copper are involved in metallic bonding

Question 19.
Zr and Hf have almost equal atomic and ionic radii because of ………………….
(a) diagonal relationship
(b) lanthanoid contraction
(c) actinoid contraction
(d) belonging to the same group
Answer:
(b) lanthanoid contraction

Question 20.
Which of the following primary and secondary valencies are not correctly marked against the compounds ?
(a) [Cr(NH3)6]Cl3, p = 3,s = 6
(b) K2[Pt(CI4],p = 2,s = 4
(c) [Pt(NH3)2Cl2],p = 2,s = 4
(d) [Cu(NH3)4]SO4,p = 4,s = 4
Answer:
(d) [Cu(NH3)4]SO4,p = 4,s = 4

Question 21.
When aqueous solution of potassium fluoride is added to the blue coloured aqueous CuSO4 solution, a green precipitate is formed. This observation can be explained as follows.
(a) On adding KF, H2O being weak field ligand is replaced by F ions forming [CuF4 ]2- which is green in colour
(b) Potassium is coordinated to [Cu(H2O)4]2+ ion present in CuSO4 and gives green colour
(c) On adding KF, Cu2+ are replaced by K+ forming a green complex
(d) Blue colour of CuSO4 and yellow colour of KI form green colour on mixingAnswer:
(a) On adding KF, H2O being weak field ligand is replaced by F ions forming [CuF4 ]2- which is green in colour

Question 22.
IUPAC name of CH3)2 CH — CH2 — CH2Br is
(a) 1-bromopentane
(b) 1-bromo-3-methylbutane
(c) 2-methyl-4-bromobutane
(d) 2-methyl-3-bromopropane
Answer:
(b) 1-bromo-3-methylbutane

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Question 23.
The IUPAC name of the compound is
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 3
(a) 1 -fluoro-4-methyl-2-nitrobenzene
(b) 4-fIu6ro-lmethyl-3-nitrobenzene
(c) 4-methyl-l-fIuoro-2-nitrobenzene
(d) 2-fIuoro-5-methyl-l-nitrobenzene
Answer:
(d) 2-fIuoro-5-methyl-l-nitrobenzene

Question 24.
The C— O — H angle in ether is about
(a) 180°
(b) 190°28′
(c) 110°
(d) 105°
Answer:
(c) 110°

Question 25.
The C— O — H bond angle in alcohols is slightly less than the tetrahedral angle whereas the C— O — C bond angle in ether is slightly greater because ………
(a) of repulsion between the two bulky R groups.
(b) O atom in both alcohols and ethers is sp3-hybridised
(c) lone pair-lone pair repulsion is greater than bond pair­bond pair repulsion
(d) none of these
Answer:
(a) of repulsion between the two bulky R groups.

Question 26.
Propanone can be prepared from ethyne by
(a) passing a mixture of ethyne and steam over a catalyst, magnesium at 420°C
(b) passing a mixture of ethyne and ethanol over a catalyst zinc chromite
(c) boiling ethyne with water and H2SO4
(d) treating ethyne with iodine and NaOH
Answer:
(a) passing a mixture of ethyne and steam over a catalyst, magnesium at 420°C

Question 27.
In the following reaction, product (P) is
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 4
(a) RCHO
(b) RCH3
(c) RCOOH
(d) RCH2OH
Answer:
(a) RCHO

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Question 28.
IUPAC name of the compound (C2H5)2 NCH is
(a) 2, 2-diethylmethanamine
(b) N, N-diethylmethanamine
(c) N-ethyl-N-methylethanamine
(d) N-methylbutanamine
Answer:
(c) N-ethyl-N-methylethanamine

Question 29.
Reduction of aromatic nitro compounds using Sn and HCI gives
(a) armatic primary amines
(b) aromatic secondary amines
(c) aromatic tertiary amines
(d) aromatic amides
Answer:
(a) armatic primary amines

Question 30.
Which of the fol lowing is an example of an aldopentose ?
(a) D-Ribose
(b) Glyceraldehyde
(c) Fructose
(d) Erythrose
Answer:
(a) D-Ribose

Question 31.
Which of the following treatment will convert starch directly into glucose ?
(a) Heating with dilute H2SO4
(b) Fermentation by diastase
(c) Fermentation by zymase
(d) Heating with dilute NaOH
Answer:
(a) Heating with dilute H2SO4

Question 32.
The correct structure of monomers of buna-S is
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 5
Answer:
(c)

Question 33.
The S in buna-S refers to
(a) sulphur
(b) styrene
(c) sodium
(d) salicylate
Answer:
(b) styrene

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Question 34.
The main cause of acidity in the stomach is
(a) release of extra gastric acid which decrease the pH level
(b) indidestion and pain in large intestine
(c) increase the pH level in the stomach
(d) release of extra bile juice which increase alkaline medium in stomach.
Answer:
(a) release of extra gastric acid which decrease the pH level

Question 35.
Which of the following will not act as antacid ?
(a) Sodium hydrogen carbonate
(b) Magnesium hydroxide
(c) Sodium carbonate
(d) Aluminium carbonate
Answer:
(c) Sodium carbonate

Non-Objective Type Questions

Short Answer Type Questions

In this Section, there are 18 Short answer type questions (each carrying 2 marks), out of which answer any 10 questions.  2 x 10 = 20

Question 1.
Calculate the osmotic pressure of 5% solution of urea at 272 K . (R = 0.0821 L-atm. deg-1).
Answer:
As we know that \(\pi=\frac{n_{\text {urea }} R T}{V}\)
Number of moles in urea \(=\frac{5}{60}=0.083\)
Volume of Solution \(=\frac{100}{1000}=0.1\) litres
Hence, Osmotic Pressure, \(\pi=\frac{0.083 \times 0.0821 \times 272}{0.1}=18.53 \mathrm{atm}\)
Osmotic Pressure = 18.53atm

Question 2.
Define standard electrode potential.
Answer:
Standard Electrode Potential : The standard electrode potential is the potential difference between the electrode & electrolyte (at 1 M), at standard conditions (1 atm, 298 K). Standard electrode potential is abbreviated by (E or E°).

Question 3.
What is activation energy ? How is the rate constant of a reaction related to its activation energy ?
Answer:
Activation Energy: The minimum extra amount of energy absorbed by the reactant molecules so that their energy becomes equal to threshold value is called activation energy.
Activation energy (Ea)= Threshold energy (ET) – Average energy of the reactant (ER). i.e. Ea = ET – ER
If activation energy will be less, then faster will be the reaction.
i. e . Activation energy = \(\alpha \frac{1}{\text { rate of reaction }}\)
e.g. 2NO + O2 → 2NO2
It is a fast reaction because of low activation energy. 2CO + O2 → 2CO2
It is a slow reaction because of high activation energy.

Question 4.
What is the main difference between physiorption and Chemisorption ?
Answer:
Physisorption:

  • Force of attraction are Vander Waal’s forces.
  • It usually takes place at low temperature and decreases with increasing temperature.
  • It does not require any activation energy.

Chemisorption :

  • Force of attraction are chemical bond forces.
  • It takes place at high temperature.
  • It requires high activation energy.

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Question 5.
Differentiate the following giving suitable example:
(i) Calcination and Roasting
(ii) Flux and Slag.
Answer:
(i) Calcination :
(a) Calcination is a thermal treatment process in absence of air applied to ores and materials to bring about a thermal decomposition, phase transition or removal of volalatile fraction It is done at temperature below the melting point of the product material.
(b) Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 6

Roasting:
(a) Roasting is reverse process of calcination. It is also thermal process in presence of air applied to ore for removal of volatile fraction under melting point of the product material is called Roasting.
(b) Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 7

Flux :
(a) It is chemical cleaning agent, which remove impurities from metal.
(b) Example – CaO + SiO2 → CaSiO3

Slag :
(a) Slag is partially vitereous by product of the process of smelting ores, which separates the desiredmetal fraction from the unwanted fraction. It is mixture of metal oxide
(b) Example – CaO + SiO2 → CaSiO3

Question 6.
Why do transition elements form coloured compounds ? Explain.
Answer:
The value of electrods potential depends upon the heat of sublimation and ionisation energy
ΔH – ΔHsub + IE + ΔHhyd . Due to the influence of ligand d-orbitals of transition metals divide into two unequal energy containing sets. Unpaired electrons absorb sunlight and jumps from one orbit into another orbit and one clour is reflected.

Question 7.
Predict the geometrical shapes of the following:
(a) sp3
(b)d2sp3
Answer:
(a) sp3 tetra-hedral
(b)d2SP3 – Square tetrahedral.

Question 8.
Specify oxidation numbers of the metals in the following co-ordination compounds:
(a) K4[Fe(CN)6]
(b) [PtCl4]2-
Answer:
(a) Oxidation number of (co-ordination compound)
Let oxidation number of Fe = x
Hence, 1 x 3 + (x -1 x 6 = 0
or, x – 3 = 0
x = 3 = O. N of Fe

(b) Oxidation number of (co-oridnation compaund)
Hence, x + 4 (-1) = – 2
or, x = -2 + 4 = + 2 = ON of Pt

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Question 9.
Write the structural formulae of the following:
(a) 4,4 dimethyl-2-pentanol
(b) 2-butanol.
Answer:
(a) 4, 4 dimethyl, 2-Pentanol
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 8

Question 10.
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 9
Answer:
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 10

Question 11.
How will you convert the following ?
(a) Ethyl alcohol to ethylamine
(b) Ethylamine to ethyl alcohol.
Answer:
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 11

Question 12.
Explain in which of the following compounds, the chemical bond would have less ionic character: LiCl or KCl.
Answer:
LiCl > KCl – Due to large size of k, KCl compound has less ionic character. LiCl is covalent than Li+ has higher polarisation capacity.

Question 13.
Discuss briefly the structure of CsCl.
Answer:
Structure of CsCl.
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 12

Question 14.
The osmotic pressure of sugar solution is 2.46 atm at 27°C. Calculate the concentration of the solution.
Answer:
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 13

Question 15.
How is molarity of a solution different from molality?
Answer:
Molarity : It is defined as the number of moles of solute dissolved in one liter of solution
\(Molarity (\mathrm{M})=\frac{\text { Moles of solute }}{\text { Volume of Solution in liter }} \)

Molality : It is defined as the number of moles of solute dissolved in one kg of solvent
\(Molality (\mathrm{m})=\frac{\text { Moles of the Solute }}{\text { Mass of the solvent in } \mathrm{kg}}\)

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Question 16.
Define heat of neutralisation.
Answer:
Defination of heat of neutralization : The heat reaction resulting from the neutralization of an acid or base especially the quantity produced when a gram equivalent of a base or acid is neutralized with a gram equivalent of an acid or base in dilute soliution.

Question 17.
(a) State law of mass action.
(b) What is the effect of temperature on reaction ?
Answer:
(a) Law of mass action: Law stating that the rate of any chemical reaction is proportional to the product of the masses of the reacting substances, with each mass raised to a power equal to the coefficient that occurs in the chemical equation.

(b) The effect of increasing collision frequency on the rate of the reaction is very minor increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions.

Question 18.
Discuss the following terms :
(a) Coordination number
(b) Effective atomic number.
Answer:
(a) The coordination number of a central atom in a molecure or crystal is the number of its near neighbours. This number is determined some what differently for molecules than for crystals.

(b) Effective atomic number has two different meaning; one that is the effective nuclear charge of an atom, and other that calculates the average atomic number for a compound or mixture of materials.

Long Answer Type Questions

There are 06 long answer type questions (each carrying 05 marks), out of which answer any there questions.
(5 x 3 = 15)

Question 19.
Define order to reaction and molecularity of relation. Derive a general expression for specific rate constant of first order reaction.
Answer:
It is the numbers of atom, ion, and molecule that collide with one another simultaneously so as to result into a chemical reaction
Rate constant → It is the speed at which the reactions are converted into the products at any moment of time.
Law of Mass Action → At a given temperature, the rate of a chemical reaction is directly proportional to the product of molar concentrations of reacting species with each concentration term raised to the power equal to numerical co-efficient of that species in the chemical reaction.
Thus, A + B → Products
Rate of reaction, r x [A] [B] = K [A] [B]
Where, [A] and [B] are the molar concentrations of the reactants A and B respectively and K is a constant of proportionality.
∴Rate = K [A]a [B]b

First Order Reaction – It is the type of reaction in which the rate of reaction depends only on the first power of the concentration of a single reacting Species.
Let, A + B → Product
If, a be the initial concentration of A and after time t, the concentration of product is x, then the concentration of A left at that instant is (a – x)
A → Products
initial conc.n (a)  ….(i)
after time ‘t’ (a – x)  … (ii)
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 14
Where, C → integration constant, which can be obtained from initial condition of the reaction, when, t = 0, x = 0,
then, from (iii) In (a – 0) = K x 0 + C
or, C = In (a)  ………….. (iv)
from (iii) + (iv) – In (a -x) = Kt – In (a)
or, In (a) – In (a – x) = kt or, In (a) – In (a – x) = kt.
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 15

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Question 20.
(a) Differentiate between DNA and RNA.
(b) What are Nucleic acids ?
Answer:
(a) The structural difference between DNA and RNA
DNA : DNA is double stranded helix in which two strands are coiled spirally in opposite directions.

  • The sugar molecule is 2-dehydrobase.
  • Nitrogeneous base uracil is not present.
  • DNA molecule are very large their molecules weights may vary from 6 million to 16.
  • DNA has unique property of replication.

RNA :

  • It is single strainded structure.
  • The sugar molecules is ribose.
  • Nitrogeneous base they-mine is not present.
  • RNA molecules are much smaller with molecular weight ranging from 20000 to 40000.
  • RNA usually doesn’t replicate.

(b) Nucleic acid – Nucleic acid are found in all living cells in form of nucleo proteins. They constitute important class of biomolecules. Nucleic acids are genetic material of the cells and are responsible for transmission of herediatry effect from one generation to the other and also carry out the biosynthesis of proteins. Nucleic acid are biopolymers (i.e., polymers present in living system). The genetic information about in nucleic acid controls the structure of all proteins including enzymes and thus governs the entire metabolic activity in the living organism.

Question 21.
(a) Discuss the principle involved in the manufacture of sulphuric acid by contact process.
(b) How will you test for sulphate ion ?
Answer:
From following steps sulphuric acid is manufactured
(i) SO2 gas is produced by burning sulphur of FeS2 in excess of air
S + O2  → SO2
4 FeS2 +11O2 → 2Fe2 O3 + 8SO2

(ii) SO2 is oxidised into SO3 in prensence of catalyst
2 SO2 + O2 → 2 SO3

(iii) SO3 on treatment with cone. H2SO4 oleum (H2S2O7) is obtained.
SO3 + H2SO4  → 2 H2S22O7

(iv) From oleum sulphuric acid is obtained of desired concentration by diluting water.
H2S2O7+ H2O → 2H2OSO4

(b) Test of sulphate radical (of NO2SO4) – We mix up Barium chloride in the salt. We get white precipate of BaSO4 which is insoluble in dil. HCl & HNO3.
BaCl2 4- Na2SO4 → BaSO4 ↓ +2 NaCl
BaCl2 + HNO3 → In soluble

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Question 22.
What are carbohydrates ? How are they classified ?
Answer:
Carbohydrates are the naturally occuring organic compounds and are a major source of energy to our body. In plants carbohydrates are formed as a result for photosynthesis.
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 16
In animal systems the carbohydrates undergo decomposition to form carbon-dioxide and water accompanied by the release of energy needed for the body.

Composition of carbohydrates – The chemical formula of the carbohydrates suggests that these are the hydrates of carbon. For example, glucose may be represented as C6(H2O)6 while sucrose as C12(H2O)11 . But this definition has certain limitation.

(i) Compounds like formaldehyde (CH2O) and acetic acid (C2H4O2) are the hydrates of carbon do not show characteristics of carbohydrates.

(ii) Similarly, compound like rhammose (C6H12O6) and deoxyribose (C5H10O4) are carbohydrates but not the hydrates of carbon.

The definition of carbohydrates has been modified and they may be defined as—The polyhydroxy aldehydes or polyhdroxy ketones are substances which generally give these on hydrolysis; contain atleast one chiral carbon and are therefore, opitcally active classification of carbohydrates—

Classification of carbohydrates are done in three way

(a) Based on molecular size – on the basis of the molecular size, carbohydrates have been classified into three types. These are

  • Manosaccharides
  • Oligosoccharides
  • Polysaccharides

Based on taste – Carbohydrates with sweet taste are called sugar while those without a sweet taste are called non-sugars. It may be noted that all mono and oligosaccharides are sugars while polysaccharides are non­sugar.

Reducing and non-reducing sugar –  Carbohydrate which reduce Tollen’s reagent and Fehling solution are called reducing sugar while those which don’t reduce, these are called non reducing sugars. For example – glucose and fructose.

Question 23.
Disuss the following :
(a) Kolbe’s reaction
(b) Wurtz’s reaction
(c) Carbylamine reaction.
Answer:
(a) Kolbe’s reaction – The reaction of phenoxide ion with CO2 at the high pressure and temperature followed by acidification to form salicylic acid is called Kolbe’s reaction.
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 17

(b) Wurtz reaction-When two moles of alkyl halide is heated with Na in the presence of ether goes higher alkane.
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 18

(c) Carbylamine reaction-Chloroform when heated with primary amine in presence of alcoholic KOH forms a derivative called isocyanide.
Bihar Board 12th Chemistry Model Question Paper 4 in English Medium 19

Bihar Board 12th Chemistry Model Question Paper 4 in English Medium

Question 24.
Give one example for each of the following :
(a) Synthetic rubber
(b) Naturally occurring amino acid
(c) Condensation polymer
(d) Additional polymer
(e) Artificial sweeteners.
Answer:
(a) Nioprin
(b) Zwitter ion
(c) NYlon-6, 6
(d) Buna-5
(e) Saccharine.

 

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Bihar Board 12th Physics Model Papers

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Objective Type Questions

There are 1 to 35 objective type questions with 4 options. Choose the correct option which is to be answered on OMR Sheet. (35 x 1 = 35)

Question 1.
The electric field intensity at distance on the axis of an electric dipole is.Ej and E2 on the perpendicular bisector of dipole. The angle between E] and E2 is 6, will be
(a) 1 : 1, π
(b) 1 : 2, π/2
(c) 2 : 1, π
(d) 1 : 3 π
Answer:
(c) 2 : 1, π

Question 2.
The metre bridge is shown in figure. The value of x is
(a) 10Ω
(b) 3 ohm
(c) 9 ohm
(d) 10 ohm
Bihar Board 12th Physics Model Question Paper 5 in English Medium 1
Answer:
(a) 10Ω

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 3.
The dimension of electromotive force is
(a) |ML2 T-3]
(b) [ML2T-3I-1]
(c) [MLT-2]
(d) [ML2T-3I-1]
Answer:
(d) [ML2T-3I-1]

Question 4.
The power of electric circuit is
(a) V.R
(b) V2.R
(c) V2/R
(d) V2RI
Answer:
(c) V2/R

Question 5.
If a 60W and 40W bulb are joined in series the
(a) 60W bulb glow more
(b) 40 W bulb glow more
(c) Both bulb glow similar
(d) Only 60W bulb is lighted
Answer:
(b) 40 W bulb glow more

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 6.
Kilowatt hour (kwh) is unit of
(a) Power
(b) Energy
(c) Torque
(d) None of these
Answer:
(b) Energy

Question 7.
A magnet is cut parallel to its length in n equal
parts. Magnetic moment of each part will be
\(\text { (a) } \frac{M}{n}\)
\(\text { (b) } \frac{M}{n^{2}}\)
\(\text { (c) } \frac{M}{2 n}\)
(d) None of these
Answer:
\(\text { (a) } \frac{M}{n}\)

Question 8.
The work done to rotate the magnet with 90° will be
(a) MB
(b) MB cosθ
(c) MB sin θ
(d) MB (1 – sin θ)
Answer:
(b) MB cosθ

Question 9.
S.I. unit of polar strength is
(a) Ampere metre
(b) Tesla
(c) Faraday
(d) Ampere gm2
Answer:
(a) Ampere metre

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 10.
Which is ferromagnetic substance
(a) Mn
(b) Cr
(c) Zn
(d) Alnico
Answer:
(d) Alnico

Question 11.
Which law is based on the principle of conservation of energy?
(a) Lenz’s law
(b) Faraday’s law
(c) Ampere’s law
(d) None of these
Answer:
(a) Lenz’s law

Question 12.
The unit of reactance is
(a) mho
(b) ohm
(c) Faraday
(d) ampere
Answer:
(b) ohm

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 13.
The phase difference between current and voltage in AC circuit is 0. Then power factor will
(a) cos θ
(b) sin θ
(c) tan θ
(d) 1θ
Answer:
(a) cos θ

Question 14.
The velocity of electro magnetic wave in air is
Bihar Board 12th Physics Model Question Paper 5 in English Medium 2
Answer:
(b)

Question 15.
The light waves are transverse in nature which is shown by
(a) Scattering
(b) Diffraction
(c) Interference
(d) Polarisation
Answer:
(d) Polarisation

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 16.
When two converging lens of same total length / are placed in contact then focal length combination is
(a) f
(b) 2f
(c) f2
(d) 3f
Answer:
(c) f2

Question 17.
When the light ray passes from one medium to another medium then it is deviated, is called
(a) Dispersion
(b) Refraction
(c) Diffraction
(d) Reflection
Answer:
(b) Refraction

Question 18.
Convex lens are used for
(a) Myopia
(b) Hypermetropia
(c) Old sightedness
(d) Astigmatisn
Answer:
(b) Hypermetropia

Question 19.
The path difference for destructive interference is
(a) nλ
\(\text { (b) }(2 n+1) \frac{\lambda}{2}\)
(c) Zero
(d) infinity
Answer:
\(\text { (b) }(2 n+1) \frac{\lambda}{2}\)

Question 20.
Brewler’s law is
(a) μ = sin ip
(b) μ = cos ip
(c) μ = tan ip
(d) μ = tan2 ip
Answer:
(c) μ = tan ip

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 21.
Light is made of vibration by
(a) Ether particle
(b) Air particle
(c) Electric and magnetic field
(d) None of these
Answer:
(c) Electric and magnetic field

Question 22.
Photo cell is based on
(a) photo electric effect
(b) chemical effect of current
(c) magnetic effect of current
(d) electromagnetic cell
Answer:
(a) photo electric effect

Question 23.
Which is uncharged
(a) α-particle
(b) β-particle
(c) photon
(d) proton
Answer:
(c) photon

Question 24.
Lymen series of Hydrogen lies in electromagnetic spectrum is
(a) X : ray
(b) Visible
(c) Infrared
(d) Ultra-violet
Answer:
(d) Ultra-violet

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 25.
When transition takes place in hydrogen atom from higher orbit to another orbit then obtain
(a) Lymen series
(b) Balmer series
(c) Paschan series
(d) Pfund series
Answer:
(b) Balmer series

Question 26.
The average binding energy per nucleon of nucleus is
(a) 8 ev
(b) 8 Mev
(c) 8 Bev
(d) 8 Joule
Answer:
(b) 8 Mev

Question 27.
The cause of emission of energy in star is
(a) chemical reaction
(b) fusion of heavy nucleus
(c) fusion of light nucleus
(d) fission of heavy nucleus
Answer:
(c) fusion of light nucleus

Question 28.
The Boolean expression of OR gate is
(a) A + B = y
(b) A.B = y
\(\text { (c) } \bar{A}=y\)
\(\text { (d) } \mathrm{C}=\overrightarrow{\mathrm{A} \cdot \mathrm{B}}\)
Answer:
(a) A + B = y

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 29.
The permeability of Ferromagnetic substance is
(a) μ > 1
(b) μ = 1
(c) μ < 1
(d) μ = 0
Answer:
(a) μ > 1

Question 30.
The light is emitted in forward biased junction diode, is called
(a) LED
(b) Photo diode
(c) Zener diode
(d) None of these
Answer:
(a) LED

Question 31.
Which expression is correct?
Bihar Board 12th Physics Model Question Paper 5 in English Medium 3
Answer:
(d)

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 32.
The majority carriers in n-type semi conductor is
(a) proton
(b) hole
(c) a-particle
(d) electron
Answer:
(d) electron

Question 33.
Which frequency range is used for TV transmission?
(a) 30 HZ-300HZ
(b) 30 KHZ-300 KHZ
(c) 30 MHZ-300MHZ
(d) 30GHZ-300GHZ
Answer:
(a) 30 HZ-300HZ

Question 34.
Ionosphere is used for radio waves in
(a) rarer mediun
(b) denser medium
(c) free space
(d) dielectric
Answer:
(a) rarer mediun

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 35.
The maximum distance upto which TV signal can be received from Antenna of height h is proportional to
(a) h1/2
(b) h
(c) h5/2
(d) h2
Answer:
(a) h1/2

Non-Objective Type Questions!
Short Answer Type Questions

Question No. 1 to 18 are short answers type question. Each question carries 2 marks. Answer any ten (10) question.

Question 1.
Electric lines of force never intersect to each other. Why?
Answer:
If two lines of force intersect at a point then it will mean that at that point electric field has two directions. As it is not possible, the lines of force here not intersect to each other.

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 2.
Write the limitations of Coulomb’s law.
Answer:
Coulomb’s law in electrostatics does not hold in all situation. It is applicable only in following situations :

  1. The electric charges must be stationary.
  2. The electric charge must be point in size. Coulomb’s law doesn’t apply to two charged bodies of finite size. It is because, the distribution of charge doesn’t remain uniform when the two bodies are brought together.

Question 3.
Prove maximum power theorem.
Answer:
It states that the output power of a source of emf is maximum, when the external resistance in the circuit is equal to the internal resistance of the source.
Bihar Board 12th Physics Model Question Paper 5 in English Medium 4
Bihar Board 12th Physics Model Question Paper 5 in English Medium 5

Bihar Board 12th Physics Model Question Paper 5 in English Medium

This is maximum power theorem.

Question 4.
Establish the relation b/w current density and drift velocity.
Answer:
Bihar Board 12th Physics Model Question Paper 5 in English Medium 6

Question 5.
What is Hysteresis loop? With its help explain the terms retentivity and co-ercivity.
Answer:
Hysteresis loop : Hysteresis loop is defined as the lagging of the magnetic induction B behind the corresponding magnetic field H.

When magnetic field H and the magnetic induction B are yarned from zero to maximum in one direction and then back through zero to a maximum in the opposite direction and finally back again through zero to the first maximum, a cycle of magnetisation is said to be completed. B(T) Y Using the value of H and B obtained above, we plot a graph by taking H along x-axis and B along y-axis. When the magnetic field H is increased from zero to the maximum value Og, the induction B follows the curve Oa. However, when the magnetic field is brought to zero, the.;induction does not follows back the curve Oa but a different curve ab. The same pattern of variations is seen for the rest of the curve. The B-H curve for decreasing H does not coincide with the B-H curve for increasing H.
Bihar Board 12th Physics Model Question Paper 5 in English Medium 7

As is clear from figure, even when the magnetising field H is zero, some magnetic induction (Ob or Oe) is still present in the speci nen. It is denoted by Br and is called remanance or retent i vity or residual magnetism.

The value of the intensity of magnetisation of a material when the magnetisi ng field is reduced to zero is called retentivity.

After the specimen has been magnetised to saturation (oh or oj) a reversed magnetising field (equal to Oc or Of) is required to reduce the magnetic induction to zero.This is called the coercivity or coercive force He. The value of the magnetising field required to reduce residual magnetism to zero is called coercivity of the material.

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 6.
Write the expression for energy stored in the
Answer:
The induced emf in coil \(e=-L \frac{d I}{d t}\)
let chasge dq passes from coil, the work done dw = e.dq
\(\begin{aligned}
&=\mathrm{L} \cdot \frac{d I}{d t} d q=\mathrm{L} \cdot d I \cdot \frac{d q}{d t} \\
d w &=\mathrm{LI} . \mathrm{dI}
\end{aligned}\)

work done after posting current O to 1
\(\omega=\mathrm{L} \int_{0}^{1} I d I=\mathrm{L}\left[\frac{I^{2}}{2}\right]_{0}^{1} ; \omega=\frac{1}{2} \mathrm{L}^{2}\)

This work done is stored in the potential energy of coil.
\(P \cdot E=\frac{1}{2} L I^{2}\)

Question 7.
What is current sensitivity and voltage sensitivity of moving coil galvanometer?
Answer:
Current sensitivity : It is defined as the deflection produced in the galvanometer, when a unit voltage is applied across its cops.
\(\frac{\alpha}{\mathrm{I}}=\frac{\mathrm{nBA}}{\mathrm{K}}\)

Voltage sensitivity : It is defined as the deflection produced in the galvanometer, when a unit voltage is applied across its COPI.
\(\frac{\alpha}{V}=\frac{n B A}{K R}\)

Question 8.
Write the expression for energy density related with electro magnetic wave and show that its ratio is equal to 1.
Answer:
Bihar Board 12th Physics Model Question Paper 5 in English Medium 9
Bihar Board 12th Physics Model Question Paper 5 in English Medium 10

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 9.
Sketch the wave front corresponding to (a)
diverging rays and (b) converging rays.
Answer:
Bihar Board 12th Physics Model Question Paper 5 in English Medium 11

Question 10.
Write the differences between magnification and magnifying power.
Answer:
Magnification :

  • It is a linear magnification which is equal to \(\frac{n_{2}}{n_{1}}\).
  • Its value increases with increase in V.
  • It may be between to -∞ to +∞.
  • Under certain conditions it is equal to magnifying power.

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Magnifying power :
(i) It is an angular magnification which is equal to \(\frac{\angle \beta}{\angle \alpha}\)
(ii) Its value decreases with increase in V.
(iii) Its value may be b/w \(\frac{d}{f}\) and \(\left(1+\frac{D}{f}\right)\)
(iv) It is a special condition of magnification when (ve = D

Question 11.
Derive the expression for de-Broglie wave length.
Answer:
A/C to quantum theory E = hv ……………………….. (i)
Bihar Board 12th Physics Model Question Paper 5 in English Medium 12
Bihar Board 12th Physics Model Question Paper 5 in English Medium 13

λ is called de-Broglie wavelength.

Question 12.
What is mass defect?
Answer:
Mass defect : The difference b/w sum of the masses of neutrons and protons forming a nucleus and actual mass of the nucleus is called mass defect.
Δm = [mpz + mn (A – Z) – M]
The unit of mass defect is amu.

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 13.
Why does thermionic emission takes place from metal surface only?
Answer:
Thermionic emission takes place from metal surface only because metal has free electrons on its surface.This free electrons requires less energy to come out from one surface. Also sometimes, to reduce work function of metal by coating oxide layer on metal.

Question 14.
Why is semi conductor damaged by a strong current?
Answer:
A strong current, when passed through a semi conductor, heat up the semi conductor and covalent bond break up. It results in a large number of free electrons. The material behaves as a conductor. As now the semi conductor no longer possesses the property of conduction, it is said to be damaged.

Question 15.
Write the differences between Intrinsic and extrinsic semi conductor.
Answer:
Intrinsic semi conductor :

  • They are the crystals of pure elements like Germanium and Silicon.
  • ne = nh
  • The electrical conductivity of Intrinsic semi conductor is low.
  • Resistivity is higher.

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Extrinsic semi conductor:

  • When some impurity is added in Intrinsic semi conductor, we get an extrinsic semi conductor.
  • ne ≠ nh
  • Its electrical conductivity is high.
  • Resistivity is lower.

Question 16.
Define mean value and root square value A.C. Write its expression.
Answer:
Mean value of Average value : It is that steady current when passes through the circuit for half time period, sends the same amount of charge of the alternating current, sends the charge in same circuit and in same time period. It is denoted by Im.
\(\begin{aligned}
&I_{m}=\frac{2 I_{0}}{\pi}\\
&I_{m}=0.636 I_{0}
\end{aligned}\)

R.M.S. value or virtual value: It is that steady current when passes through the circuit for half time period, produces the same amount of heat as the alternating current produces the heat in same time and in same circuit. It is denoted by Irms.
\(\begin{aligned}
&I_{r m s}=\frac{I_{0}}{\sqrt{2}}\\
&I_{r m s}=0.7071
\end{aligned}\)

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 17.
What is polaroids? Write its important uses.
Answer:
It is a device which produces plane polarised light. Use of polaroids :

  • Sun glasses fitted with polaroid sheets protect the eye from glass.
  • Wind shields of automobiles are also made of Polaroid sheets.
  • They are useful in three dimensional motion pictures.
  • It is used in L.C.D., calculator, watches, T.V. etc.

Question 18.
Write the condition for sustained interference.
Answer:
Condition for sustained interference :

  • The two source should emf the light wave continuously.
  • The light wave should be of same wave length.
  • The two light source should be narrow.
  • The light waves emitted should be of the same amplitude.
  • The two source of light must lie very close to each other.

Long Answer Type Questions

Question No. 19 to 24 are long answers type question. Each question of this category carries 5 marks. Answer any three (3) question. (3 x 5 = 15)

Question 19.
Explain any two of the following terms :
(i) Ground Waves
(ii) Sky Waves
(iii) Space Waves.
Answer:
(i) Ground Waves : The ground waves which progress along the surface of the earth are called ground waves or surface waves. The ground propagation is suitable for low and medium frequency, i.e., up to 2 MHz only, hence it is also called medium wave propagation: The maximum range of ground or surface wave propagation depends on :

Bihar Board 12th Physics Model Question Paper 5 in English Medium

  • The frequency of the radio waves and
  • Power of the transmitter.

(ii) The Sky Waves : The sky waves are the radio waves of frequency between 2 MHz to 30 MHz. The ionosphere reflects those radio waves so that they can propagate through atmosphere. The sky waves propagation is also known as ionosphere propagation.

The sky waves are used for very long distance radio communication at medium high frequencies (i.e. at medium waves and short waves). The radio waves can cover a distance approximately 400 km in a single reflection from the ionosphere.

(iii) Space Waves : The space waves are the radio waves of very high frequency (i.e. between 30 MHz to 300 MHz or more). The space waves can travel through atmosphere from transmitter antenna to receive antenna either directly or after reflection from ground in the earth’s troposphere region. It is also called Tropospherical propagation or line of sight propagation. This propagation is limited (a) to the line of sight distance, (b) by the curvature of the earth.

It is utilized in T.V. communication, Radar communication, etc.

Question 20.
Find an expression for the electric field strength at a distant point situated (i) on the axis and (ii) along the equatorial line of an electric dipole.
Answer:
Consider an electric dipole AB. The charges -q and +q of dipole are situated at A and B respectively. The separation between the charges is 21.

Electric dipole moment, p = Q 21
The direction of dipole moment is from -q to + Q

Bihar Board 12th Physics Model Question Paper 5 in English Medium

(i) At axial or end-on position : Consider a point P on the axis of dipole at a distance r from mid-point O of electric dipole.
Bihar Board 12th Physics Model Question Paper 5 in English Medium 14

The distance of point P from charge + q is BP = r – l and distance of point P from charge – q is, AP = r + l. Let E1 and E2 be the electric field strengths at point P due to charges +<7 and -q respectively. We know that the direction of electric field due to a point charge is away from positive charge and towards the negative charge. Therefore
Bihar Board 12th Physics Model Question Paper 5 in English Medium 15

Clearly the directions of electric field strengths \(\overrightarrow{\mathrm{E}}_{1}\) and \(\overrightarrow{\mathrm{E}}_{2}\) are along the same line but opposite to each other and E1 > E2 because positive charge is nearer.

∴ The resultant electric field due to electric dipole has magnitude equal to the difference of E1 and E2 and direction from 13 to P i.e.
Bihar Board 12th Physics Model Question Paper 5 in English Medium 16
Bihar Board 12th Physics Model Question Paper 5 in English Medium 17

Bihar Board 12th Physics Model Question Paper 5 in English Medium

If the dipole is infinitely small and point P is far away from the dipole, then r >> l, therefore equation (i) may be expressed as
\(\mathrm{E}=\frac{1}{4 \pi \varepsilon_{0}} \frac{2 p r}{r^{4}} \text { or } \mathrm{E}=\frac{1}{4 \pi \varepsilon_{0}} \frac{2 p}{r^{3}}\) …………………………… (ii)

This is the expression for the electric field strength at axial position due to a short electric dipole.

Question 21.
Explain the principle and working of a Cyclotron with the help of a neat diagram. Write the expression for Cyclotron frequency.
Or,With the help of a labelled diagram, state the underlying principle of a Cyclotron. Explain clearly how it works to accelerate the charged particles.
Bihar Board 12th Physics Model Question Paper 5 in English Medium 18

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Show that Cyclotron frequency is independent of energy of the particle. Is there an upper limit on the energy acquired by the particle? Give reason.
Answer:
(a) Cyclotron : The cyclotron, devised by Lawrence and Livingston, is a device for accelerating ions to high speed by the repeated application of accelerating potentials.

Construction:
The cyclotron consists of two flat semi-circular metal boxes called ‘dees’ and are arranged with a small gap between them. A source of ions is located near the mid-point of the gap between the dees (fig). The dees are connected to the terminals of a radio frequency oscillator, so that a high frequency alternating potential of several million cycles per second exists between the dees. Thus dees act as electrodes. The dees are enclosed in an insulated metal box containing gas at low pressure. The whole apparatus is placed between the poles of a strong electro¬magnet which provides a magnetic field perpendicular to the plane of the dees.

Working :
The principle of action of the apparatus is shown in fig.The positive ions produced from a source S at the centre are accelerated by a dees which is at negative potential at that moment. Due to the presence of perpendicular magnetic field the ion will move in a circular path inside the dees. The magnetic field and the frequency of the applied voltages are so chosen that as the ion comes out of a dees, the dees change their polarity (positive becoming negative and vice-versa) and the ion is further accelerated and moves with high velocity along a circular path of greater radius. The phenomenon is continued till the ion reaches at the periphery of the deeS where an auxiliary negative electrode (deflecting plate) deflects the accelerated ion on the target to be bombarded.

Bihar Board 12th Physics Model Question Paper 5 in English Medium

The function of electric field is to accelerae the charged particle and so to impart energy to the charged particle.

The function of magnetic field is to provide circular path to charged particle and so to provide the location where charged particle is capable of gaining energy from electric field.

Expression for Period of Revolution and Frequency :

Suppose the positive ion with charge q moves in a dees with a velocity v, then,
\(q v \mathrm{B}=\frac{m v^{2}}{r} \text { or }=\frac{m v}{q \mathrm{B}}\) …………………………… (i)

where m is the mass and r is the radius of the path of ion in the dees and B is the strength of the magnetic field. The angular velocity to of the ion is given by.
\(\omega=\frac{v}{r}=\frac{q \mathrm{B}}{m}( \text { from eq. }\) ………………… (ii)

The time taken by the ion in describing a semi-circle, i.e., in turning through an angle π is.
\(t=\frac{\pi}{\omega}=\frac{\pi m}{\mathrm{B} q}\)

Thus the time is independent of the speed of the ion i.e., although the speed of the ion goes on increasing with increase in the radius (from eQuestion i) when it moves from one dees to the other, yet it take the same time in each dees.

From eQuestion (iii) it is clear that for a particular ion, \(\frac{m}{q}\)

being known, B can be calculated for producing resonance with the high frequency alternating potential.

(b) Resonance Condition : The condition of working of cyclotron is that the frequency of radio frequency alternating potential must be equal to the frequency of revolution of charged particles within the dees. This is called resonance condition.

Now for the cyclotron to work, the applied alternating potential should also have the same semiperiodic time (T/2) as that taken by the ion to cross either dees, i.e.,

This is the expression for period of revolution. Obviously, period of revolution is independent of speed of charged particle and radius of circular path.

Bihar Board 12th Physics Model Question Paper 5 in English Medium

∴ Frequency of revolution of particles.
\(f=\frac{1}{T}=\frac{q B}{2 \pi m}\)

This frequency is called the cyclotron frequency. Clearly the cyclotron frequency is independent of speed of particle.

(c) Expression for K.E. attained : If R be the radius of the path and Vmax, the velocity of the ion when it leaves the periphery, then in accordance with eq (ii)
\(v_{\max }=\frac{q \mathrm{BR}}{m}\) …………………………….. (vi)

The kinetic energy of the ion when it leaves the apparatus is,
\(\text { K.E. }=\frac{1}{2} m v^{2} \max =\frac{q^{2} B^{2} R^{2}}{2 m}\) ………………….. (vii)

When charged particle crosses the gap between dees it gains KE = qV

In one revolution, it crosses the gap twice, therefore if it completes ^-revolutions before emerging the dees, the kinetic energy gained = 2nqV ………………. (viii)
\(\text { Thus, K.E. }=\frac{g^{2} \mathrm{B}^{2} \mathrm{R}^{2}}{2 m}=2 n q \mathrm{V}\)

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 22.
Using Ampere’s circuital law, derive an expression for the magnetic field along the axis of a toroidal solenoid.
Answer:
Magnetic field due to a toroidal solenoid : A long solenoid shaped in the form of closed ring is called toroidal solenoid (or endless solenoid). Let n be the number of turns per unit of toroid and I the current flowing through it. The current causes the magnetic field inside the turns of the solenoid. The magnetic lines of force inside the toroid are in the form of concentric circle. By symmetry of the magnetic field it has the same magnitude at each point of circle and is along the tangent at every point on the circle.
Bihar Board 12th Physics Model Question Paper 5 in English Medium 19

For points inside the core of toroid: Consider a circle of radius r in the region enclosed by turns of toroid. Now we apply Ampere’s circuital law to this circular path, i.e.,
\(\vec{f} \overrightarrow{\mathrm{B}} \cdot \overrightarrow{d l}=\mu_{0} I\) ………………. (i)

\(\vec{f} \overrightarrow{\mathrm{B}} \cdot \overrightarrow{d l}=f B d l \cos 0=B \cdot 2 \pi r\) Length of toroid = 2πr Number of turns in toroid = n (2πr) and current in one- turn = I.

∴ Current enclosed by circular path = (n 2πr) • 1
∴ Equation (i) gives
\(\mathrm{B} 2 \pi r=\mathrm{m}_{0}(n 2 \pi r l) \Rightarrow \mathrm{B}=\mu_{0} n \mathrm{l}\)

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Derivation of formula for magnetic field due to a current carrying wire using Biot-Savart law : Consider a wire EF carrying current I in upward direction. The point of observation is P at a finite distance R from the wire. If PM is perpendicular dropped from P on wire; then PM = R. The wire may be supposed to be formed of a large number of small current elements. Consider a small element CD of length δf at a distance f from M.
Bihar Board 12th Physics Model Question Paper 5 in English Medium 20

\(\text { Let } \angle \mathrm{CPM}=\phi \text { and } \angle \mathrm{CPD}=\delta \phi, \angle \mathrm{PDM}=\theta\) The length δf is very small, so that ∠PCM may also be taken as equal to θ.

The perpendicular dropped from C on PD is CN.

The angle formed between element I \(\overrightarrow{\delta l}\) and \(\overrightarrow{r}\) (= cp is (π – θ), Therefore according to Biot-Savart law, the magnetic field due to current element I \(\overrightarrow{\delta l}\) at P is
Bihar Board 12th Physics Model Question Paper 5 in English Medium 21
Bihar Board 12th Physics Model Question Paper 5 in English Medium 22

Bihar Board 12th Physics Model Question Paper 5 in English Medium

If the wire is of finite length and its ends make angles a and p with line MP, then net magnetic field (B) at P is obtained by summing over magnetic fields due to all current elements, i.e.,
Bihar Board 12th Physics Model Question Paper 5 in English Medium 23

This is expression for magnetic field due to current carrying wire of finite length (or very long), then α = β ⇒ π/2.
Bihar Board 12th Physics Model Question Paper 5 in English Medium 24

Question 23.
Draw the labelled ray diagram for the formation of image by a compound microscope.
Derive an expression for its total magnification (or magnifying power), when the find image is formed at the near point.
Why both objective and eye piece of a compound microscope must have their short focal lengths?
Answer:
Compound Microscope :
It consists of a long cylindrical tube, containing at one end of a convex lens of small aperture and small focal length. This is called the objective lens (O). At the other end of the tube another co¬axial smaller and wide tube is fitted which carries a convex lens (E) at its outer end. This lens is towards the eye and is called the eye-piece. The focal length and aperture of eye piece are somewhat large than those of objective lens. Cross¬wires are mounted at a definite distance before the eye piece. The entire tube can be moved forward and backward by the rack and pinion arrangement.

Bihar Board 12th Physics Model Question Paper 5 in English Medium
Bihar Board 12th Physics Model Question Paper 5 in English Medium 25

Magnifying power of a microscope:
is defined as the ratio of angle ((3) subtended by final image on the eye to the angle (a) subtended by the object on eye, when the object is placed at the least distance of distinct vision, i.e.,
Bihar Board 12th Physics Model Question Paper 5 in English Medium 26

Magnifying power \(M=\frac{\beta}{\alpha}\)

As object is very small, angles α and β are very small and so tan α = α and tan β = β. By  efinition the object AB is placed at the least distance of distinct vision
Bihar Board 12th Physics Model Question Paper 5 in English Medium 27
Bihar Board 12th Physics Model Question Paper 5 in English Medium 28

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Question 24.
State the principle of working of p-n diode as a rectifier. Explain with the help of a circuit diagram, the use of p-n diode as full wave rectifier. Draw a sketch of the input and output wave forms. Or, Draw a circuit diagram of a full wave rectifier. Explain the working principle. Draw the input/output wave forms indicating clearly the functions of the two diodes used.
Answer:
Rectification :
Rectification means conversion of a.c. into d.c. A p-n diode acts as a rectifier because an ac changes polarity periodically and a p-n diode conducts only when it is forward biased; it does not conduct when reverse biased.
Bihar Board 12th Physics Model Question Paper 5 in English Medium 29

In a full wave rectifier, if input frequency is / hertz, then output frequency will be 2/ hertz because for each cycle of input, two positive half cycles of output are obtained.

Working:
The AC input voltage across secondary s1 and s2 cli anges polarity after each half cycle. Suppose during the first half cycle of input AC signal, the terminal s1 is positive relative to centre tap O and s2 is negative relative to O. Then diode D1 is forward biased and diode D2 is reverse biased. Therefore diode D1 conducts while diode D2 does not. The direction of current (i1) due to diode D1 in load rsistance RL is directed from A to 13. In next half cycle, the terminal s is negative and s2 is positive relative to centre tap O.

Bihar Board 12th Physics Model Question Paper 5 in English Medium

The diode D is reverse biased and diode D2 is forward biased. Therefore, diode D2 conducts while D1 does not. The direction of current (i2) due to diode D2 in load resistance RL is still from A to B. Thus the current in load resistance RL is in the same direction for both half cycles of input AC voltage. Thus for input AC signal the output current is a continuous series of unidirectional pulses.
Bihar Board 12th Physics Model Question Paper 5 in English Medium 30

In a full wave rectifier, if input frequency is f hertz, then output frequency will be 2f hertz because for each cycle of input, two positive half cycles of output are obtained.

Bihar Board 12th Physics Model Question Paper 5 in English Medium

Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms

Bihar Board 12th Biology Objective Questions and Answers

Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms

Question 1.
Single-celled animals are said to be immortal because
(a) they grow indefinitely in size
(b) they can tolerate any degree of change in temperature
(c) they can reproduce throughout their life span
(d) they continue to live as their daughter cells.
Answer:
(d) they continue to live as their daughter cells.

Question 2.
Which of the following has the longest life span?
(a) Banyan tree
(b) tortoise
(c) parrot
(d) Elephant
Answer:
(a) Banyan tree

Question 3.
Select the option which arranges the given organisms in ascending order of their life span.
(a) Parrot < Crow < Butterfly < Banyan tree
(b) Butterfly < Crow < Parrot < Crocodile
(c) Fruit fly < Crocodile < Parrot < Banyan tree
(d) Parrot < Tortoise < Dog < Crow
Answer:
(c) Fruit fly < Crocodile < Parrot < Banyan tree

Question 4.
________ is a life process that is not essential for an individual’s survival but for survival of the species.
(a) Growth
(b) Reproduction
(c) Respiration
(d) Nutrition
Answer:
(b) Reproduction

Question 5.
‘Clones’ are individuals that have exactly the same
(a) Lifespan
(b) physiology
(c) growth rate
(d) genetic makeup.
Answer:
(d) genetic makeup.

Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms

Question 6.
Which one of the following processes results in the formation of clone of bacteria?
(a) Regeneration
(b) Budding
(c) Binary fission
(d) Fragmentation
Answer:
(c) Binary fission

Question 7.
Asexual reproduction is seen in members of Kingdom
(a) Monera
(b) Plantae
(c) Animalia
(d) All of these.
Answer:
(d) All of these.

Question 8.
During binary fission in Amoeba which of the following organelles is duplicated?
(a) Plasma membrane
(b) Nucleus
(c) Contractile
(d) All of these
Answer:
(b) Nucleus

Question 9.
Vegetative propagation is the term used for
(a) sexual reproduction in animals
(b) sexual reproduction in plants
(c) asexual reproduction in animals
(d) asexual reproduction in plants.
Answer:
(d) asexual reproduction in plants.

Question 10.
Which of the following is not used for vegetative propagation?
(a) Bud
(b) Bulbil
(c) Turion
(d) Antherozoid
Answer:
(d) Antherozoid

Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms

Question 11.
Identify the given organism and find its maximum life span.
Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms 1
(a) Sparrow, 25 years
(b) Crow, 30 years
(c) Crow, 15 years
(d) Eagle, 40 years
Answer:
(c) Crow, 15 years

Question 12.
Which of the following options shows two plants in which new plantlets arise from the same organ?
(a) Dahlia and ginger
(b) Potato and sweet potato
(c) Dahlia and rose
(d) Potato and sugarcane
Answer:
(d) Potato and sugarcane

Question 13.
Refer to the given figure and identify X in it.
Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms 2
(a) Offset
(b) Eyes
(c) Runner
(d) Bulb
Answer:
(b) Eyes

Question 14.
Fleshy buds produced in the axil of leaves, which grow to form new plants when shed and fall on ground, are called
(a) bulbs
(b) bulbils
(c) tubers
(d) offsets.
Answer:
(b) bulbils

Question 15.
In which one pair, both the plants can be vegetatively propagated by leaf pieces?
(a) Bryophyllum and Kalanchoe
(b) Chrysanthemum and Agave
(c) Agave and Dioscorea
(d) Bryophyllium and Asparagus
Answer:
(a) Bryophyllum and Kalanchoe

Question 16.
Identify the given vegetative propagule.
Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms 3
(a) Bulb
(b) Runner
(c) Rhizome
(d) Bulbil
Answer:
(d) Bulbil

Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms

Question 17.
If a leaf cell of Agave has x chromosomes then what will
be the number of chromosomes in a cell of its bulbil?
(a) 2 x
(b) x/2
(c) x/4
(d) x
Answer:
(d) x

Question 18.
Which of the following cannot serve as a vegetative propagule?
(a) A piece of potato tuber with eyes
(b) A middle piece of sugarcane internode
(c) A piece of ginger rhizome
(d) A marginal piece of Bryophyllum leaf
Answer:
(b) A middle piece of sugarcane internode

Question 19.
Which of the following options correctly identifies artificial and natural methods of vegetative propagation?
Artificial methods – Natural methods
(a) Grafting – Cutting
(b) Layering – Bulbils
(c) Offset – Tissue culture
(d) Tubers – Rhizomes
Answer:
(b) Layering – Bulbils

Question 20.
Sexual reproduction is considered more beneficial than asexual reproduction because
(a) it is not affected by adverse environmental conditions
(b) fertilization is a chance factor
(c) it rapidly multiplies the population
(d) it assists in evolution by producing variations.
Answer:
(d) it assists in evolution by producing variations.

Question 21.
The growth phase of an organism before attaining sexual maturity is referred to as
(a) juvenile phase
(b) vegetative phase
(c) both (a) and (b)
(d) none of these.
Answer:
(c) both (a) and (b)

Question 22.
Select the monocarpic plant out of the following.
(a) Bamboo
(b) Lite hi
(c) Mango
(d) All of these
Answer:
(a) Bamboo

Question 23.
Clear cut vegetative, reproductive and senescent phases cannot be observed in
(a) annual plants
(b) perennial plants
(c) biennial plants
(d) ephemeral plants.
Answer:
(b) perennial plants

Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms

Question 24.
Strobilanthus kunthiana flowers once in
(a) 5 years
(b) 12 years
(c) 20 years
(d) 50 years.
Answer:
(b) 12 years

Question 25.
Strobilanthus kunthiana differs from bamboo in
(a) being monocarpic
(b) length of juvenile phase
(c) being polycarpic
(d) none of these.
Answer:
(b) length of juvenile phase

Question 26.
Oestrous cycle is reported in
(a) cows and sheep
(b) humans and monkeys
(c) chimpanzees and gorillas
(d) none of these.
Answer:
(a) cows and sheep

Question 27.
Which of the following animals show menstrual cycle ?
(a) Gorillas and chimpanzees
(b) Monkeys and humans
(c) Orangutans and monkeys
(d) All of these
Answer:
(d) All of these

Question 28.
Senescent phase of an organism’s life span can be recognised by
(a) slow metabolism
(b) cessation of reproduction
(c) decreased immunity
(d) all of these
Answer:
(d) all of these

Question 29.
If a fungal thallus has both male and female reproductive structures, it will be called
(a) heterothallic
(b) homothallic
(c) dioecious
(d) monoecious
Answer:
(b) homothallic

Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms

Question 30.
Staminate flowers produce
(a) eggs
(b) antherozoids
(c) fruits
(d) all of these
Answer:
(b) antherozoids

Question 31.
Which of the following is a unisexual organisam?
Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms 4
Answer:
Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms 5

Question 32.
Which of the following groups is formed only of the hermaphrodite organisms?
(a) Earthworm, tapeworm, housefly, frog
(b) Earthworm, tapeworm, sea horse, housefly
(c) Earthworm, leech, sponge, roundworm
(d) Earthworm, tapeworm, leech, sponge
Answer:
(d) Earthworm, tapeworm, leech, sponge

Question 33.
Which of the following options shows bisexual animals only?
(a) Amoeba, sponge, leech
(b) Sponge, cockroach, Amoeba
(c) Earthworm, sponge, leech
(d) Tapeworm, earthworm, honeybee
Answer:
(c) Earthworm, sponge, leech

Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms

Question 34.
Read the following statements and select the incorrect one.
(a) Cucurbits and coconuts are monoecious plants.
(b) Papayas and date palms are dioecious plants.
(c) Leeches and tapeworms are bisexual animals.
(d) Sponges and coelenterates are unisexual animals.
Answer:
(d) Sponges and coelenterates are unisexual animals.

Question 35.
Meiosis does not occur in
(a) asexually reproducing diploid individuals
(b) sexually reproducing haploid individuals
(c) sexually reproducing diploid individuals
(d) all of these.
Answer:
(a) asexually reproducing diploid individuals

Question 36.
A diploid parent plant body produces ________ gametes and a haploid parent plant body produces ________ gametes.
(a) diploid, haploid
(b) haploid, diploid
(c) diploid, diploid
(d) haploid, haploid
Answer:
(d) haploid, haploid

Question 37.
Which of the following organisms has the highest number of chromosomes?
(a) Housefly
(b) Butterfly
(c) Ophioglossum
(d) Onion
Answer:
(c) Ophioglossum

Question 38.
In maize, a meiocyte has 20 chromosomes. What will be the number of chromosomes in its somatic cell?
(a) 40
(b) 30
(c) 20
(d) 10
Answer:
(c) 20

Question 39.
If a butterfly has chromosome number 360 in its meiocyte (2n). What will be the chromosome number in its gametes?
(a) 380
(b) 190
(c) 95
(d) 760
Answer:
(b) 190

Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms

Question 40.
In flowering plants, both male and female gametes are non-motile. The method to bring them together for fertilisation is
(a) water
(b) air
(c) pollination
(d) apomixis
Answer:
(c) pollination

Question 41.
Development of new individual from female gamete without fertilisation is termed as
(a) syngamy
(b) embryogenesis
(c) oogamy
(d) parthenogenesis.
Answer:
(d) parthenogenesis.

Question 42.
Fertilisation cannot occur in absence of surface water in
(a) Fucus
(b) Funaria
(c) Marsilea
(d) all of these.
Answer:
(d) all of these.

Question 43.
Spirogyra is a sexually reproducing alga in which vegetative thallus is haploid. In Spirogyra, meiosis
(a) never occurs
(b) occurs at time of gamete production
(c) occurs after fertilisation
(d) occurs during vegetative growth.
Answer:
(c) occurs after fertilisation

Question 44.
Life begin in all sexually reproducing organisms as a
(a) single-celled zygote
(b) double-celled zygote
(c) haploid zygote
(d) haploid gametes.
Answer:
(a) single-celled zygote

Question 45.
Which of the following is not correct regarding sexual reproduction ?
(a) It is usually biparental.
(b) Gametes are always formed.
(c) It is a slow process
(d) It involves only mitosis.
Answer:
(a) It is usually biparental.

Question 46.
Offsprings of oviparous animals are at greater risk of survival as compared to those of viviparous animals because
(a) proper embryonic care and protection is absent
(b) embryo does not develop completely
(c) progenies are of smaller size
(d) genetic variations do not occur.
Answer:
(a) proper embryonic care and protection is absent

Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms

Question 47.
Deposition of calcareous shell around zygote occurs in
(a) birds and reptiles
(b) birds and mammals
(c) mammals and reptiles
(d) all of these.
Answer:
(a) birds and reptiles

Question 48.
Select the option which shows viviparous animals only,
(a) Lizard, Turtile
(b) Platypus, Crocodile
(c) Cow, Crocodile
(d) Whale, Mouse
Answer:
(d) Whale, Mouse

Question 49.
Which of the following animals give birth to young ones?
(a) Ornithorhynchus and Echidna
(b) Macropus and Pteropus
(c) Balaenoptera and Homo sapiens
(d) Both (a) and (c)
Answer:
(d) Both (a) and (c)

Question 50.
Viviparity is found in
(a) Sharks
(b) lizards
(c) frogs
(d) birds
Answer:
(a) Sharks

Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms

Question 51.
In which of the following plants, sepals do not fall off after fertilisation and remain attached to the fruit?
(a) Brinjal
(b) Cucumber
(c) Papaya
(d) Bitter gourd
Answer:
(a) Brinjal

Question 52.
Which of the labelled parts in the transverse section of tomato fruit, is/are diploid?
Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms 6
(a) X
(b) Y
(c) Both X and Y
(d) None of these
Answer:
(c) Both X and Y

Question 53.
The wall of the ovary forms
(a) pericarp
(b) fruit wall
(c) fruit
(d) both (a) and (b).
Answer:
(d) both (a) and (b).

Question 54.
The term ‘clone’ cannot be applied to offspring formed by sexual reproduction because
(a) offspring do not possess exact copies of parental DNA
(b) DNA of only one parent is copied and passed on to the offspring
(c) offspring are formed at different times
(d) DNA of parent and offspring are completely different
Answer:
(a) offspring do not possess exact copies of parental DNA

Question 55.
The male gametes of rice plant have 12 chromosomes in their nucleus. The chromosome number in the female gamete, zygote and the cells of the seedling will be, respectively
(a) 12,24,12
(b) 24,12,12
(c) 12, 24, 24
(d) 24, 12, 24.
Answer:
(c) 12, 24, 24

Question 56.
Appearance of vegetative propagules from the nodes of plants such as sugarcane and ginger is mainly because
(a) nodes are shorter than intemodes
(b) nodes have meristematic cells
(c) nodes are located near the soil
(d) nodes have non-photosynthetic cells.
Answer:
(b) nodes have meristematic cells

Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms

Question 57.
There is no natural death in single celled organisms like Amoeba and bacteria because
(a) they cannot reproduce sexually
(b) they reproduce be binary fission
(c) parental body is distributed among the offspring
(d) they are microscopic.
Answer:
(c) parental body is distributed among the offspring

Question 58.
There are various types of reproduction. The type of reproduction adopted by an organism depends on
(a) the habitat and morphology of the organism
(b) morphology of the organism
(c) morphology and physiology of the organism
(d) the organisms habitat, physiology and genetic makeup.
Answer:
(d) the organisms habitat, physiology and genetic makeup.

Question 59.
Which of the following is a post-fertilisation event in flowering plants?
(a) Transfer of pollen grains
(b) Embryo development
(c) Formation of flower
(d) Formation of pollen grains
Answer:
(b) Embryo development

Question 60.
The number of chromosomes in the shoot tip cells of a maize plant is 20. The number of chromosomes in the microspore mother cells of the same plant shall be
(a) 20
(b) 10
(c) 40
(d) 15
Answer:
(a) 20

Bihar Board 12th Biology Objective Answers Chapter 1 Reproduction in Organisms

Bihar Board 12th Biology Model Question Paper 5 in English Medium

Bihar Board 12th Biology Model Papers

Bihar Board 12th Biology Model Question Paper 5 in English Medium

Time : 3 Hours 15 Min
Total Marks : 70

Instructions for the candidates:

  1. Candidates are required to give answers in their own words as far as practicable.
  2. Figures in the right-hand margin indicate full marks.
  3. While answering the questions, the candidate should adhere to the word limit as for as practicable.
  4. 15 Minutes of extra time has been allotted for the candidates to read the questions carefully.
  5. This question paper is divided into two sections: Section – A and Section – B
  6. In Section – A, there are 35 objective type questions which are compulsory, each carrying 1 mark. Darken the circle with blue/black ball pen against the correct option on OMR Sheet provided to you. Do not use Whitener/Liquid/ Blade/Nail on OMR Sheet otherwise result will be treated as invalid.
  7. In Section – B, there are Non-objective type questions. There are 18 Short answer type questions, out of which any 10 questions are to be answered. Each question carries 2 marks. Apart from this, there are 6 long answer type questions, out of which any 3 of them are to be answered. Each question carries 5 marks
  8. Use of any electronic device is prohibited.

Objective Type Questions

There are 1 to 35 objective type questions with 4 options. Choose the correct option which is to be answered on OMR Sheet. (35 x 1 = 35)

Question 1.
Pollination by birds is called
(a) Entomophily
(b) Cheiropterophily
(c) Ornithophily
(d) All of the above
Answer:
(c) Ornithophily

Question 2.
Which one is the hotspot of biodiversity?
(a) Eastern Ghat
(b) Western Ghat
(c) Aravalli Hills
(d) None of the above
Answer:
(b) Western Ghat

Bihar Board 12th Biology Model Question Paper 5 in English Medium

Question 3.
Who is considered as Father of Genetics?
(a) Morgan
(b) Darwin
(e) Hugo-de-Vries
(d) Mendel
Answer:
(d) Mendel

Question 4.
Noise pollution is measured in
(a) Heartz
(b) Fathoms
(c) Decibels
(d) Nanometer
Answer:
(c) Decibels

Question 5.
Indicator of water pollution is
(a) Entamoeba histolytica
(b) E. Coli
(c) Vibrio cholera
(d) All of the above
Answer:
(b) E. Coli

Question 6.
mRNA formation takes place in
(a) Ribosome
(b) Nucleus
(c) Cytoplasm
(d) Mitochondria
Answer:
(b) Nucleus

Question 7.
Cancer affecting connective tissue is called
(a) Lymphoma
(b) Sarcoma
(c) Carcinoma
(d) None of the above
Answer:
(b) Sarcoma

Question 8.
IgM antibody is found in
(a) Serum
(b) Saliva
(c) Blood
(d) All of the above
Answer:
(c) Blood

Question 9.
How many Peptide chains are found in each antibody molecule?
(a) 4
(b) 3
(c) 2
(d) None of the above
Answer:
(a) 4

Question 10.
Green plants are known as producers, which convert
(a) Chemical energy into light energy.
(b) Light energy into chemical energy
(c) All of the above
(d) None of the above
Answer:
(b) Light energy into chemical energy

Bihar Board 12th Biology Model Question Paper 5 in English Medium

Question 11.
Which of the following cry gene prevents crop from borer
(a) Cry AC
(b) Cry / Ab
(c) Cry // Ab
(d) All of the above
Answer:
(d) All of the above

Question 12.
Human blood groups are
(a) A, B, AB, O
(b) A, B, C, O
(c) B, C, O
(d) None of the above
Answer:
(a) A, B, AB, O

Question 13.
Khorana got Nobel prize for
(a) Discovery of RNA
(b) Discovery of DNA
(c) Chemical synthesis of gene
(d) None ‘
Answer:
(c) Chemical synthesis of gene

Question 14.
Secondary pollutant is
(a) CO
(b) C02
(c) PAN
(d) None of these
Answer:
(c) PAN

Question 15.
Chipko movement is launched for protection of
(a) Grass land
(b) Forest
(c) Animal Community
(d) All of the above
Answer:
(b) Forest

Question 16.
TTxttis
(a) Test cross
(b) Back cross
(c) Hybridization
(d) None of the above
Answer:
(a) Test cross

Question 17.
How many types of DNA polymerases are associated with eukaryotic cell ?
(a) 2
(b) 3
(c) 4
(d) 5
Answer:
(d) 5

Question 18.
Example of In Situ conservation is
(a) Zoological garden
(b) Botanical garden
(c) Biological safari park
(d) All of the above
Answer:
(d) All of the above

Bihar Board 12th Biology Model Question Paper 5 in English Medium

Question 19.
Which of the following is diploid ?
(a) Male gamete
(b) Ovum
(c) Zygote
(d) All of the above
Answer:
(c) Zygote

Question 20.
Pattern of any population depends on
(a) Density
(b) Distribution
(c) Specific structure
(d) All of the above
Answer:
(d) All of the above

Question 21.
Montreal Protocol is related to control the deleterious effect of
(a) Acid rain
(b) Ozone depletion
(c) Deforestation
(d) Global warming
Answer:
(b) Ozone depletion

Question 22.
Fertilization takes place in
(a) Ovary
(b) Uterus
(c) Fallopian tube
(d) All of the above
Answer:
(c) Fallopian tube

Question 23.
Hugo de-Vries worked on which plant ?
(a) Pea
(b) Evening Primrose
(c) Both
(d) None
Answer:
(b) Evening Primrose

Question 24.
Salmonella is associated with
(a) Polio
(b) T.B,
(c) Typhoid
(d) All of the above
Answer:
(c) Typhoid

Question 25.
AIDS is identified first of all in
(a) USA
(b) France
(c) Russia
(d) All of the above
Answer:
(a) USA

Question 26.
Bones of fore limbs of Bat, and humans are
(a) Homologous
(b) Analogous
(c) Both
(d) None
Answer:
(a) Homologous

Bihar Board 12th Biology Model Question Paper 5 in English Medium

Question 27.
Which enzyme is used to join cut ends of DNA?
(a) Ligase
(b) Cellulose
(c) Pectinase
(d) None of the above
Answer:
(a) Ligase

Question 28.
Which of the following serve as biofertilizer in paddy fields?
(a) Yeast
(b) Bacteria
(c) Cyano bacteria
(d) Fungi
Answer:
(c) Cyano bacteria

Question 29.
Which of the following is used in preparing Cheese?
(a) Viruses
(b) Algae
(c) Fungi
(d) Micorobes
Answer:
(d) Micorobes

Question 30.
Statins used for lowering blood cholesterol level
are extracted from
(a) Yeast
(b) Algae
(c) Virus
(d) All of the above
Answer:
(a) Yeast

Question 31.
Microbes are found in
(a) air
(b) water
(c) soil
(d) All of the above
Answer:
(d) All of the above

Question 32.
Ranikhet disease is connected with
(a) Pigs
(b) Cow
(c) Fish
(d) Hens
Answer:
(d) Hens

Question 33.
Induced breeding is done in case of
(a) Apiculture
(b) Pisci culture
(c) Lac culture
(d) Sericulture
Answer:
(b) Pisci culture

Question 34.
Taichung Native-1 is a variety of
(a) Rice
(b) Wheat
(c) Maize
(d) None
Answer:
(a) Rice

Bihar Board 12th Biology Model Question Paper 5 in English Medium

Question 35.
Zeba cattle is
(a) Goat
(b) Cat
(c) Cow
(d) Sheep
Answer:
(c) Cow

Non-Objective Type Questions

Short Answer Type Questions

In this section, there are 18 short answer type question (each carryies 2 marks) out of which answers any ten (10) questions. (10 x 2 = 20)

Question 1.
What is co-dominance? Explain with example.
Answer:
In co-dominance both dominant alleles of a gene express themselves equally in F, hybrids. The phenotype ratio matches with genotypic ratio i.e, 1: 2: 1 in F2 generation of offspring. Example of co-dominance can be seen in goat colour in
Bihar Board 12th Biology Model Question Paper 5 in English Medium 1

Question 2.
What is significance of double fertilization?
Answer:
Significance of double fertilization:
(i) Double fertilization is very important in angiospermic plants. If only syngamy occurs in plants and triple fusion does not occur, only 3 zygote will be formed. Endosperm will not be formed and this will result seed with undeveloped embryo or seed without embryo.

(ii) Endosperm is formed due to double fertilization. This provides nutrition to embryo and it contains maternal and paternal chromosomes. A body shows physiological aggressiveness due to hybrid vigour in inner endospermic cells.

Question 3.
What is radio-active pollution? What are the sources of radio-active pollution?
Answer:
Radio-active Pollution: Certain elements such as Radium, Thorium, Uranium emit protons (Alpha particles), electrons (Beta particles) and Gamma particles by disintegration of atomic nuclei. This phenomenon is called radio-activity and these elements are known as radio-active. When the radio-active radiations contaminate to water, air, soil and food materials it is called radio-active pollution.

Bihar Board 12th Biology Model Question Paper 5 in English Medium

Question 4.
Define Commensalism and Parasitism.
Answer:
Commensalism: An interaction between two species in which one is benefitted and the other one is neither harmed nor benefitted.
e.g. Orchids growing on trunk/branch of a tree.

Parasitism: An interaction between two species where parasite not only obtains food from its host but also completes its life cycle on the host. e.g. Bacteria, Fungi etc.

Question 5.
What are the ways for controlling amoebiosis?
Answer:
Amoebiosis is caused by a protozoan parasite Entamoeba histolytica, in which pain in stomach and stool with mucus and blood are seen as specific symptom.
Following are the control major of amoebiosis:

  1. Patient should take rest and after some interval electrolytic fluid must be taken.
  2. For control of disease, emetin, vioform, chinoform and diodoquin should be taken as drug and antibiotics like Terramycine, Erythromycine, Metronidazole and Aureomycin may be helpful in treatment and control of this disease.

Question 6.
What is Jumping Gene (Transposons)?
Answer:
These are capable of changing their locations from one place to another, so it is called jumping genes. It is a mobile fragment of DNA that can change position in a genome, a cause of sequence insertions and deletions in some organisms.

Question 7.
Name four living fossils.
Answer:
A living fossil is a living animal of ancient origin with many primitive characters. A living fossil has been living as such from the time of origin without many changes.
Examples are:

  • Peripatus of phylum Arthropoda.
  • Limulus of phylum Arthropoda.
  • Latimeria-a bony fish.
  • Sphenodon-a reptile.

Bihar Board 12th Biology Model Question Paper 5 in English Medium

Question 8.
Write any four benefits of micro-propagation.
Answer:
Benefits of micro-propagation:

  • By such method crop production increases.
  • By such method storage of germplasm can be taken place.
  • By Meristem tip culture method disease resistant plants are produced.
  • Micropropagation is also beneficial in conservation of biodiversity.

Question 9.
What is fishery? Name few common freshwater and marine edible fishes.
Answer:
Fishery: It is an industry concerned with catching, processing or selling of fish, shell fish or other aquatic animals.
Freshwater edible fishes:

  • Catla
  • Rohu
  • Cirrhina mrigala.

Marine water edible fishes: (a) Hilsa (b) Sardines (c) Mackerel (d) Pomfrets.

Question 10.
Write short notes on gene cloning.
Answer:
The production of living structures genetically identical to their parent structure is known as gene cloning. It is therefore an exact copy of a single living parent. Gene cloning is the act of making copies of single gene. Once a gene is identified clones can be used.

Question 11.
Why is the Human Genome Project called a megaproject?
Answer:
Human Genome Project is called a mega project because it is aimed to sequence every base in human genome. It has developed the ways of mapping the human genome at increasing fine level of precision and to store this information in database and develops tools for data analysis. The magnitude and the requirements for this project are more for opening up new areas and avenues.

Question 12.
What are the functions of t-RNA in the protein synthesis?
Answer:

  1. It carries specific amino acids from the cytoplasm to the ribosomal sites for the formation of polypeptide chain according with the sequence specified by m-RNA.
  2. The t-RNA charged with the amino acid serves as a adaptor molecule to decode the information on the m- RNA.
  3. It comes to elongate the polypeptide chain by the addition of several newly synthesised amino acids.

Question 13.
Define homologous orgAnswer: Give examples.
Answer:
These are the organs of similar structure and origin but dissimilar in functions and form.This is due to common ancestary.
Examples:
(i) The forelimbs of a frog, the wings of a bird, legs of a horse, the hands of a man and the flipper of a whale are homologous organs because all of them have similar pattern of basic plan (pentadacty) i.e. same number of bones, muscles, nerves and blood vessels etc. but they do the different functions such as hopping (frog), flying (bird), running (horse), graping (man) and swimming (whale).

(ii) Phylloclade of Opuntia and Cladode of Ruscus are homologous organs as both are modified stems. Similarly, a thorn of Bougainvillea and a tendril of Cucurbita are homologous as both arise in axillary position.

Bihar Board 12th Biology Model Question Paper 5 in English Medium

Question 14.
What is green revolution? List two factors that have led green revolution in India.
Answer: Green revolution is the enormous increase in the food production due to intensive cultivation by use of improved varieties of seeds and fertilizers.
The factors that contributed to the green revolution in India are:

  • The development and introduction of high yielding varieties of crop and extension of the high yielding varieties over large area in the country.
  • Transfer of technology of scientific farming from research farm to village farmers.

Question 15.
What do you understand by restriction enzyme?
Answer:
Restriction enzymes: These enzymes are nucleases which cut DNA into short pieces containing identifiable genes at specific sites. These pieces are then introduced into plastids, yeasts or plant cells.
Ex. ECORI, Hind-III.

Question 16.
Write short notes on plasmids.
Answer:
A plasmid is small circular double stranded DNA molecule that is distinct from a cell, chromosomal DNA.
Plasmids naturally exist in bacterial cells and they also occur in some eukaryotes. Often, the genes carried in plasmid provide bacteria with genetic advantage, such as antibiotic resistance.

Question 17.
Write short notes on organic evolution.
Answer:
The process by which changes in the genetic composition of populations of organism occur in response to environmental changes is known as organic evolution. Examples of organic evolution include organs that are different in structure but perform similar function. A Dolphin’s flipper’ and human arms are example of organic evolution.

Question 18.
Discuss the concept of IPM.
Answer:
Integrated Pest Management (IPM) aims at minimum use of pesticides to prevent agro-chemical pollution and to adopt natural methods of pest control as far as possible. The natural methods of pest control are the part of a larger agricultural strategy and these include:

  1. Use of resistant varieties of crop to local pests.
  2. To carry the practice of crop rotation and improved sanitation method.
  3. To adopt biological control method and starvation method.
  4. To grow planting or a preferred target crop to lure away insects.
  5. Use of sterilization strategy, mechanical control, repellents, chemical attractants and natural insecticides etc.

Bihar Board 12th Biology Model Question Paper 5 in English Medium

Long Answer Type Questions

There are 6 long answers type question (each carrying 05 marks) out of which answers any three questions. (5 x 3 = 15)

Question 19.
Discuss the characters chosen by Mendel in garden pea. Mention the advantages of selecting this plant for experiment.
Answer:
Gregor Mendel, conducted hybridisation experiments on garden peas for seven years (1856-1863) and proposed the laws of inheritance. During Mendel’s investigations into inheritance patterns it was for the first time that statistical analysis and mathematical logic were applied to problems in biology. His experiments had a large sampling size, which have greater credibility to the data

that he collected. Also, the confirmation of his inferences from experiments on successive generations of his test plants, proved that his results pointed to general rules of inheritance rather than being unsubstantiated ideas. Mendel selected only pea plants for his experiment due to presence of many types of contrasting characters like:

  • Round and wrinkled seeds
  • Yellow and green seeds
  • Violet and white flowers
  • Inflated and constricted pods
  • Green and yellow pods
  • Axillary and terminal flowers
  • Tall and dwarf plants

Mendel investigated characters in the garden pea plants that were manifested as two opposite traits which allowed him to set up a basic frame work of rules governing inheritance. Mendel conducted such artificial pollination/ cross pollination experiments using several true breeding pea lines.

Advantages of selecting pea plants for experiment by Mendel:

  1. Due to short height of pea plants, it was easy to do experiment on that.
  2. Pea plants had a short life cycle so that results could be had within a year.
  3. Pea plants produced many seeds in one generation which helped in drawing correct conclusions.
  4. Artificial cross-pollination could be easily achieved because androecium and gynoecium were completely enclosed.
  5. Pea plants having each of the seven characters he selected were readily available.
  6. Mendel took only one character at one time for his experiment.
  7. Pea plants are self pollinated and pure.

Question 20.
Give an accout of Neo-Darwinism/Modern concept of evolution.
Answer:
Neo-Darwinism is the improvement of Darwin’s orginal theory of Natural Selection in order to remove its defects.
Important mechanisms for Neo-Darwinism are:
(a) Variations (b) Natural selection (c) Isolation

(a) Variations: Variations which influence evolution are the ones that develop in the genetic machinery of the germ cells. They are formed due to Mutations, Recombinations, Migrations, Hybridisation and Genetic Drift.

(b) Natural Selection: It operates through differential reproduction. Individuals with advantageous variations survives, reach maturity and leave there genes in the gene pool through differential reproduction. Repeated reproductive selection of individuals with specific traits increases the frequency of their genes in the gene pool. Individuals with harmful neutral variations are eliminated at various stages.

(c) Isolation: It is the separation of a segment of population from the rest due to apearance of a barrier. Gene pool of the isolated population changes due to genetic drift and accumulation of different types of reproduction.

Question 21.
Give a labelled diagram of the electron microscopic view of a human sperm and describe it briefly.
Answer:
The human sperm is a microscopic, long, flagellated and haploid motile cell and is formed of head, neck, middle piece and tail.

(i) Head: It constitutes the anterior region of sperm containing nucleus and acrosome. The nucleus is a narrow, flat and oval structure consisting of densely packed nuclear chromatin material. The latter is formed of DNA and nucleo protein. A small pointed sheathy acrosome is found at the anterior region of head and is derived from the golgi bodies. It contains hydrolytic enzyme-hyalourinidase which helps the sperm to penetrate into ovum during fertilization by dispersing the cells of corona radiata.

Bihar Board 12th Biology Model Question Paper 5 in English Medium 2

(ii) Neck: It is very short or indistinguishable region lying in between head and middle piece. It contains the proximal and distal centriole with 9 + 0 arrangement of micro-tubules. The proximal centriole forms the spindle in the first cleavage divison of the fertilised ovum. The distal centriole gives rise to many fine micro-tubules which run upto sperm tail by passing through middle piece.

(iii) Middle piece: It is a cylindrical region lying behind the neck. It contains number of mitochondrial spiral (nebenkern) which encircles the axial fdament arising from distal centriole. The mitochondrial spiral contains the oxidative enzymes which provide energy for movement of sperm by the process called oxidative phosphorylations.

(iv) Tail: It is the longest part of the sperm and is formed of main central axial filament and the outer protoplasmic sheath with small amount of cytoplasm. At the posterior end of tail, the axial filament is naked without any sheath and is called as end piece. The tail undulates rapidly and provides mobility to the sperm with the head forward in the fluid medium.

Bihar Board 12th Biology Model Question Paper 5 in English Medium

Question 22.
What is deforestation? Write its causes and effects.
Answer:
Deforestation is the conversion of forest areas to non-forest ones. It is a serious threat to the quality of life, national economy and future of environment. According to an estimate, almost 40>percent forests have been lost in the tropics, compared to only one percent in the temperate region. The present-scenario of deforestation is particularly grim in India.

The main cause of decrease in forest cover in India is deforestation due to expansion of agriculture, urbanization, industrialization, excessive commercial use of timber, fuel, wood etc. The causes of deforestation are population explosion, fires, pests, grazing and gnawing mammals, weather, jhum cultivation, etc.

Effects of deforestation are as follows:

  1. Soil erosion has increased;
  2. Flood and droughts have become more frequent;
  3. Pattern of rain fall is changing;
  4. Land slides and avalanches are on the increase;
  5. Climate has become warmer;
  6. Forest dwilling species are becoming extinct;
  7. Consumption of CO2 and production of O2 are getting adversely affected.

Question 23.
Give an account of Apiculture.
Answer:
The maintenance of hives of honey bees for the production of honey is called bee keeping or apiculture.
Bee keeping is a small scale industry for the production of honey which have following economic importance:

  • Bee keeping gives honey which is an important nutritive substance.
  • Bee-hives gives bee-wax which is utilized in making polishes.
  • Bee keeping helps in pollination of various crops useful for mankind

Question 24.
Write short notes on Homology and Analogy organ, vestigial organ, Atavism and Connecting links.
Answer:
(i) Homology and Analogy: The organs of similar structure and origin but dissimilar in functions and forms are called as homologous organs and this phenomenon is called homology. The presence of homologous organs implies a common evolutionary origin of amphibians, reptiles, birds and mammals from some ancient fish ancestor. The homologous structures seen in successive generations indicate actual relationship and the possessors are the diverse descendants of common ancestry (Divergent evolution).

The organs that perform the same function but differ in their origin and structure, are called as analogous organs and the phenomenon is called analogy. The wings of an insect are analogous to those of birds and bats because they perform the same function but have dissimilar structure and origin. The wings of an insect are modified outgrowth of the body wall whereas wings of birds and bats are forelimbs.

These organs have arisen in evolutionary process through adaptation of quite different organisms to a similar mode of life (Convergent evolution). On the same line, the similarities in proteins are genes performing a given function among diverse organisms give clues to common ancestry. These biochemical similarities point to the same shared ancestry as structural similiarities among diverse organisms.

(ii) Vestigial organs: These are the reduced and functionless organs which are of no use to the possessor but they still persists generation after generation in reduced form in an individual. They were complete and functional in the ancestors e.g. appendix in man is considered as the remnant of large intestine (caecum) but it is considered to be storage organ for cellulose digestion in herbivorous mammals. The vestigial organs which used to perform a normal function in the ancestor but during the course of evolution, they have been reduced to vestiges.

(iii) Atavism: It is reappearance of ancestral characters other than parents in the newly born offspring, which have either completely disappeared or reduced. The reappearance of short tail in some babies, multiple mammals in some individuals and dense hairy body etc. are the examples of atavism. The reappearance of such ancestral characters favour evolution.

(iv) Connecting links: The organisms which possess the characters of two different groups of organisms are known as connecting links e.g., duckbilled platypus and spiny ant-eater serve as a connecting link between the mammals and reptiles. Similarly lung fishes (Protopterus) is a connecting link between fishes and amphibians.

Bihar Board 12th Biology Model Question Paper 5 in English Medium

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State

Bihar Board 12th Chemistry Objective Questions and Answers

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State

Question 1.
Which among the following will show anisotropy ?
(a) Glass
(b) NaBr
(c) Plastic
(d) Rubber
Answer:
(b) NaBr

Question 2.
Which of the following forms a molecular solid when solidified ?
(a) Calcium fluoride
(b) Silicon dioxide
(c) Carbon dioxide
(d) Sodium chloride
Answer:
(c) Carbon dioxide

Question 3.
The major binding force in diamond, silicon and quartz is ……………
(a) electrostatic force
(b) electrical attraction
(c) covalent bond force
(d) van der Waals force
Answer:
(c) covalent bond force

Question 4.
Solid X is a very hard solid which is electrical insulator in solid as well as in molten state and has extremely high melting point. What type of solid is it ?
(a) Ionic solid
(b) Covalent solid
(c) Metallic solid
(d) Molecular solid
Answer:
(b) Covalent solid

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State

Question 5.
Examples of few solids are given below. Find out the example which is not correctly matched.
(a) Ionic solids – NaCl, ZnS
(b) Covalent solids – H2,l2
(c) Molecular solids – H2O(s)
(d) Metallic solids – Cu, Sn
Answer:
(b) Covalent solids – H2,l2

Question 6.
Which of the following solids is the structure of CsCl crystal ?
(a) Body centred cubic
(b) Simple cubic
(c) Face centred cubic
(d) Edge centred cubic
Answer:
(a) Body centred cubic

Question 7.
Which of the following does not represent a type of crystal system ?
(a) Triclinic
(b) Monoclinic
(c) Rhombohedral
(d) Isotropical
Answer:
(d) Isotropical

Question 8.
Which of the following primitive cells show the given parameters ?
a # b # c, α = β = Y = 90°
(a) Cubic
(b) Tetragonal
(c) Orthorhombic
(d) Hexagonal
Answer:
(c) Orthorhombic

Question 9.
Which type of crystals contains more than one Bravais lattice ?
(a) Hexagonal
(b) Triclinic
(c) Rhombohedral
(d) Monoclinic
Answer:
(d) Monoclinic

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State

Question 10.
For the structure given below the site marked as S is a ……………
(a) tetrahedral void
(b) cubic void
(c) octahedral void
(d) none of these

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State
Answer:
(c) octahedral void

Question 11.
A metal crystallises into a lattice containing a sequence of layers as AB AB AB………………….. What percentage of voids are left in the lattice ?
(a) 72%
(b) 48%
(c) 26%
(d) 32%
Answer:
(c) 26%

Question 12.
In ccp arrangement the pattern of successive layers can be designated as …………
(a) AB AB AB
(b) ABC ABC ABC
(c) AB ABC AB
(d)  ABA ABA ABA
Answer:
(b) ABC ABC ABC

Question 13.
The coordination number of metal crystallising in a hexagonal close packing is ………
(a) 12
(b) 4
(c) 8
(d) 6
Answer:
(a) 12

Question 14.
A crystalline structure has radius ratio (r, / r) in the range of 0.225 – 0.414. The coordination number and arrangement of anions around the cations are ………..
(a) 3, plane triangular
(b) 6, octahedral
(c) 4, tetrahedral
(d) 8, cubic
Answer:
(c) 4, tetrahedral

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State

Question 15.
A crystal lattice with alternative +ve and -ve ions has radius ratio 0.524. The coordination number of lattice is …………
(a) 4
(b) 6
(c) 8
(d) 12
Answer:
(b) 6

Question 16.
A solid AB has a rock salt structure. If radius of cation A+ is 120 pm, what is the minimum value of radius of B+anion (a) 120 pm
(b) 240 pm
(c) 290 pm
(d) 360 pm
Answer:
(c) 290 pm
Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State 2
Question 17.
How many chloride ions are surrounding sodium ion in sodium chloride crystal ?
(a) 4
(b) 8
(c) 6
(d) 12
Answer:
(c) 6

Question 18.
In NaCl structure, ……………
(a) all octahedral and tetrahedral sites are occupied
(b) only octahedral sites are occupied
(c) only tetrahedral sites are occupied
(d) neither octahedral nor tetrahedral sites are occupied.
Answer:
(b) only octahedral sites are occupied

Question 19.
NaCl type crystal (with coordination no. 6 : 6) can be converted into CsCl type crystal (with coordination no. 8 : 8) by applying ……
(a) high temperature
(b) high pressure
(c) high temperature and high pressure
(d) low temperature and low pressure.
Answer:
(b) high pressure

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State

Question 20.
Coordination numbers of Cs+ and Cl in CsCl crystal are ………….
(a) 8, 8
(b) 4,4
(c) 6,6
(d) 8,4
Answer:
(a) 8, 8

Question 21.
A unit cell of BaCl2 (fluorite structure) is made up of ………..
(a) four Ba2+ ions and four Cl ions
(b) four Ba2+ ions and eight Cl ions
(c) eight Ba2+ ions and four Cl ions
(d) four Ba2+ ions and six Cl
Answer:
(c) eight Ba2+ ions and four Cl ions

Question 22.
In face centred cubic unit cell, edge length is …………..
(a) \(\frac{4}{\sqrt{3}} \mathrm{r}\)
(b) \(\frac{4}{\sqrt{2}} \mathrm{r}\)
(c) 2r
(d) \(\frac{\sqrt{3}}{2} \mathrm{r}\)
Answer:
(b) \(\frac{4}{\sqrt{2}} \mathrm{r}\)

Question 23.
The edge length of fee cell is 508 pm. If radius of cation is 110 pm, the radius of anion is …………
(a) 110 pm
(b) 220 pm
(c) 285 pm
(d) 144 pm
Answer:
(d) 144 pm
Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State 3

Question 24.
The edge length of sodium chloride unit cell is 564 pm. If the size of Cl ion is 181 pm. The size of Na+ ion will be …….
(a) 101 pm
(b) 181 pm
(c) 410 pm
(d) 202 pm
Answer:
(a) 101 pm

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State

Question 25.
The radii of Na+ and Cl ions are 95 pm and 181 pm respectively. The edge length of NaCl unit cell is ………..
(a) 276 pm
(b) 138 pm
(c) 552 pm
(d) 415 pm
Answer:
(c) 552 pm

Question 26.
Copper crystallises in fee with a unit cell length of 361 pm. What is the radius of copper atom ?
(a) 157 pm
(b) 181 pm
(c) 127 pm
(d) 108 pm
Answer:
(c) 127 pm

Question 27.
Total volume of atoms present in a fee unit cell of a metal with radius r is …………
(a) \(\frac{12}{3} \pi r^{2}\)
(b) \(\frac{16}{3} \pi r^{3}\)
(c) \(\frac{20}{3} \pi r^{3}\)
(d) \(\frac{24}{3} \pi r^{3}\)
Answer:
(b) \(\frac{16}{3} \pi r^{3}\)

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State 4

Question 28.
Relationship between atomic radius and the edge length a of a body-centred cubic unit cell is ……..
(a) r = a/2
(b) \(r=\sqrt{a / 2}\)
(c) \(r=\frac{\sqrt{3}}{4} a\)
(d) \(r=\frac{3 a}{2}\)
Answer:
(c) \(r=\frac{\sqrt{3}}{4} a\)
Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State 5

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State 6
Question 29.
Edge length of a unit cell of chromium metal is 287 pm with bcc arrangement. The atomic radius is of the order
(a) 124.27 pm
(b) 287 pm
(c) 574 pm
(d) 143.5 pm
Answer:
(a) 124.27 pm
Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State 8

Question 30.
The fraction of the total volume occupied by the atoms present in a simple cube is ………….
(a) \(\frac{\pi}{4}\)
(b) \(\frac{\pi}{6}\)
(c) \(\frac{\pi}{3 \sqrt{2}}\)
(d) \(\frac{\pi}{4 \sqrt{2}}\)
Answer:
(b) \(\frac{\pi}{6}\)

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State

Question 31.
A unit cell of sodium chloride has four formula units. The edge length of the unit cell is 0.564 nm. What is the density of sodium chloride ?
(a) 3.89 g cm-3
(b) 2.16 gem-3
(c) 3 g cm-3
(d) 1.82 g cm-3
Answer:
(b) 2.16 gem-3

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State 9

Question 32.
The distance between Na+ & Cl ions in NaCl with a density 3.165 g cm-3 is …………..
(a) 497 pm
(b) 248.5 pm
(c) 234 pm
(d) 538.5 pm
Answer:
(b) 248.5 pm
Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State 10

Question 33.
How many lithium atoms are present in a unit cell with edge length 3.5A and density 0.53 g cm-3 ?
(a) 2
(b) 1
(c) 4
(d) 6
Answer:
(a) 2
Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State 11

Question 34.
Alkali halides do not show Frenkel defect because …………….
(a) cations and anions have almost equal size
(b) there is a large difference in size of cations and anions
(c) cations and anions have low coordination number
(d) anions cannot be accommodated in voids.
Answer:
(a) cations and anions have almost equal size

Question 35.
Which of the following crystals does not exhibit Frenkel defect ?
(a) AgBr
(b) AgCl
(c) KBr
(d) ZnS
Answer:
(c) KBr

Question 36.
What type of stoichiometric defect is shown by ZnS ?
(a) Schottky defect
(b) Frenkel defect
(c) Both Frenkel and Schottky defects
(d) Non-stoichiometric defect
Answer:
(b) Frenkel defect

Question 37.
In a Schottky defect, …………..
(a) an ion moves to interstitial position between the lattice points
(b) electrons are trapped in a lattice site
(c) some lattice sites are vacant
(d) some extra cations are present in interstitial spaces.
Answer:
(c) some lattice sites are vacant

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State

Question 38.
Silver halides generally show ………….
(a) Schottky defect
(b) Frenkel defect
(c) both Frenkel and Schottky defects
(d) cation excess defect.
Answer:
(c) both Frenkel and Schottky defects

Question 39.
An electron trapped in an anion site in a crystal is called ………….
(a) F-centre
(b) Frenkel defect
(c) Schottky defect
(d) interstitial defect
Answer:
(a) F-centre

Question 40.
Which of the following will have metal deficiency defect ?
(a) NaCl
(b) FeO
(c) KCl
(d) ZnO
Answer:
(b) FeO

Question 41.
Pure silicon and germanium behave as …………
(a) conductors
(b) semiconductors
(c) insulators
(d) piezoelectric crystals
Answer:
(c) insulators

Question 42.
To get n-type of semiconductor, germanium should be doped with ………….
(a) gallium
(b) arsenic
(c) aluminium
(d) boron
Answer:
(b) arsenic

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State

Question 43.
p-type semiconductors are formed when Si or Ge are doped with …………
(a) group 14 elements
(b) group 15 elements
(c) group 13 elements
(d) group 18 elements.
Answer:
(c) group 13 elements

Question 44.
Paramagnetic substances are magnetised in a magnetic field in the same direction. Paramagnetism is due to the presence of……………….
(a) one or more unpaired electrons
(b) all paired electrons
(c) permanent spin and orbital motion
(d) parallel and anti-parallel spins in equal numbers.
Answer:
(a) one or more unpaired electrons

Question 45.
Fe3O4 is ferrimagnetic at room temperature but at 850 K, it becomes
(a) diamagnetic
(b) ferrimagnetic
(c) paramagnetic
(d) anti-ferromagnetic
Answer:
(c) paramagnetic

Question 46.
Which of the following metal oxides is antiferromagnetic in nature ?
(a) MnO2
(b) TiO2
(c) NO2
(d) CrO2
Answer:
(a) MnO2

Question 47.
Which of the following conditions favours the existance of a substance in the solid state ?
(a) High temperature
(b) Low temperature
(c) High thermal energy
(d) Weak cohesive forces
Answer:
(b) Low temperature

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State

Question 48.
Which of the following is an amorphous solid ?
(a) Graphite (c)
(b) Quartz glass (SiO2)
(c) Chrome alum
(d) Silicon carbide (SiC)
Answer:
(b) Quartz glass (SiO2)

Question 49.
Iodine molecules are held in the crystals lattice by
(a) London forces
(b) dipole-dipole interactions
(c) covalent bonds
(d) coulombic forces
Answer:
(a) London forces

Question 50.
Which of the following is a network solid ?
(a) SO2(Solid)
(b) I2
(c) Diamond
(d) H2O(Ice)
Answer:
(c) Diamond

Question 51.
Graphite is a good conductor of electricity due to the presence of_______
(a) lone pair of electrons
(b) free valence electrons
(c) cations
(d) anions
Answer:
(b) free valence electrons

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State

Question 52.
Which of the following oxides behaves as conductor or insulator depending upon temperature ?
(a) TiO
(b) SiO2
(c) TiO3
(d) MgO
Answer:
(c) TiO3

Question 53.
Which of the following oxides shows electrical properties like metals ?
(a) SiO2
(b) MgO
(c) SO2(s)
(d) CrO2
Answer:
(d) CrO2

Question 54.
The lattice site in a pure crystal cannot be occupied by
(a) molecule
(b) ion
(c) electron
(d) atom
Answer:
(c) electron

Question 55.
Graphite cannot be classified as_____________ .
(a) conducting solid
(b) network solid
(c) covalent solid
(d) ionic solid
Answer:
(d) ionic solid

Question 56.
Cations are present in the interstitial sites in___________
(a) Frenkel defect
(b) Schottky defect
(c) vacancy defect
(d) metal deficiency defect
Answer:
(a) Frenkel defect

Question 57.
Which of the following is true about the charge acquired by p-type semiconductors ?
(a) positive
(b) neutral
(c) negative
(d) depends on concentration of p impurity
Answer:
(b) neutral

Bihar Board 12th Chemistry Objective Answers Chapter 1 The Solid State

Question 58.
In which pair most efficient packing is present ?
(a) hep and bcc
(b) hep and ccp
(c) bcc and ccp
(d) bcc and simple cubic cell
Answer:
(c) bcc and ccp

Question 59.
What is the coordination number in a square close packed structure in two dimensions ?
(a) 2
(b) 3
(c) 4
(d) 6
Answer:
(c) 4

Question 60.
Which kind of defects are introduced by doping ?
(a) Dislocation defects
(b) Schottky defects
(c) Frenkel defects
(d) Electronic defects
Answer:
(d) Electronic defects

Question 61.
The edge lengths of the unit cells in terms of the radius of spheres constituting fee, bcc and simple cube unit cell are respectively.
(a) \(2 \sqrt{2} r, \frac{4 r}{\sqrt{3}}, 2 r\)
(b) \(\frac{4 r}{\sqrt{3}}, 2 \sqrt{2} r, 2 r\)
(c) \(2 \mathrm{r}, 2 \sqrt{2} \mathrm{r}, \frac{4 \mathrm{r}}{\sqrt{3}}\)
(d) \(2 \mathrm{r}, \frac{4 \mathrm{r}}{\sqrt{3}}, 2 \sqrt{2} \mathrm{r}\)
Answer:
(a) \(2 \sqrt{2} r, \frac{4 r}{\sqrt{3}}, 2 r\)

Bihar Board 12th Biology Model Question Paper 4 in English Medium

Bihar Board 12th Biology Model Papers

Bihar Board 12th Biology Model Question Paper 4 in English Medium

Time : 3 Hours 15 Min
Total Marks : 70

Instructions for the candidates:

  1. Candidates are required to give answers in their own words as far as practicable.
  2. Figures in the right-hand margin indicate full marks.
  3. While answering the questions, the candidate should adhere to the word limit as for as practicable.
  4. 15 Minutes of extra time has been allotted for the candidates to read the questions carefully.
  5. This question paper is divided into two sections: Section – A and Section – B
  6. In Section – A, there are 35 objective type questions which are compulsory, each carrying 1 mark. Darken the circle with blue/black ball pen against the correct option on OMR Sheet provided to you. Do not use Whitener/Liquid/ Blade/Nail on OMR Sheet otherwise result will be treated as invalid.
  7. In Section – B, there are Non-objective type questions. There are 18 Short answer type questions, out of which any 10 questions are to be answered. Each question carries 2 marks. Apart from this, there are 6 long answer type questions, out of which any 3 of them are to be answered. Each question carries 5 marks
  8. Use of any electronic device is prohibited.

Objective Type Questions

There are 1 to 35 objective type questions with 4 options. Choose the correct option which is to be answered on OMR Sheet. (35 x 1 = 35)

Question 1.
Mendel worked on
(a) Garden pea
(b) Chick pea
(c) Grass pea
(d) None of these
Answer:
(a) Garden pea

Question 2.
Thymus is present near
(a) Heart
(b) Kidney
(c) Liver
(d) Testis
Answer:
(a) Heart

Bihar Board 12th Biology Model Question Paper 4 in English Medium

Question 3.
Which among the following antibodies, the Nascent child Obtains maximum from mother’s milk.
(a) Ig A
(b) Ig M
(c) Ig B
(d) Ig E
Answer:
(a) Ig A

Question 4.
10% law for energy transfer in a food chain is given by
(a) Tansley
(b) Weismann
(c) Lindmann
(d) None of the above
Answer:
(c) Lindmann

Question 5.
Causative agent of Dengue fever is
(a) Virus
(b) Bacteria
(c) Protozoa
(d) All of the above
Answer:
(a) Virus

Question 6.
New plants develop from leaves in
(a) Cycas
(b) Eichhornia
(c) Bryophyllum
(d) None of the above
Answer:
(c) Bryophyllum

Question 7.
Phosphorus is important constituent of
(a) Plasma membrane
(b) Nucleic Acid
(c) Cellular energy transport system
(d) All of the above
Answer:
(d) All of the above

Question 8.
Which of the following disease is spread by Protozoan parasite?
(a) Malaria
(b) Kala-azar
(c) Amoebiasis
(d) All of the above
Answer:
(d) All of the above

Bihar Board 12th Biology Model Question Paper 4 in English Medium

Question 9.
Fingcrlings and larvae of
(a) Silkworm
(b) Honey bee
(c) Fish
(d) All of the above
Answer:
(c) Fish

Question 10.
Inducer molecule in lac operon of E. Coli is chemically.
(a) Amino acid
(b) Disaccharides
(c) Protein
(d) All of the above
Answer:
(b) Disaccharides

Question 11.
In a natural Ecosystem decomposition takes place by
(a) Parasitic Algae
(b) Virus
(c) Bacteria and Fungi
(d) All of the above
Answer:
(c) Bacteria and Fungi

Question 12.
PCR technique is routinely used to detect
(a) Cancer
(b) T.B.
(c) HIV
(d) All of the above
Answer:
(c) HIV

Question 13.
Production of fruit without fertilization is known as
(a) Apomixis
(b) Apogamy
(c) Parthenogenesis
(d) None of the above
Answer:
(c) Parthenogenesis

Bihar Board 12th Biology Model Question Paper 4 in English Medium

Question 14.
Chiasma formation occurs during
(a) Amitosis
(b) Mitosis
(c) Meiosis
(d) None of the above
Answer:
(c) Meiosis

Question 15.
Acrosome is a part of
(a) Spermatozoa
(b) RNA
(c) DNA
(d) All of the above
Answer:
(a) Spermatozoa

Question 16.
Biogas contains
(a) H2S
(b) CH4
(c) CO2
(d) All of the above
Answer:
(b) CH4

Question 17.
How many structural genes are present in lac- operon in E. coli?
(a) 4
(b) 2
(c) 3
(d) None of the above
Answer:
(c) 3

Question 18.
Ozone layer is found in
(a) Troposphere
(b) Stratosphere
(c) Mesosphere
(d) Exosphere
Answer:
(b) Stratosphere

Question 19.
Mendel’s Monohybrid ratio is
(a) 1 : 2
(b) 3 : 1
(c) 9 : 3 : 3 : 1
(d) All of the above
Answer:
(b) 3 : 1

Question 20.
Ta jmahal located in Agra is in danger due to which gas?
(a) CO2
(b) NO2
(c) SO2
(d) CFC
Answer:
(c) SO2

Question 21.
Which is used to see DNA in laboratory?
(a) Aniline
(b) Carmine
(c) Ithidium Bromide
(d) All of the above
Answer:
(c) Ithidium Bromide

Bihar Board 12th Biology Model Question Paper 4 in English Medium

Question 22.
Pyramid of energy is always
(a) Upright
(b) Downward
(c) Both
(d) None of the above
Answer:
(a) Upright

Question 23.
An organism with two identical alleles is said to be
(a) Homozygous
(b) Heterozygous
(c) Dominant
(d) Hybrid
Answer:
(a) Homozygous

Question 24.
Bacteriophase kills
(a) Fungi
(b) Parasites
(c) Bacteria
(d) Viruses
Answer:
(c) Bacteria

Question 25.
Which of the following is used in ELISA test?
(a) Endonuclease
(b) Polymerase
(c) Ligase
(d) Peroxydase
Answer:
(d) Peroxydase

Question 26.
Catla fish is found in
(a) Fresh water
(b) Hard water
(c) Both a and b
(d) None of the above
Answer:
(a) Fresh water

Question 27.
Which of the following fixes nitrogen in Symbiotic association?
(a) Chana
(b) Volvox
(c) Rhizobium
(d) None of the above
Answer:
(c) Rhizobium

Bihar Board 12th Biology Model Question Paper 4 in English Medium

Question 28.
Which on of the following is active in treatment of sewage?
(a) Fishes
(b) Fish
(c) Bacteria
(d) All of the above
Answer:
(c) Bacteria

Question 29.
Smoking causes
(a) Asthama
(b) Bronchitis
(c) Lung disease
(d) All of the above
Answer:
(d) All of the above

Question 30.
Which of the following study is called Oncology?
(a) Leprosy
(b) Cholera
(c) Cancer
(d) All of the above
Answer:
(c) Cancer

Question 31.
Elephantiasis is called as
(a) Malaria
(b) Filaria
(c) Kala-azar
(d) All of the above
Answer:
(b) Filaria

Bihar Board 12th Biology Model Question Paper 4 in English Medium

Question 32.
Which of the following causes Ozone hole?
(a) Ethylene
(b) Acetylene
(c) Chloro-florp carbon
(d) All of the above
Answer:
(c) Chloro-florp carbon

Question 33.
The process of producing immunity in the body is called
(a) Immunity
(b) Immunization
(c) Allergy
(d) All of the above
Answer:
(b) Immunization

Question 34.
Which of the following is the copper releasing IUD
(a) Lippes loop
(b) Progestasert
(c) LNG 20
(d) CUT
Answer:
(d) CUT

Question 35.
Chiasma formation occurs during
(a) Amitosis
(b) Mitosis
(c) Meiosis
(d) None of the above
Answer:
(c) Meiosis

Non-Objective Type Questions

Short Answer Type Questions

In this section, there are 18 short answer type question (each carryies 2 marks) out of which answers any ten (10) questions. (10 x 2 = 20)

Question 1.
What is Bt cotton?
Answer:
Bt cotton-Bt cotton is a type of toxin, which is obtained from Bacillus thuringiensis. It is called Bt in short form. Bt toxin gene has been cloned from the bacteria and expressed in plants to provide resistance from insects without the requirement of insecticide. Bt toxin genes were isolated from Bacillus thuringiensis and incorporated into the several crop plants such as cotton.

Question 2.
What measures should be opted to prevent from contracting sexually transmitted diseases ?
Answer:
For prevention of sexually transmitted diseases following actions should be opted :

  • Avoid sex with unknown partner/multiple partners.
  • Always use condoms during coitus.
  • In case of doubt, should go to a qualified doctor for early detection and get complete treatment if diagnosed with disease.

Bihar Board 12th Biology Model Question Paper 4 in English Medium

Question 3.
Write short notes on Golden rice.
Answer:
Golden rice is a genetically modified variety of rice. It contains the transgenes from the daffodil plants and also from some bacteria which are responsible for the synthesis of (3-carotene which is a component of Vitamin A. Deficiency of vitamin A causes blindness. Therefore, P-carotene present in golden variety of rice can be helpful in preventing the child blindness.

Question 4.
Describe the disease transmitted through blood transfusion.
Answer:
AIDS is a blood-transfusion transmitted disease caused by Human Immuno deficiency Virus (HIV) in which the natural immune system of the body is destroyed and body is infected with various pathogens.

Question 5.
What is tumor ?
Answer:
When cancerous cells by their division from a storage of cells, it is called tumor. Tumor are of two types –
1. Benign, 2. Malignant.

  • Benign Tumor – They are restricted to a limited portion and do not extend in other parts of the body.
  • Malignant – They can easily spread to different parts of the body and their cells are known as Neoplastic cells.

Question 6.
(i) What is noise pollution ? What are its various sources ?
(ii) What are its effects on human beings ?
(iii) Give some methods to control noise pollution.
Answer:
(i) Noise Pollution : It is the unwanted sound which is dumped into the atmosphere and it interferes with human communication, comfort and health.
Sources : Vehicles, musical horns, machines, transistors, radio, drum, beats of religious processions, amplified rock music and disco etc.

Question 7.
Why we say energy flow in the biosphere is unidirectional?
Answer:
The main source of energy of biosphere is ‘Sun’. During photosynthesis solar energy is converted into the chemical energy in the plants. Plants are consumed by herbivores and chemical energy of plants is partially transferred to herbivores animals. Carnivores consume herbivorous animals, their chemical energy of herbivores is transferred to carnivores. That is why, we can say that flow of energy in the biosphere is unidirectional.

Question 8.
Enumerate the major criterias for self-pollination.
Answer:
In which there is transfer of pollen grains from anther to stigma of same flower or another flower of same plants.

  • It is found in bisexual plants only.
  • It may occur in Cleistogamous flowers.
  • There is no need of pollinating agent in it.

Bihar Board 12th Biology Model Question Paper 4 in English Medium

Question 9.
Differentiate between DNA and RNA.
Answer:

DNA RNA
1. DNA is a genetic 1. It is not a genetic material, exception Virus.
2. De-oxyribose sugar is present. 2. Ribose sugar present.
3. Pyrimidine base thymine is present. 3. Uracil in place of thymine.
4. It is double helical 4. It is a single helical structure.

Question 10.
Describe the post-fertilization changes in a flower.
Answer:
During fertilization, the pollen tube reaches into the ovule through the micropyle. One of the two gametes, one joins with the egg cell resulting in the production of zygote. This is called syngamy and other with the two polar nuclei producing triploid primary endosperm nucleus. This is called as triple fusion. This completes the process of fertilization. After fertilization, the ovule converts into the seed and the whole ovary develops into a complete fruit. The ovary wall forms.

Question 11.
Write principles of Biotechnology.
Answer:
Principles of Biotechnology :
Biotechnology is based on two main techniques
(i) Genetic engineering-It is the science of manipulation of genes. In a strict sense it involves alterations in the chemistry of genetic material, introduction of the same into host and thereby changing the phenotype of host.

(ii) Biochemical engineering processes devoted for the growth of desired microbe or eukaryotic cell in large quantities in a culture medium in aseptic conditions for the manufacture and multiplication of biotechnological products, such as antibiotics, vaccines, enzymes etc.

Question 12.
Differentiate between Innate and Acquired Immunity?
Answer:
Innate immunity is a kind of non-specific protection of the body which persist from the birth whereas acquired immunity is pathogen-specific in which primary and secondary responses occur which depend upon memory of the primary responses.

Question 13.
Name the hormones invovled in regulation of spermatogenesis.
Answer:
The hormones involved in the regulation of spermatogenesis one follicle stimulating hormones (F.S.H.) and Lutenizing stimulating hormones (L.S.H.) which are secreted by pituitory gland under the influence of gondotropin releasing hormones from the hypothalamus.

Bihar Board 12th Biology Model Question Paper 4 in English Medium

Question 14.
Describe about Parthenium Weed.
Answer:
Parthenium is a genus of North American shrubs. Parthenium invades disturbed land including roadsides. It infests pastures and form land causing after disastrous loss of yield. As an invader it first appeared as a contaminant in imported wheat. The plant produces Allelopathic chemical that suppress crop and pasture plants and allergens that affect humans and livestock. It also causes pollen allergies. But, it may be used as a remedy of skin inflammation, diarrhoea, dysentery and malaria etc.

Question 15.
What is Tranquilizers? Explain it with examples.
Answer:
Drugs which are used in patients having mental tension & worries are called tranquilizers.
For example :

  • Benzodiazepins-Used in case of mental patient and gives mental peace to them.
  • Phenothiazines-It stimulate the patient and gives mental peace through eradicating mental worriness.
  • Reserpine-It is obtained from Rauvolfia serpentina and very effective in mental tension and worriness.

Question 16.
List few important uses of Human Genome Project.
Answer:
(i) The genetic make up of an organism or an individual lies in the DNA sequence. The knowledge about the effect of DNA variations among individuals can lead to revolutionary new ways to diagnose, treat and prevent thousands of disorders that affect human beings.

(ii) The learning about non-human organisms, DNA sequences can lead to understanding of their natural capabilities that can be applied towards solving challenges in health care, agriculture and energy production etc.

Question 17.
Draw a labelled diagram of human male reproductive system.
Answer:
Bihar Board 12th Biology Model Question Paper 4 in English Medium 1

Question 18.
Describe the structure of biogas plant. Give various steps involved in obtaining biogas.
Answer:
Biogas plants consists of a concrete tank (10-15 feet deep) in which bio-wastes are collected and a slurry of dung is fed. A floating cover is placed over the slurry which keeps on rising as the gas is produced. The biogas plant has an outlet for supply of biogas and another outlet for removing slurry.
Steps :

  1. Slurry of animal dung (dung + water) is fed into the digester.
  2. In the digester, microbes break down or decompose the complex compounds of the biomass in the slurry.
  3. Thd anaerobic microbes do not require oxygen, so the digesters are designed like a sealed chamber.
  4. The process takes a few days and gases like methane, CO2, hydrogen and hydrogen sulphide are produced.

Bihar Board 12th Biology Model Question Paper 4 in English Medium

Long Answer Type Questions

There are 6 long answers type question (each carrying 05 marks) out of which answers any three questions. (5 x 3 = 15)

Question 19.
What is pollination? Give an account of the varied means of cross-pollination in plants.
Answer:
Transfer of pollen grains after sheding from the anther to the stigma of the carpel is called pollination.
Pollination in flowering plants occurs by two methods:

  • Self Pollination and
  • Cross-Pollination.

(1) Self Pollination – Self pollination involves the transfer of pollen grains from the anther of the flower to the stigma of the same flower or another flower of the same plant.

(2) Cross Pollination – Cross pollination involves the transfer of pollen grains from the flower of one plant to the stigma of the flower of another plant.

Varied means of cross pollination in plants are:

(a) Dicliny – Cross-pollination always occurs when the plants are unisexual and dioecious. Ex-Papaya.
(b) Self Sterility – When the stigma of the gynoecium of a flower is not pollinated by pollen grains of the same flower. Ex-Pea, Potato etc.
(c) Dichogamy – When maturity of male and female parts of a bisexual flower occurs in different times. It is of two types : (i) Protogyny (when gynoecium matures first. Ex-Banyan) and (ii) Protandry (when androecium matures first. Ex:-Maize)
(d) Herkogamy – In some flowers physical barrier present between anther and stigma which avoid self-pollination. Ex-Calotropis
(e) Heterostyly – The flowers of some plants have different lengths of stamens and styles so their self-pollination is not possible. Ex-Primula, Oxalis etc.

Question 20.
What is adaptation? Describe the different types of adaptation in plants of deserts.
Answer:
Adaptation is an attribute of the organism to survive and reproduce in its habitat. Many adaptations have evolved over a long evolutionary time and are genetically fixed. It is of two types-temporary and permanent, e.g. Shrinking of pupil due to bright light is temporary adaptation while change of fore-limbs in feathers for fly in birds is permanant adaptation.

Following adaptations are found in plants of deserts

(a) Its roots are long, thick and goes deep in the soil.
(b) Its stems are fleshy and thick for storage of water.
(c) To check loss of water due to vapourisation, stems are generally cuticulised and fill with dense hairs.
(d) Leaves are changed into small scales and spines, which decreases loss of water due to vapourisation. .
(e) Leaves have suitable tissues for storage of water.
(f) Stomata are embedded in stomatal cavity.
Example of Xerophytic plants are-Opuntia, Euphorbia, Argemone, etc.

Question 21.
Describe the properties of genetic code.
Answer:
The properties of genetic code are as follows :
(a) Triplet nature – The genetic code is a triplet code which is arranged in a sequence on m-RNA.
(b) Unambiguous and Specific-One codon codes for only one amino acid, hence it is unambiguous and specific.
(c) Degenerate code – Some amino acids are coded by more than one codon, hence the code is degenerate.
(d) Commaless form – There are no comma and punctuation marks between the coding triplets (Codons).
(e) Universal – The code is nearly universal. For example, from bacteria to human UUU would code for Phenylalanine (Phe).
(f) Nonsense or Terminator Codon – Three of the 64 codons, namely UAA, UAG and UGA, do not specify any amino acids, but signals the end of the message.
(g) Initiation codon – AUG and sometime GUG are the initiator codon. As AUG stands for methionine, polypeptide chain begins with methionine when they are synthesized.

Bihar Board 12th Biology Model Question Paper 4 in English Medium

Question 22.
Define Biodiversity. Describe in brief any three important components of Biodiversity.
Answer:
Biodiversity is the variation of life at all levels of biological organization. In other words variability found in different forms of life like plants, animals and microorganisms and in their genes are called as biodiversity. It voluntarily integrates terresterial, aquatic and ecosystem diversity.

There are three basic components of biodiversity :-

  • Genetic diversity
  • Species diversity
  • Ecological diversity.

(d) Genetic diversity-Genetic diversity is related to the variations of genes within species. A single species might show high diversity at the genetic level over its distributional range. For example, genetic variations shown by the medicinal plant Rauwolfia vomitoria growing in different Himalayan ranges might be in terms of the potency and concentration of the active chemical (reserpine) that the plant produces. India has more than 50,000 genetically different strains of rice and 1,000 varieties of mango.

(e) Species diversity-The diversity at the species level is called species diversity. For example, the Westerm Ghats have a greater amphibian species diversity than Eastern Ghats. Similarly, taking example of plants, Brinjal {Solatium melanogena) Potato (Solarium tuberosum) and Tomato (Solatium lycopersicon) belong to the same genus Solatium but they all too differ at the species level.

(f) Ecological diversity-The diversity at the ecosystem level is called ecological diversity. It is related to the different types of ecosystems, e.g., terrestrial (deserts, rain forest, grass land, etc.) and aquatic (rivers, ponds, lakes, sea, etc.) ecosystems.

Ecological diversity is of three types-Alpha (α), Beta (β) and Gamma (γ) diversity.

(i) Alpha diversity – It refers to the diversity of those organism which belongs to same community and habitat.

(ii) Beta diversity – Diversity between different communities of same habitat is called Beta diversity. If there is more heterogeneity in the habitats in a region or more dissimilarity between communities, there will be more Beta diversity.

(iii) Gamma diversity – Diversity at landscape level is called Gamma diversity. It envolves both types of diversity- alpha and beta. It refers to the diversity of the habitats in the whole geographical region.

Question 23.
How microbes are essential for human welfare? Explain it in detail.
Answer:
Microbes are essential for human welfare because they help through various ways in promotion of our health, foods, agro products and reduction of pollution level as well. These are illustrated below

(a) Microbes are essential for production of dairy products like paneer, curd, butter etc. which are processing products of milk. Production is carried out by the microbes such as bacteria. Similarly bread, idli, vinegar are produced by the activity of microbes.

(b) By using Mithanogen bacteria, production of biogas is possible.

(c) Microbes also help us in the treatment of domestic waste water.

(d) In the field of industries, by activity of microbes, we obtain alcoholic drinks of ionous type, organic acids, vitamin B2, and B12, dextrins, steroid, amino acids, cyclosporin etc. which all enhances our life.

(e) Microbes are used in the field of treatment against infectious diseases.

(f) In the field of agriculture, microbes are used to increase production of agriculture. We uses microbes as pesticides, weedicides which improve our environmental health.

(g) Microbes are also used as ‘single cell protein’ which fulfills our protein requirements.

Question 24.
Give an account of molecular diagnosis.
Answer:
For effective treatment of a disease, early diagnosis and understanding its pathophysiology is very important. Using conventional method of diagnosis (serum and urine analysis), early detection is not possible. Recombinant DNA technology, polymerase chain reaction (PCR) and Enzyme linked Immuno Sorbent Assay (ELISA) are some of the techniques that serves the purpose of early diagnosis.

Very low concentration of pathogen (bacteria, viruses) can be detected in early stage by application of their nucleic acid by PCR. PCR is now routinely used to detect HIV in suspected AIDS patients. It is being used to detect mutations in genes in suspected cancer patients too. It is powerful technique to identify many other genetic disorder.

ELISA is based on the principle of antigen-antibody interaction. Infection by pathogen can be detected by the presence of antigens (proteins, glyco-proteins) or by detecting the antibodies synthesised against the pathogens. Hybridoma technology is also used to produce monoclonal antibody to detect microscopic pathogens.

Bihar Board 12th Biology Model Question Paper 4 in English Medium

Bihar Board 12th Economics Model Question Paper 2 in English Medium

Bihar Board 12th Economics Model Papers

Bihar Board 12th Economics Model Question Paper 2 in English Medium

Time : 3 Hour 15 Min
Full Marks : 100

Instructions

  1. Candidates are required to give their answers in their own words as far as practicable.
  2. Figures in the right hand margin indicate full marks.
  3. 15 minutes of extra time has been allotted for the candidate to read the questions carefully.
  4. This question paper has two sections : Section-A and Section-B.
  5. In Section-A, there are 50 objective type questions which are compulsory, each carrying 1 mark. Darken the circle with black/blue ball pen against the correct option on OMR Sheet provided to you Do. not use Whitener/Liquid/Blade/Nail on OMR Sheet, otherwise the result will be treated as invalid.
  6. In Section-B, there are Non-objective type questions. There are 25 Short answer type questions, out of which any 15 questions are to be answered. Each question carries 2 marks. Apart froms this, there are 08 Long answer type questions, out-of which any 04 of them are to be answered. Each questions carries 5 marks.
  7. Use of any electronic device is prohibited.

Objective Type Questions

Question No. 1 to 50 have four options provided, out of which only one is correct. Youhave to mark, your selected option, on the OMR-Sheet. Each questiion carries 1 (one) mark. [50 x 1 = 50]

Question 1.
The subject matter of economics is being studied under which branches :
(a) Micro Economics
(b) Macro Economics
(c) Above two
(d) None of the above
Answer:
(c) Above two

Bihar Board 12th Economics Model Question Paper 2 in English Medium

Question 2.
On the basis of the ownership of the resources, economies are ?
(a) Centrally planned economy
(b) Market economy
(c) Mixed economy
(d) All of above
Answer:
(c) Mixed economy

Question 3.
Which are the central problems of an economy ?
(a) Allocation of resources
(b) Best use of resources
(c) Economic development
(d) All the above
Answer:
(d) All the above

Question 4.
Macro Economics studies :
(a) Full employment
(b) Aggregate price level
(c) Gross National Product
(d) All the above
Answer:
(d) All the above

Question 5.
This is required for a budget set:
(a) Collection of bundles
(b) Prevailing market price
(c) Total income of the consumer
(d) All the above
Answer:
(d) All the above

Question 6.
In diminishing rate of substitution :
(a) more of goods 1
(b) less of goods 2
(c) more of both 1 and 2
(d) (a) and (b) both
Answer:
(c) more of both 1 and 2

Question 7.
Consumer behaviour is studied in :
(a) Micro Economics
(b) Macro Economics
(c) Income theory
(d) None of the above
Answer:
(b) Macro Economics

Question 9.
Indifference curve is :
(a) Concave to the origin
(b) Convex to the origin
(c) Both the above true
(d) Both the above false
Answer:
(c) Both the above true

Question 10.
The slope of the demand curve is :
(a) left to right downward
(b) left to right upward
(c) parallel to x-axis
(d) none of the above
Answer:
(c) parallel to x-axis

Question 11.
Demand function is expressed by which equation ?
(a) Px
(b) Dx = Px
(c) Dx = ∫(Px)
(d) None of the above
Answer:
(d) None of the above

Question 12.
Short run production function is explained by which law ?
(a) By the law of demand
(b) By law of variable proportions
(c) By law of returns to scale
(d) By elasticity of demand
Answer:
(a) By the law of demand

Question 13.
Tick the correct in the following :
(a) TVC = TC – TFC
(b) TC = TVC – TFC
(c) TFC = TVC + TC
(d) TC = TVC × TFC
Answer:
(b) TC = TVC – TFC

Question 14.
MR is expressed as :
(a) \(\frac { ΔTR }{ ΔQ }\)
(b) \(\frac { TR }{ Q }\)
(c) \(\frac { ΔAR }{ Q }\)
(d) None of the above
Answer:
(a) \(\frac { ΔTR }{ ΔQ }\)

Question 15.
In monopoly and monopolistic condition :
(a) AR = MR
(b) AR > MR
(c) AR < MR
(d) None of the above
Answer:
(a) AR = MR

Question 16.
In every market situation which condition is necessary to be fulfilled for a firm’s equilibrium ?
(a) AR = MC
(b) MR = MC
(c) MC curve should cut the MR curve from below
(d) (b) and (c) both
Answer:
(d) (b) and (c) both

Bihar Board 12th Economics Model Question Paper 2 in English Medium

Question 17.
Which of the following statement is true ?
(a) There is direct relationship between the price of a commodity and its Supply
(b) Supply curve moves left to right upward
(c) Supply is affected by many factors
(d) All the above
Answer:
(d) All the above

Question 18.
If the price of a commodity rises by 40% but the supply increases by only 15%, supply of such commodity would be :
(a) Excessive elastic
(b) Elastic
(c) Inelastic
(d) completely inelastic
Answer:
(d) completely inelastic

Question 19.
In equilibrium position :
(a) The amount to be sold is equal to the amount to be purchased.
(b) Market supply is equal to market demand
(c) Neither the firm nor the consumer wants to be destabilised
(d) All the above
Answer:
(d) All the above

Question 20.
Every firm uses labour up to the point:
(a) Where labour’s marginal productivity is equal to the wage rate
(b) Where labour’s marginal productivity is less than the wage rate
(c) Where labor r’s marginal productivity is more than the wage rate
(d) None of the above
Answer:
(a) Where labour’s marginal productivity is equal to the wage rate

Question 21.
In which market product differentiation is found ?
(a) Pure competition
(b) Perfect competition
(c) Monopoly
(d) Monopolistic competition
Answer:
(c) Monopoly

Question 22.
Government decides “price ceiling”
(a) On necessary goods
(b) Which is less than the price decided by market ?
(c) To make it affordable to the common man
(d) All of the above
Answer:
(d) All of the above

Question 23.
Price is determined at the point, where :
(a) Demand of the commodity is high
(b) Supply of the commodity is high
(c) Demand of the commodity and supply of the commodity is equal
(d) None of the above
Answer:
(c) Demand of the commodity and supply of the commodity is equal

Question 24.
Market price is found in :
(a) Short period market
(b) Long period market
(c) Very long period market
(d) None of the above
Answer:
(a) Short period market

Question 25.
British economist John Maynard Keynes famous book “The General Theory” was published in which year :
(a) 1926
(b) 1936
(c) 1946
(d)1956
Answer:
(c) 1946

Question 26.
The great Depression came in which year :
(a) 1949
(b)1939
(c) 1929
(d) 19194
Answer:
(a) 1949

Question 27.
Macro economics sees an economy as a combination of which sectors :
(a) Family
(a) Firm
(c) Government and external sector
(d) All of above
Answer:
(d) All of above

Bihar Board 12th Economics Model Question Paper 2 in English Medium

Question 28.
GNPMP = ?
(a) GDPMP – Depreciation
(b) GDPMP + net factor income from abroad
(c) Both the above
(d) None of the above
Answer:
(d) None of the above

Question 29.
Which is the correct sequence of money’s development ?
(a) Commodity money, Paper money, Metal money
(b) Commodity money, Metal money, Paper money
(c) Credit money, Metal money, Paper money
(d) None of the above
Answer:
(a) Commodity money, Paper money, Metal money

Question 30.
Reserve Bank of India has presented four measures of money supply, namely M1, M2, M3 and M4, M1 includes :
(a) C = currency held by public
(b) DD = net demand deposit of the bank
(c) OD = other deposits held with the RBI
(d) All of the above
Answer:
(a) C = currency held by public

Question 31.
Which is common man’s bank ?
(a) Commercial Bank
(b) Central Bank
(c) (a) and (b) both
(d) None of the above
Answer:
(c) (a) and (b) both

Question 32.
(a) \(\frac { 1 }{ CRR }\)
(b) Cash × \(\frac { 1 }{ CRR }\)
(c) Cash × CRR
(d) None of these above
Answer:
(c) Cash × CRR

Question 33.
Which of the following is Central Bank’s function ?
(a) Right of issuing notes
(b) Government’s banker
(c) Custodian of Foreign Exchange Reserves
(d) All of the above
Answer:
(d) All of the above

Question 34.
Which currency is issued by Central Bank of the country ?
(a) Money in circulation
(b) Credit money
(c) Coins
(d) All of the above
Answer:
(a) Money in circulation

Question 35.
In an open economy which are the components of Aggregate Demand :
(a) Consumption
(b) Investment
(c) Consumption + government expenditure
(d) Consumption + Investment + Govt, expenditure + net export
Answer:
(d) Consumption + Investment + Govt, expenditure + net export

Question 36.
APC + APS = ?
(a) 0
(b) 1
(c) Infinity
(d) None of the above
Answer:
(c) Infinity

Question 37.
What are the reasons of excess demand ?
(a) Increase in public expenditure
(b) Increase in money supply
(c) Decrease in taxes
(d) All the above
Answer:
(d) All the above

Question 38.
Indian’s financial year is :
(a) 1st April to 31st March
(b) 1st January to 31st March
(c) 1st July to 30th June
(d) None of the above
Answer:
(a) 1st April to 31st March

Question 39.
In direct taxes which one of the following is included ?
(a) Income Tax
(b) Gift Tax
(c) (a) and (b) both
(d) None of the above
Answer:
(c) (a) and (b) both

Question 40.
In India who issues one rupee note;
(a) Reserve Bank of India
(b) Finance Ministry of govt, of India
(c) State Bank of India
(d) None of the above
Answer:
(b) Finance Ministry of govt, of India

Bihar Board 12th Economics Model Question Paper 2 in English Medium

Question 41.
Capital Budget includes:
(a) Revenue receipts and revenue expenditure
(b) Capital receipts and capital expenditure
(c) Direct and Indirect taxes
(d) None of the above
Answer:
(b) Capital receipts and capital expenditure

Question 42.
Primary deficit is :
(a) Fiscal Deficit – Interest Payment
(b) Fiscal Deficit + Interest Payment
(c) (a) and (b) both
(d) None of the above
Answer:
(a) Fiscal Deficit – Interest Payment

Question 43.
Budgets are of the following types :
(a) Balanced Budget
(b) Surplus Budget
(c) Deficit Budget
(d) All the above
Answer:
(d) All the above

Question 44.
Exchange rate is of the following types :
(a) Fixed exchange rate
(b) Flexible echange rate
(c) (a) and (b) both
(d) None of the above
Answer:
(c) (a) and (b) both

Question 45.
During Bretton Woods System most countries had:
(a) Fixed Exchange Rate
(b) Pegged Exchange rate
(c) (a) and (b) both
(d) None of the above
Answer:
(c) (a) and (b) both

Question 46.
Fixed exchange rate has following merits :
(a) Promotes Capital movtinem
(b) Prevents capital outflow
(c) Prevents speculation
(d) All the above
Answer:
(d) All the above

Question 47.
Bretton Woods Conference of 1944 established :
(a) International Monetary Fund
(b) World Bank
(c) (a) and (b) both
(d) None of the above
Answer:
(a) International Monetary Fund

Question 48.
Demerits of flexible exchange rate are :.
(a) Instability and uncertainty
(b) Encourages speculation
(c) Discourage international trade and investment
(d) All of the above
Answer:
(d) All of the above

Question 49.
Balance of Trade = ?
(a) Export of visible items – Import of visible item
(b) Export if visible and invisible items – Import of visible and invisible items
(c) Import of visible items – Export of visible items
(d) None of these
Answer:
(b) Export if visible and invisible items – Import of visible and invisible items

Question 50.
Components of Balance of Payments is :
(a) Current Account
(b) Capital Account
(c) (a) and (b) both
(d) None of the above
Answer:
(c) (a) and (b) both

Non-Objective Type Questions

Short Answer Type Questions

Question no. 1 to 25 are Short answer type questions. Answer any 15 out of them. Each question carries 2 marks. (15 x 3 = 30)

Question 1.
What do you mean by consumer’s equilibrium ? State its assumptions.
Answer:
The state of balance achieved by an end user of products that refers to the amount of goods and services they can purchase given their present level of income and the current level of prices. Consumer equilibrium allows a consumer to obtain the most satisfaction possible from their income.
Assumptions of consumer’s equilibrium :

  1. His money income is given and constant
  2. There is no change in the habits and tastes of the consumer throughout the analysis.

Question 2.
Write the meaning of perfectly elastic demand and perfectly inelastic demand.
Answer:
Perfectly elastic demand : It means at a higher price, quantity demanded decrease to zero, and perfectly inelastic demand. It means a change in price has no effect on quantity demanded.

Question 3.
State the relation between Marginal Production and Average Production.
Answer:
Marginal production and average production curves initialy increase then decrease due to the law of diminishing marginal returns.

  • Marginal productions : It is the change in total production divided by the change in quantity of resources or inputs.
  • Average production : It is the total production divided by the quantity of economic resources.

Question 4.
Clarify the concept of opportunity cost.
Answer:
Opportunity cost in the value of the next best alternative in choosing an alternative.
For example suppose to produce one unit of goods x, the producer has to sacrifice production of 2 units of x, the 2x is the opportunity cost producing one unit of x.

Bihar Board 12th Economics Model Question Paper 2 in English Medium

Question 5.
Why short run average cost curve is of “U” shaped ? Write briefly.
Answer:
Long run average cost curve is also known as ‘Envelope curve’. Where as LAC is a continuous curve. .The reason behind the ‘U’. Shape the curve is the Law of Returns to scale. According to this law, as plant size increases, the average cost of production decrease due to economies of scale.”

Question 6.
What do you mean by Total Revenue, Average Revenue and Marginal Revenue ?
Answer:

  • Total Revenue : The income earned by a seller or producer after selling the output is called the total revenue.
  • Average Revenue : Average Revenue refers to the revenue obtained by the seller by selling the per unit commodity. It is obtained by divideding the total revenue by total output.

Marginal Revenue : Marginal revenue is the change in total revenue which results from the sale of one more or one less unit of output.

Question 7.
Write the three characteristics of perfect competitive market.
Answer:
Characteristics of the Market : Main characteristics (or features) of the market are as follows:

  1. One Area : The term market in Economics does not refers to any fixed place but indicates that area where buyers and sellers are present and compete with each other.
  2. Presence of both Buyers and Sellers : An area is called the market where both buyers and sellers are present. Absence of any one creates hindrance in converting the area into market.
  3. One Commodity : In Economics, every commodity has different market, e.g., market of wheat, market of sugar etc.
  4. One Price of the Commodity : Market contains one single price of the commodity due to competition between buyers and sellers.

Hence, on the basis of above feature the market can be defined as :
“In economics market signifies the presence of such groups of buyers and sellers of a commodity who freely competer with each other and as a result one price prevails in the market.”

Question 8.
What is the difference between monopoly and monopolistic competition ?
Answer:
Monopoly differs from perfect competition in the following ways :

  1. In monopoly, there is a single seller (or firms) of a product whereas under perfect competition there are large number of sellers (or firms).
  2. A monopolist produces or sells a product which has no close substitute on the other hand, under perfect competition, the products sold by the various firms are homogeneous or identical. They are perfect substitutes of each other.
  3. In case of monopoly, there is no freedom of entry in the industry whereas under perfect competition, there is free entry and exit of firms in the industry.
  4. For a monopolist firm, the demand curve of its product slopes downward to the right. On the other hand, a perfect competitive firm faces a perfectly elastic downward curve (i.e., a horizontal straight line).

Bihar Board 12th Economics Model Question Paper 2 in English Medium 1

Question 9.
What is meant by equilibrium price and equilibrium quanity ?
Answer:
“When the supply and demand curves intersect, the market is in equilibrium. This is where the quantity demanded and quality supplied are equal. The corresponding price is the equilibrium price or market clearing price, the quantity is the equilibrium quantity.”

Bihar Board 12th Economics Model Question Paper 2 in English Medium

Question 10.
Differentiate between national income and domestic income.
Answer:
Difference between National Income and domestic Income :

  • National Income : “It is the sum total of factor incomes earned or generated by normal residents of a country during on accounting year.”
  • Domestic Income : “It is the sum total of factor incomes generated by all the production units located with in domestic territory of a country during an accounting year.”.

Difference : The difference between the two is net factor income from abroad which is added to domestic income to get national income.

symbolical : National income = Domestic income + Net factor income from abroad.

Question 11.
What is meant by private income ? What is the difference between private income and personal income ?
Answer:
Private income refers to.that income which accrues to private sector from all sources, both within domestic territory as well as from rest of the world.
Difference between private income and personal income :
Private Income :

  1. It includes income of only private sector.
  2. It includes both factor income and transfer earnings.
  3. Interest on national debt is a part of national income.

Personal Income :

  1. It is a receipt concept. It does not include the income of public sector.
  2. It includes transfer income of households and individuals.
  3. It includes interest on national debts.

Question 12.
Factor income is divided into how many classes ?
Answer:
Factor income is devided into three classes :

  1. Rent income
  2. Wages income
  3. Profit.

Question 13.
What are the precautions related to the calculation of income method ?
Answer:
Following are the precautions related to income method :

  1. Income from the sale of second hand goods
  2. Transfer payments
  3. Sales of shares and bonds
  4. Income from Illegal activities
  5. Wind full gains
  6. Imputed Rent
  7. Indirect Takes
  8. Corporation Tax and income tax.
  9. Deata Duties, Gift tax
  10. Travelling Allowances.

Question 14.
What is meant by under employment
equilibrium and over full employment equilibrium ?
Answer:
Underemployment equilibrium : refers to a situation with a persistent shortfall relative to full „ employment and potential output so that unemployment is higher than at the natural rate of unemployment.”

Over full employment equilibrium occurs when a country’s gross domestic product (GDP) is higher than normal.

Question 15.
Write the names of main measures of monetary policy.
Answer:
Following are the measures of monetary i policy of India :

  1. Measures of Expansion of currency.
  2. Measures of credit control
  3. Quantitative credit control
  4. Quantitative credit control
  5. Statutory liquidity ratio
  6. Cash reserve ratio
  7. Multiple rate of interest
  8. Repo Rate and Reverse repo rate.

Question 16.
Describe the various types of production cost.
Answer:
Following are the types of production cost.
Money cost :
(a) Explicit cost
(b) Implicit cost
(c) Normal profit.

Bihar Board 12th Economics Model Question Paper 2 in English Medium

Question 17.
What is an economic activity ?
Answer:
Economic activity is an important component , of subject matter of economics. All economic activities arising out of unlimited wants and scarce means are included in the subject matter of economics.

According to the modern economists, “that activity is called economic activity which is related to the use of limited resources for satisfying human wants.”

Question 18.
What do you understand by Micro economics ?
Answer:
Small units of an economy are included in micro 1 economics e.g. one consumer, one producer, one firm, one industry etc. In other words, individual units are studied in micro economics. According to K.E. Boulding, “Micro economics may be defind as that branch of analysis, which studies the economics behaviour of the individual unit, may be a person, a particular house-hold or a particular firm. It is a study of one particular unit rather than all the units combined together.”

Question 19.
Define capitalist economy.
Answer:
Capitalist economy is a system of economic organisation featured by the private ownership and the use of private profit of man-made and the nature-made capital or in other words, capitalist economy is that economy in which means of production are controlled and regulated by private organisation. Market economy contains the following important features

  1. Private property
  2. Economic freedom
  3. Laissez faire & free trade
  4. Competition
  5. Price mechanism

Question 20.
Explain the Law of Diminishing Marginal Utility.
Answer:
Law of diminishing marginal utility is a fundamental and universal law. According to this law, as we go on utilizing standard additional units of commodity continuously, marginal utility obtained from use of every additional unit decreases. It occurs or happens in all goods and services. Therefore, this law is called fundamental and universal law of satisfaction.

According to this law, as the stock of goods increases with people, marginal utility obtained from additional units of that commodity decreases after a limit.

Question 21.
Explain the circular flow income.
Answer:
Production gives birth to income, income to consumption, consumption to expenditure and again expenditure to income and production. Thus, circular flow of income earning economic activities takes place in the economy.

According to hipsey, “The circular flow of income is the flow of payment and receipt between domestic firms and domestic households.”

Hence, the circular flow of income refers to flow of money income or the flow of goods and services across different sectors of the economy in a circular form.

Question 22.
Distinguish between national income and domestic income.
Answer:
National income :

  1. It is related to the generation of income by public and private sector.
  2. It goes not include transfer income.
  3. It does not include interest on national debts.
  4. It include corporate tax and corporate savings.

Domestic Income :

  1. It is a receipt concept. It does not include the income of public sector.
  2. It includes transfer income of households and individuals.
  3. It includes interest on national debts.
  4. It neither includes corporate tax nor corporate savings.

Question 23.
Define commercial bank.
Answer:
Commercial banks perform general banking functions. A commercial bank is an institution which deal with money and credit. It accepts deposits from the public, makes the fund available to those who need them and helps in remittance of money from one place to another.

  1. According to Banking Regulation Act, “Banking means the accepting for the purpose of tending and investment of deposits of money from the public, repayable on demand or otherwise, and with draw able by cheque, draft, order or otherwise.”
  2. According to Horace white, “Bank is a manufacturer of credit and a machine for facilitating exchanges.”

Question 24.
Explain the subject matter of economics.
Answer:
Subject Matter of Economics : Various economists have presented the subject matter of economics in different ways. On the basis of various economists’ view points, the subject matter of economics can broadly be divided into four categories :

  1. Wealth-related Viewpoint: Classical economists Adam Smith, J.B. Say, Walker, Senior etc. have included wealth, its earning, distribution and use in the subject matter of economics. These economists have included economic man and his activities into the subject matter of economics.
  2. Welfare-related Viewpoint: Marshall, Pious, Canon established the concept of human-welfare (instead of wealth) in the subject matter of economics. According to welfare-related viewpoint, those economic activities should be included in the subject matter of economics which are associated with physical welfare.
  3. Scarcity-related Viewpoint: Robbins has included ‘problem of choice’ related to limited resources and unlimited ends in the subject matter of economics. According to Robbins those human activities are included in subject matter of economics with which human being tries to fulfill his unlimited ends with limited resources.
  4. Growth-related Viewpoint : Modern economists like Samuelson has included growth-based activities in the subject matter of economics. According to Samuelson both the aspects i.e. distribution of limited resources’ and ‘economic growth’ are the part of subject matter of economics.

Question 25.
Explain marginal utility.
Answer:
Marginal Utility is the addition to the total utility by consuming an extra unit of a commodity by the consumer. Symbolically:
MU = ATU/An or, MU = TU – TU„
Law of diminishing marginal utility states that consumer consumes more and more of commodity, the marginal utility obtained from an additional unit of it goes on diminishing, other things remaining the same.

Long Answer Type Questions

Question no. 26 to 33 are Long answer type questions. Answer any 4 of them. Each question carries 5 marks. (4×5 = 20)

Question 26.
Explain the law of demand with the help of a diagram. Explain any five factors affecting the demand of a commodity.
Answer:
Law of demand states that there is an inverse relation between the price of a commodity and its quantity demanded assuming all other factors effecting demand remain constants. It means that when the price of a goods falls, the demand for the goods rises and when price the demand falls.
Bihar Board 12th Economics Model Question Paper 2 in English Medium 2
There is same price in the market. All consumers purchase commodity according to their needs. The marker demand curve is the total amount demanded by all consumers at different prices. The market demand curve slopes from left down to the right.
Factors affecting the demand of commodity are as below :

  1. Price of the commodity itself: When a commodity is selling at very high price, only rich people are able to buy it. So the demand of commodity will be less. But when the price is low more and more people will be able to buy it and the demand of the commodity would be more. Thus, the demand of the commodity is greatly influenced by its price.
  2. Price of other related goods : The demand for a commodity is also influenced by prices of other related goods as substitutes.
  3. Leves of income of the consumer : consumers demand is also influenced by the size of this income.This is but natural that with increase in the level of income, there is increase in the demand of goods and services.
    (iv) Tastes and preference of consumers : Tastes and preference of the consumers also influence his demand. A taste, fashions, preferences of the consumer keep on changing and is his demand.
  4. Population : The change in the population in a country changes the demand.
  5. Income distribution: It is only the size or level of income which affects the demand but also the nature of income distributions in the country
  6. State of Trade : During a period of boom a period in which there is higher circulation of money and the production level is at a peak, the employment of resources reaches the optimum level. Consequently there is more purchasing power in the hands of the people.

Bihar Board 12th Economics Model Question Paper 2 in English Medium

Question 27.
What is meant by returns to scale ? Using a suitable diagram, explain the concepts of increasing constant and diminishing returns to scale.
Answer:
Return to scale : Return to scale refers to long run production when none of the factors of production remains fixed. All factors of production became variable and they can be changed also.
According to watson, “Returns to scale refers to the behaviour of total output as all inputs are varied in the same proportion and is a long-run concept.”
Return of scale is of three types as discussed below :
(i) Increasing Returns to scale : Increasing returns to scale occur when a given percentage increase in all factor inputs causes proportionately greater increase in output. In this way, it factors of production are increased 10%, then production increased more than 10%. Increasing return to scale occur due to division of labour and specilization.
Bihar Board 12th Economics Model Question Paper 2 in English Medium 3
(ii) Constant Returns to scale : Constant return to scale occurs when a given percentage increase in all factors inputs causes equal proportionate increase in output. If factors of production are increased 10% then production also increased by 10% and vice versa.
Bihar Board 12th Economics Model Question Paper 2 in English Medium 4
(iii) Diminishing Return to scale : Diminishing returns to scale occurs when a given percentage increase in factors of productions causes proportionately lesser increase in output.
In diminishing Retur to scale =
Proportionate increase inproduction <
Proportionate increase in factors of production.

Question 28.
What do you mean by double counting problem ? How can it be avoided Explain with an illustration. .
Answer:
Meaning : Double counting means counting of the value of the same product (or expenditure) more than once. How ? According to output method, of calculating national income value of only final goods and services produced by all the production units of a country during a year should be counted. In other words, value of intermediate goods which enter into final goods Ce.g. paper used in printing of books, raw cotton used in garments, wheat used in making breads, should not be taken into account.

But in actual practice, while taking value of final goods, value of intermediate goods also gets included because every producer treats the commodity he sells as final product irrespective of weather it is used as intermediate or final good. For instance, while taking value of final goods like cycles the value of tyres, tubes, frames, bells etc. (intermediate goods) used in manufacturing these cycles also gets included inadvertently.

In this way certain items are counted more than once resulting in over-estimation of national product to the extent of the value of intermediate goods included. This is called the problem of double counting which means counting value of the same commodity more than once.

How to avoid Double Counting : Theoritically we may say that there may be two alternative ways of avoiding double counting namely

  1. final product approach
  2. value added approach.

But in actual practice, double counting still occurs unintentionally in final product approach because every producer treats the product he sells as final product though the same night have been used by the buyer as an intermediate product.

Therefore, this problem is perfectly solved by value added method according to this method ‘instead of taking value of final products, value added by each firm at each stage of production is included.
Bihar Board 12th Economics Model Question Paper 2 in English Medium 5
Clearly value added by all the four firms is Rs. 3500 comprising Rs. 1000 by A+ Rs 500 by B + Rs. 700 by C + Rs. 1300 by D. There is no scope of double counting in this method. Thus to avoid double counting, the value added method also known as industry of origin method is used in computation of national income. It is worth mentioning that total value added is equal to value of final product.

Question 29.
Define investment multiplier. What is the relationship between investment and marginal propensity to consume.”
Answer:
Difinition of Investment multiplier :
According to Dillard, “Investment multiplier is the ratio of an increase of income to given increase in investment.” Relation between Multiplier and marginal propensity to consume (MPC) : Keynesian investment multiplier depends on marginal propensity to consume (MPC). Higher the marginal propensity to consume, greater will-be the size of multiplier, on the contrary lower the MPC, smaller will be the size of multiplier.
So, there is direct relation between multiplier and MPC
multiplier (k) = \(\frac { 1 }{ 1-MPC }\)
We know that k = \(\frac { ΔY }{ Δ1 }\)
Y=C +I; ΔY = ΔC +ΔI
ΔI = ΔY -ΔC
Here ΔI = change in Investment ΔY = change in Income and ΔC = change in consumptions.
putting the value of AI in equation (i) we have
k = \(\frac { ∆Y }{ ∆I }\)
Dividing right hand side of the equation by ΔY

Bihar Board 12th Economics Model Question Paper 2 in English Medium 6

It is clear that by knowing the value of either MPC or MPS, the value of multiplier can be calculated. Higher the MPC ‘greater will be the value of multiplier. Thus, MPC and multiplier are directly related while MPS and Multiplier are inversely related.

Question 30.
What is excess demand How can it be controlled.
Answer:
(i) Excess Demand : Meaning : If aggregate demand and aggregate supply attain equilibrium at the point beyond full employment, the situation of excess demand appears. In other words, when aggregate demand exceeds aggregate supply at full employment level, excess demand arises.

Thus, “Excess demand refers to a situation in which aggregate demand becomes excess of aggregate supply corresponding to full employment in the economy.” Excess Demand Aggregate Supply corresponding to Full Employment Level

Bihar Board 12th Economics Model Question Paper 2 in English Medium 7

(ii) In situation of excess demand, the aggregate demand exceeds the required demand, hence, increased demand will not put any reaction on employment and production levels because factors are already at full employment level. In this situation of excess demand (in which aggregate demand exceeds aggregate supply) the prices of goods and services rise and situation of inflation arises in the economy.
Characteristics of Excess Demand :

  1. When existing aggregate demand exceeds aggregate supply of full employment level, it becomes the situation of excess demand.
  2. When aggregate demand exceeds required demand, there is not effect on employment and production level and they remain constant.
  3. The difference between aggregate demand and aggregation supply is tremed as ‘Inflationary Gap’ Thus, inflationary gap is measured as the difference, between ‘aggregate demand beyond full employment’ and aggregation demand at full employment’.
    i. e., Inflationary Gap = Aggregate Demand beyond Full Employment – Aggregate Demand at Full Employment.
  4. Higher the inflationary gap, more will be the excess demand, i.e., inflationary gap is the measurement of excess demand. Excess Demand : Diagrammatic Representation

Bihar Board 12th Economics Model Question Paper 2 in English Medium 8

(iii) In adjoining fig the situation of excess demand has been shown. Aggregate demand curve AD refers to the situation of full employment. At full employment level Y, required aggregate demand is EY. Aggregate demand beyond full employment is shown by AD] line where aggregate demand becomes FY. Existing aggregate demand FY exceeds required aggregate demand EY and the difference EF becomes excess demand.
Diagrammatically,

Excess Demand = FY – EY – EF
Effects on Excess Demand

(a) Effects on Production : In situation of excess demand, production remains constant, excess demand only puts excess pressure on existing supply.

(b) Effects on Employment: In situation of excess demand, employment remains unaffected because the economy is already at full employment level and hence, there is no possibility of employment increase due to increased demand.

(c) Effects on Prices : The economy being already working at full employment level, no possibility of production increase appears in case of excess demand. Hence, supply falls short of excess demand and as a result, prices of goods and services start rising. In adjoining fig., OL is the production level at full employment level which remains constant even if aggregate demand increases to AD (7 from ∆DF. In this situation of excess demand, only price level rises from OP1 to OP2?
Bihar Board 12th Economics Model Question Paper 2 in English Medium 19

Question 31.
Explain the law of demand and what are its assumptions ?
Answer:
Law of demand-Low of demand explains quantitative relation beholden price of goods and quantity demanded. Every consumer has a psychology to buy less amount or quantity of anything of high price and more quantity of low price, ceteris Paribus (other things being equal), there is inverse relationship between price of a goods and when price is low, demand is high.
Thus, p ∞ \(\frac { 1 }{ Q }\) – where,
P = Price of commodity
Q =Quantity demanded

Assumptions of the law of demand-Law of demand is based on few assumptions. These assumptions are-

  1. Consumer’s income should remain contant.
  2. Consumer’s taste, nature, etc. should remain constant.
  3. Consumer remains unknown with new substitutes.
  4. There is no possibility of price change in future.

Bihar Board 12th Economics Model Question Paper 2 in English Medium

Question 32.
What do you understand by National Income ? Explain any two methods of calculating National Income.
Answer:
Net National product at factor cost (NNPFC) is known as ‘National Income’ NNPFC is the sum total of net domestic product at factor cost and net factor income from abroad.

Net National product at factor cost (NNPFC) or national income is the sum total of factor incomes (rent + interest + profit + wages) generated within the domestic territary of a country, alongwith net factor income from abroad during a year.
NNPFC is the sum total of factor incomes earned by normal residents of a country during year.

(a) First step-identification and classification of productive enterprise.
At the very first step, we are to identify and classify various productive enterprises of an economy. Broadly speaking, we can classify the economy into the following three sectors-

  • Primary sector
  • Secondary sector
  • Tertiary sector

(b) Second step-Calculation of net value of output to estimate the net value added in each identified enterprise in first step the following estimated are calculated

  • Value of output
  • value of intermediate consumption
  • consumption of fixed capital,

i.e., Depreciation.
Value of output is worked out by multiplying the amount of goods and services by each enterprises with their market price. Value of intermediate consumption is calculated by using the prices paid by the enterprise. Consumption of fixed capital is also estimated as per rules and regulations.
[Net value added = Value of output – Intermediate consumption – Net indirect taxes]

(c) Third step-Calculation of net factor income from abroad.
The third and final step in the estimation of national incomes is to estimate the net factor income earned from abroad and add it to the net domestic product at factor cost. This gives us the national income.

Bihar Board 12th Economics Model Question Paper 2 in English Medium 10

Bihar Board 12th Economics Model Question Paper 2 in English Medium

Question 33.
What is Barter system ? Mention its difficulties.
Answer:
The direct exchange of goods for goods without the use of money is called barter system. The major drawbacks of the barter system are-

  1. Lack of double coincidence of wants-The lack of double coincidence of wants is the major drawback of the barter system. It is very rare when the owner of some goods or services could find someone who wanted his goods or services and possessed that goods or services that the first person wanted. No, exchange is possible if the double coincidence of wants is not there.
  2. Lack of common measure of value-The second main drawback of barter system is the absence of a common unit of measurement in which the value of goods and services can be measured. In the absence of common unit, proper accounting is not possible.
  3. Lack of standard for deferred payments- The third drawback of the barter system is that it lacks any satisfactory unit to engage in contracts involving future payments. In a barter economy, future payments would have to be stated in specific goods or services which may involve disagreement over the quality of goods even on the commodity used for repayment.
  4. Lack of store of value-The bater system does not provide for any method of storing purchasing power for future use. It can be stored only in terms of commodities which subject to storage cost, durability, increases or decreases in the value of goods and the difficulty in disposing of the commodity without loss

Bihar Board 12th Chemistry Model Question Paper 3 in English Medium

Bihar Board 12th Chemistry Model Papers

Bihar Board 12th Chemistry Model Question Paper 3 in English Medium

Time : 3 Hours 15 Min
Full Marks: 70

Instructions for the candidates

  1. Candidates are required to give answers in their own words as far as practicable.
  2. Figures in the right hand margin indicates full marks.
  3. While answering the questions, candidate should adhere to the words limit as far as practicable.
  4. 15 Minutes of extra time has been allotted for the candidates to read the questions carefully.
  5. This question paper is divided into two sections : Section -A and Section-B
  6. In Section A, there are 35 objective type questions which are compulsory, each carrying 1 mark. Darken the circle with blue/black ball pen against the correct option on OMR Sheet provided to you. Do not use Whitener/Liquid/Blade/ Nail on OMR Sheet otherwise your result will be treated as invalid.
  7. In section-B, there are 18 short answer type questions (each carrying 2 marks), out of which only 10 (ten) questions are to be answered Apart from this there are 06 Long Answer type questions (each carrying 5 marks), out of which 3 questions are to be answered.
  8. Use of any electronic device is prohibited.

Objective Type Questions

In the following questions no. from 1 to 35, there is only one correct answer against each question. For each question, mark (darken) the correct answer on the OMR Sheet provided to you. (1 x 35 = 35)

Question 1.
Solid X is a very hard solid which is electrical insulator in solid as well as in molten state and has extremely high melting point. What type of solid is it ?
(a) Ionic solid
(b) Covalent solid
(c) Metallic solid
(d) Molecular solid
Answer:
(b) Covalent solid

Question 2.
Examples of few solids are given below. Find out the example which is not correctly matched.
(a) Ionic solids – NaCl, ZnS
(b) Covalent solids – H2,I2
(c) Molecular solids – H2O(s)
(d) Metallic solids – Cu, Sn
Answer:
(b) Covalent solids – H2,I2

Question 3.
Which of the following solids is the structure of CsCI crystal ?
(a) Body centred cubic
(b) Simple cubic
(c) Face centred cubic
(d) Edge centred cubic
Answer:
(a) Body centred cubic

Bihar Board 12th Chemistry Model Question Paper 3 in English Medium

Question 4.
Which of the following does not represent a type of crystal system ?
(a) Triclihic
(b) Monoclinic
(c) Rhombohedral
(d) Isotropical
Answer:
(d) Isotropical

Question 5.
Which of the following primitive cells show the given parameters ?
a ≠ b ≠ c, α = β = γ = 90°
(a) Cubic
(b) Tetragonal
(c) Orthorhombic
(d) Hexagonal
Answer:
(c) Orthorhombic

Question 6.
In amalgam of mercury with sodium, solvent is
(a) mercury
(b) sodium
(c) amalgam
(d) none of these
Answer:
(b) sodium

Question 7.
What is the mole fraction of glucose in 10% w/W glucose . solution ?
(a) 01
(b) 0.02
(c) 03
(d) 0.04
Answer:
(a) 01

Bihar Board 12th Chemistry Model Question Paper 3 in English Medium

Question 8.
The cell reaction of the galvanic cell:
Bihar Board 12th Chemistry Model Question Paper 3 in English Medium 1
(a) Hg + Cu2+→ Hg2+ + Cu
(b) Hg + Cu2+→ Cu+ + Hg+
(c) Cu + Hg → CuHg
(d) Cu + Hg2+ → Cu2+ + Hg
Answer:
(d) Cu + Hg2+ → Cu2+ + Hg

Question 9.
Which of the following reaction is possible at anode ?
(a) 2Cr3+ +7H2O → Cr2O22-+14H+
(b) F2 → 2F
(c) (1/2)O2 +2H+→H2O
(d) None of these.
Answer:
(a) 2Cr3+ +7H2O → Cr2O22-+14H+

Question 10.
Consider the reaction :
Bihar Board 12th Chemistry Model Question Paper 3 in English Medium 2
\(-\frac{\mathrm{d}\left[\mathrm{N}_{2} \mathrm{O}_{4}\right]}{\mathrm{dt}}=\mathrm{k} \text { and } \frac{\mathrm{d}\left[\mathrm{NO}_{2}\right]}{\mathrm{dt}}=k^{\prime} \)
(a) 2 k’ = k
(b)k’ = 2k
(c)k’=k
(d) K = 1/4 k’
Answer:
(b)k’ = 2k

Bihar Board 12th Chemistry Model Question Paper 3 in English Medium

Question 11.
For the reaction 2NH3 → N2+3H2, if
\(-\frac{\mathrm{d}\left[\mathrm{NH}_{3}\right]}{\mathrm{dt}}=\mathrm{k}_{1}\left[\mathrm{NH}_{3}\right], \frac{\mathrm{d}\left[\mathrm{N}_{2}\right]}{\mathrm{dt}}\) then the relation between k1, k2 and k3 is
(a) k1=k2 = k3
(b) k1=3k2-2k2
(c) 1.5= 3k2 = k3
(d) 2kx =k2= 3k3
Answer:
(c) 1.5= 3k2 = k3

Question 12.
The term activation of adsorbent is used when
(a) adsorbing power is increased by increasing surface area by making the surface rough
(b) adsorbing power is increased by dipping the surface in acid to make it smooth
(c) adsorbing power is increased by dissolving it in water
(d) adsorbing power is decreased to reduce the extent of adsorption
Answer:
(a) adsorbing power is increased by increasing surface area by making the surface rough

Question 13.
Which of the following is less than zero during adsorption ?
(a) ΔG
(b) ΔS
(c) ΔH
(d) All of these
Answer:
(d) All of these

Question 14.
In which of the following the name of the ore is not matched with its formula ?
(a) Cassiterite – SnO2
(b) Limonite – Fe2O3.3H2O
(c) Siderite – FeCO3
(d) Anglesite – PbCO3
Answer:
(d) Anglesite – PbCO3

Question 15.
Pyrolusite is ………………
(a) a sulphide ore of Mn
(b) an oxide ore of Mn
(c) a carbide ore of P
(d) a chloride ore of Zn
Answer:
(b) an oxide ore of Mn

Question 16.
Nitrogen forms stable N2 molecule but phosphorus is converted to.P4 from P2 because
(a) pπ – pπ bonding is strong in phosphorus
(b) pπ – pπ bonding is weak in phosphorus
(c) triple bond is present in phosphorus
(d) single P – P bond is weaker than N – N bond
Answer:
(b) pπ – pπ bonding is weak in phosphorus

Bihar Board 12th Chemistry Model Question Paper 3 in English Medium

Question 17.
The decreasing order of boiling points of the following hydrides is
(a) H2O > SbH3 > AsH3 > PH3 > NH3
(b) H2O > NH3 > SbH3 > AsH3 > PH3
(c) H2O>SbH3>NH3>AsH3>PH3
(d) H2O > PH3 > AsH3 > SbH3 > NH3
Answer:
(c) H2O>SbH3>NH3>AsH3>PH3

Question 18.
Which of the following pairs of ions have the same electronic configuration ?
(a) Cu2+,Cr2+
(b) Fe3+,Mn2+
(c) CO3++Ni3+
(d) SC3+ + cr 3+
Answer:
(b) Fe3+,Mn2+

Question 19.
The melting points of Cu, Ag and Au follow the order
(a) Cu > Ag > Au
(b) Cu > Au > Ag
(c) Au > Ag > Cu
(d) Ag > Au > Cu
Answer:
(b) Cu > Au > Ag

Question 20.
When one mole of each of the following complexes is treated with excess of AgN03, which will give maximum amount of AgCl ?
(a) [Co(NH3)6]Cl3
(b) [Co(NH3)5Cl]Cl2
(c) [Co(NH3)4Cl2]Cl
(d) [Co(NH3)3Cl3]
Answer:
(a) [Co(NH3)6]Cl3

Question 21.
According to Werner’s theory of coordination compounds.
(a) primary valency is ionisable
(b) secondary valency is ionisable
(c) primary and secondary valencies are ionisable
(d) neither primary nor secondary valency is ionisable
Answer:
(a) primary valency is ionisable

Question 22.
Haloalkanes contain halogen atom(s) attached to the sp3 hybridised carbon atom of an alkyl group. Identify haloalkane from the following compounds.
(i) 2-Bromopentane
(ii) Vinyl chloride
(iii) 2-Chloroacetophenone
(iv) Trichloromethane
(a) Only (ii)
(b) (ii) and (iv) only
(c) (i) and (iv) only
(d) (i), (ii) and (iii) only
Answer:
(c) (i) and (iv) only

Bihar Board 12th Chemistry Model Question Paper 3 in English Medium

Question 23.
The IUPAC name of tertiary butyl chloride is ……………..
(a) 2-chloro-2-methypropane
(b) 3-chlorobutane
(c) 4-chlorobutane
(d) 1, 2-chloro-3-methylporpane .
Answer:
(a) 2-chloro-2-methypropane

Question 24.
A compound …………. has two tertiary alcoholic groups. The IUPAC name of this compound is
(a) 2, 3-dimethyl-1, 2-butanediol
(b) 3, 3-dimethyl-1, 2-butanediol
(c) 2, 3-dimethyl-2, 3-butanediol
(d) 2-methyI-2, 3-pentanediol
Answer:
(c) 2, 3-dimethyl-2, 3-butanediol

Question 25.
Which of the following is phenol ?
(a) Cresol
(b) Catechol
(c) Benzenol
(d) All of these
Answer:
(d) All of these

Question 26.
Ketones
Bihar Board 12th Chemistry Model Question Paper 3 in English Medium 3
can be obtained in one step by (where R and R’ are alkyl groups)
(a) hydrolysis of esters
(b) oxidation of primary alcohols
(c) oxidation of secondary alcohols
(d) reaction of alkyl halides with alcohols
Answer:
(c) oxidation of secondary alcohols

Question 27.
Ozonojysis of an organic compound gives formaldehyde as one of the products. This confirms the presence of
(a) two ethylenic double bonds
(b) a vinyl group
(c) an isopropyl group
(d) an acetylenic triple bond
Answer:
(b) a vinyl group

Bihar Board 12th Chemistry Model Question Paper 3 in English Medium

Question 28.
Which of the following is not a primary amine ?
(a) tert-Butylamine
(b) sec-Butylamine
(c) Isobutylamine
(d) Dimethylamine
Answer:
(d) Dimethylamine

Question 29.
Which one of the following is aromatic amine ?
Bihar Board 12th Chemistry Model Question Paper 3 in English Medium 4
(d) Both (a) and (b)
Answer:
(d) Both (a) and (b)

Question 30.
Cellulose is a
(a) hexapolysaccharide
(b) pentapolysaccharide
(c) tripolysaccharide
(d) none of these
Answer:
(d) none of these

Question 31.
Which of the following is a non-reducing sugar ?
(a) Glucose
(b) Sucrose
(c) Maltose
(d) Lactose
Answer:
(b) Sucrose

Question 32.
Which of the following sets contain only addition homopolymers ?
(a) Polythene natual rubber, cellulose
(b) Nylon polyester, melamine resin
(c) Teflon, bakelite, orlon
(d) Neoprene, PVC, polythene
Answer:
(d) Neoprene, PVC, polythene

Question 33.
Teflon and neoprene are the examples of
(a) copolymers
(b) monomers
(c) homopolymers
(d) condensation polymers
Answer:
(c) homopolymers

Question 34.
Some drugs do not bind to the enzyme’s active site, instead bind to a different site of enzyme. This site is called
(a) allosteric site
(b) substrate site
(c) ionic site
(d) competitive site.
Answer:
(a) allosteric site

Bihar Board 12th Chemistry Model Question Paper 3 in English Medium

Question 35.
Drugs that bind to the receptor site and inhibit its natural function are called
(a) agonistic drugs
(b) antagonistic drugs
(c) antimicrobial drugs
(d) allosteric drugs.
Answer:
(b) antagonistic drugs

Non-Objective Type Questions

Short Answer Type Questions

In this Section, there are 18 Short answer type questions (each carrying 2 marks), out of which answer any 10 questions.  2 x 10 = 20

Question 1.
What happens when
(a) ethanol is oxidised with acidified KMnO4 solution ?
(b) ethanol is treated with PCl5 ?
Answer:
(a) Ethanoic acid will be formed
Bihar Board 12th Chemistry Model Question Paper 3 in English Medium 5

(b) Chloroethane will be formed
C2H5OH + PCl5 → C2H5Cl + POCl3 + HCl

Question 2.
How will you convert
(a) aniline to 2, 4, 6 tribromoaniline ?
(b) acetamide to ethylamine ?
Answer:
Bihar Board 12th Chemistry Model Question Paper 3 in English Medium 6

Question 3.
(a) What is inert pair effect ?
(b) Why does BCI3 act as Lewis acid ?
Answer:
Inert pair effect – The pairs of two electrons doesn’t participated in a chemical reaction of heavy outside & subnucleic non metal. This effect is called inert pair effect. BCl3 behaves as Lewis acid due to the electron deficient in BCl3

Question 4.
Explain the following :
(a) H2S is a gas while H2G is a liquid at room temperature.
(b) Carbon and silicon are tetravalent but Ge, Sn and Pb show divalency also.
Answer:
(a) Since H – 0 bond is more polar than H – S because of greater electronegativity difference in the bond participating atoms. Due to this, H2O molecules are involved in the bending associates to be liquid at room temperature.

Where as, the intermolecular hydrogen bonding is negligible in the molecules of H2S and does not associates, and it maintains the gaseous state at room temperature.

(b) Due to small shape of atoms of carbon and silicon and due to the maximum value of electron negativity. The carbon and silicon are tetravalent but the Sn, Pb shows divalency.

Bihar Board 12th Chemistry Model Question Paper 3 in English Medium

Question 5.
Write the IUPAC names of the following coordinate compounds :
(a) [Pt (NH3)2 Cl2] Cl2
(b) [Cr (NH3)4 Cl2]+
Answer:
(a) [Pt (NH3)2Cl2[Cl2 → Diammine dicholorplatinum (iv) chloride.
(b) [Cr {NH3)4Cl2]+ → Tetra aminedichloro chromium (iii) ion.

Question 6.
(a) Why are Cd2+ salts white ?
(b) Why does H3PO3 act as reducing agent but H3PO4 does not ?
Answer:
(a) Due to absence of unpaired electron CD2+ molecule is found CD2+ salt in white.
(b) The oxidation no. of P in H3PO3 in +3 so its oxidation no. can be increased, or we can say that H3PO3 acts as reducing agent while the oxidation no. of P is +5 in H3 PO4 . Therefore, we can say that H3PO3 acts as reducing agent but H3PO4 does not act as reducing agent.

Question 7.
Write IUPAC names of the following :
(a) [Cu (NH3)4]Cl2
(b) K4 [Fe (CN)6 ]
Answer:
(a) Hexa-amino Copper (II) Chloride
(b) Potassium hexacyano Ferrate (II)

Question 8.
How will you convert the following ?
(a) Ethyl alcohol to Ethylene
(b) Acetylene to Benzene.
Answer:
Bihar Board 12th Chemistry Model Question Paper 3 in English Medium 7
Question 9.
How will you account for the following ? The electron affinity of fluorine is less than that of chlorine.
Answer:
The electron affinity of fluorine is less than that of chlorine because atom of chlorine is much smaller, hence electron density is very high, so an external electron can be added easily.

Question 10.
Give reasons for the following :
(a) Formic acid is stronger that Acetic acid.
(b) Aniline is less basic than methylamine.
Answer:
(a) Acidity of acid depends upon donation of proton
Since \(K a=\frac{\left[R C O O^{-}\right]\left[H_{3} O^{+}\right]}{[R C O O H]}\)
As we know, if the value of Ka is max, The Acidity will be maximum
HCOOH (Formic acid) ⇒ Ka= 1.77 x 10 5
CH3COOH+ (acidic acid) ⇒ Ka = 1.75 x 105
Hence formic acid is more acidic than acetic acid.

Bihar Board 12th Chemistry Model Question Paper 3 in English Medium

(b) One pair of electron of nitrogen atom in aniline, which is overlaped with re-electron in ring. So, nitrogen atoms is positive charged or their is lack of electrons and it isn’t in the state than it can give paired electron to acid in comparison with methyl amine, due to this reason there is no overlapping so, aniline is a weak base than methyl amine.

Question 11.
Define the following : (a) Roasting (b) Smelting.
Answer:
Roasting – Roasting is the process by heating an ore in oxygen below its melting point to avoid volatile impurities.
Example –
CuS + 3O2 → 2Cm2 O+2SO2
S + O→ SO2
Smelting – Smelting is process in which metal oxide is obtained by heating with some reducing agent such metals are Zn, Fe, Sn, Cu.

Question 12.
Give two methods for the preparation of colloids.
Answer:
There are two methods of the preparation of colloids

  • Condensation method
  • Disperson method

Question 13.
State coiligative properties of dilute solution. Write down the different types of coiligative properties.
Answer:
The property, which depends upon number of atom or molecule of the solute and hot on their nature is called coiligative properties. There are four type of coiligative properties.

  • Relative lowering of vapour pressure.
  • Elevation in boiling point.
  • Deperession in freezing point.
  • Osmosis or Osmotic pressure.

Question 14.
The rate constant of a first order reaction is 60 sec-1. How much time will it take to reduce 75% of its initial concentration ?
Answer:
Let initial concentration = amz 1; According to Question 75% reduce
Let after t second, concentration remains \(\frac{a}{4}\)
As we know \(t=\frac{2.303}{t} \log \frac{a}{a-x}\)
\(t=\frac{2.303}{60} \log 4\)log 4 = 0.023 second
t = 0.023 seconds

Bihar Board 12th Chemistry Model Question Paper 3 in English Medium

Question 15.
Prove that the half-life of a first order reaction is independent of the initial concentration.
Answer:
Bihar Board 12th Chemistry Model Question Paper 3 in English Medium 8
Bihar Board 12th Chemistry Model Question Paper 3 in English Medium 9
From above, it is clear that the half-life of a first order reaction is independent of the initial concentration.

Question 16.
What do you mean by vapour pressure ? What happens to the vapour pressure. When (i) volatile solute is dissolved in solution, (ii) non-volatile solute is dissolved in solution ?
Answer:
Vapour pressure : It is defined as the pressure exerted by a vapour in thermodynamic equilibrium with its condensed phased (solid or liquid) at a given temperature in a closed sytem.

  • Volatile solute increases vapour pressure of solvent.
  • Nonvolatile solute lowers vapour pressure of solvent.

Question 17.
Differentiate between thermoplastic and thermosetting polymers. Give one example of each.
Answer:
Thermoplastic : Thermoplastic is a polymer that becomes pladable or moledable above a specific temperature and returns to a state upon cooling. Most thermoplastic have a high molecular weight.
Example : Polyethelene.

Thermosetting : A thermosetting is also known as thermoset is petrochemical material that irreversibly chures. The cure may be induced by heat through chemical reaction. A cured thermosetting resin is called a thermoset.
Example: Polyester.

Question 18.
How many moles of Cu will be deposited by passing 24125 coulombs of electric current from CuSQ4 solution ?
Answer:
Cu++ + 2e → Cu
2 x 96500 = 1 mole
Change 2 x 96500 columb Cu heated on = 1 mole 24125 columb change Cu on
1 Mole x \(\frac{24125}{2 \times 96500}\) = 0.125 mole

Long Answer Type Questions

There are 06 long answer type questions (each carrying 05 marks), out of which answer any there questions.
(5×3 = 15)

Question 19.
(a) What is the difference between Ferromagnetism and paramagnetism ?
(b) For the cell shown below Zn (s) | ZnSO4 (aq) || CuSO4 (aq) | Cu (s) Calculate standard cell potential if standard state reduction electrode potentials for Cu2+ |Cu and Zn2+| Zn are + 0.34 V and – 0.76 V respectively.
Answer:
(a) Paramagnetism :

  • The substances which are weakly attracted by magnetic field are called paramagnetic substances.
  • These substances have permanent magnetic dipoles due to the presence of atom or ions with
    unpaired electrons.
  • These substances lose their magnetism in the absence of magnetic field, e.g., TiO, CuO.

Ferromagnetism :

  • The substances which are strongly attracted by magnetic field are called ferromagnetic substance.
  • These substances show permanent magnetic even in the absence of magnetic field.
  • e.g., Iron, Cobalt, Nickel & CrO2
    Zn (s) \ZnSOI4(a2)\\CuSO4(aq)\Cu (s)
    So, the cell reaction

At Anode : Oxidation
Bihar Board 12th Chemistry Model Question Paper 3 in English Medium 10

Bihar Board 12th Chemistry Model Question Paper 3 in English Medium

Question 20.
(a) What do you mean by the term elevation in boiling point’ ?
(b) State Raoult’s law. How is it applicable in determining the molecular weight of non-electrolyte solute ?
Answer:
(a) Elevation in boiling – The boiling point of a liquid may be defined as the temperature at which its vapour pressure becomes equal to atmospheric pressure. When we add a solute in any pure solvent, then the boiling point of the solution gets increased. This increasement is known as the elevation in boiling point.

(b) Raoult’s law – According to this law, the vapour pressure of a solution containing non-volatile solute is directly proportional to the mole fraction of the solvent.
Bihar Board 12th Chemistry Model Question Paper 3 in English Medium 11

Fig. Vapour pressure curve explaining elevation of boiling point. If a solution contains two components A (volatile solvent) and B (non-volatile solute) the vapour pressure of solution is given as
[Vapour Pressure of solution ] = [Vapour Pressure of solvent insolution (PA)] α [ Mole fraction of solvent (Xa)]

PA α XA where, K is a proportionality constant
PA = KXa
Roult’s law is applicable in determing the molecular weight of non-electrolyte solute because unsaturated solute in solvent is pure solute than its boiling point is elevated. Hence, by this law we determine the molecular weight of non-electrolyte solute.

Question 21.
(a) Give the principle for the manufacture of nitric acid from ammonia.
(b) Give the reaction of 50% dilute HNO3 with copper metal.
Answer:
(a) Due to following 11 parts of NH3 and 89 part of mixture of air Pt gaize and heated at 100°, then we get (NO).
4NH3+ 5O2 → 4 NO + 6H2O
2NO + O2 → 2NO2
2N02 + H2O → HNO3 + HNO2
HNO2 → HNO3 +2NO+ H2O
Thus, from above equations it is clear that NO. gives NO2 due to its oxidation which mix in water and forms HNO3 .

(b) 3Cw + dil. SHNO3 → 3Cu(NO3)2 +4H2O + 2NO

Question 22.
What happens when
(a) Ammonia reacts with excess of chlorine ?
(b) H2S reacts with acidified K2Cr2O7 solution ?
(c) Copper sulphate reacts with KI Solution ?
Answer:
(a) Ammonia reacts with excess of Chlorine
2NH3 + 6Cl2 → 2NCl3 + 6HCl

(b) When H2S reacts with acidified K2Cr2O7 solution then a milky white or pale yellow colour of solution appears, due to the oxidations of H2S to sulphur which are of colloidal nature.
H2S + K2Cr2O7 → K2SO4 + Cr2O3 + H2O

(c) When copper sulphate (CuSO4) reacts with KI solution, then a white precipitate of cuprous iodide is formed.
[CuSO4 +2KI → Cul2 + K2SO4] x 2
2CuI2 → CuI2 + I2
2CuSO4 + 4KI → 2K2SO4 + Cu2I2 + I2

Question 23.
(a) Describe the following chemicals with suitable examples :
(i) Antipyretics
(ii) Antiseptics.
(b) Name the vitamin whose deficiency is responsible for night blindness.
(c) What are the starting materials used for preparing bakelite and PVC ?
Answer:
(a) (i) Antipyretics – Those chemicals which are used to lower down the body temperatures during high fever are known as antipyretics, e.g., Paracetamol, aspirin, etc.

Antiseptic – Those chemicals which are able to kill the micro-organisms, which are harmful to us are known as antiseptic. e.g., dettol or tincture of iodine can be applied an wounds, cuts, etc. They are also applied to reduce odours resulting from bacteria de-composition on the body.

(b) Vitamin A or A, is the vitamin whose deficiency is responsible for night blindness.

(c) Bakelite – Phenol and formaldehyde PVC – Methyl chloride

Bihar Board 12th Chemistry Model Question Paper 3 in English Medium

Question 24.
(a) Define the following with one example in each case : (i) Analgesics (ii) Antibiotics.
(b) How many molecules of ATP are produced per molecule of glucose in glycolysis ?
(c) What are synthetic rubbers ? Give one example.
Answer:
(a)

  • Analgesics – Those chemicals, which are used for the relief of pain are known as analgesics.
    e.g., Moov, Fast relief are some malgesic creams which are helpful in pain.
  • Antibiotics – Those chemicals which are obtained from micro-organisms (bacteria, Fungi and mos) that destroy O2 inhibit the growth of other micro-organisms. e.g., Penicillin, streptomycin, tetracy lin, etc.

(b) 8 molecules of ATP are produced per molecule of glucose in glycolysis.
(c) Synthetic rubbers – Those rubbers which are manufactured artificially in laboratories are called synthetic rubbers. e.g., Neuprene.